/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Radium is a radioactive element ... [FREE SOLUTION] | 91Ó°ÊÓ

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Radium is a radioactive element whose nucleus emits an \(\alpha\) particle (a helium nucleus) with a kinetic energy of about \(7.8 \times 10^{-13} \mathrm{J}(4.9 \mathrm{MeV})\) To what amount of mass is this energy equivalent?

Short Answer

Expert verified
The mass equivalent is approximately \(8.67 \times 10^{-30} \mathrm{kg}\).

Step by step solution

01

Understanding the Problem

We need to find the mass equivalent of a given energy, specifically the kinetic energy of an \(\alpha\) particle which is \(7.8 \times 10^{-13} \mathrm{J}\). This requires the application of the mass-energy equivalence principle.
02

Recall Einstein's Mass-Energy Equivalence Formula

The mass-energy equivalence principle is described by the famous equation \(E=mc^2\), where \(E\) is energy, \(m\) is mass, and \(c\) is the speed of light in a vacuum (approximately \(3\times 10^8\, \mathrm{m/s}\)). We will use this equation to solve for \(m\).
03

Solve for Mass

Rearrange the equation \(E=mc^2\) to find \(m\): \[ m = \frac{E}{c^2} \]. Substitute \(E = 7.8 \times 10^{-13} \mathrm{J}\) and \(c = 3 \times 10^8 \mathrm{m/s}\) into the equation: \[ m = \frac{7.8 \times 10^{-13}}{(3 \times 10^8)^2} \].
04

Calculate the Result

Calculate \(m\): \[ m = \frac{7.8 \times 10^{-13}}{9 \times 10^{16}} \]. Simplify to find \(m\): \[ m = 8.67 \times 10^{-30} \mathrm{kg} \].
05

Interpret the Result

The mass equivalent of the \(7.8 \times 10^{-13} \mathrm{J}\) energy is approximately \(8.67 \times 10^{-30} \mathrm{kg}\). This small mass reflects the high energy involved in nuclear processes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alpha Particle
Alpha particles are one of the most fascinating types of subatomic particles. They are essentially helium nuclei, comprised of two protons and two neutrons. This makes them relatively heavier and positively charged compared to other radiation particles.
These particles are emitted during some types of radioactive decay, specifically alpha decay, and play a crucial role in nuclear physics. When an alpha particle is emitted from the nucleus of a radioactive element, such as radium, it carries energy away from the nucleus. This process changes the original atom into a different element with an atomic mass reduced by four units, reflecting the loss of the alpha particle.
Alpha particles have high kinetic energy, typically measured in millions of electron volts (MeV), making them capable of ionizing other atoms and particles they encounter. However, despite their high energy, their range is relatively short because they quickly lose energy through interactions with matter.
Radioactive Decay
Radioactive decay is a natural and spontaneous process where unstable atomic nuclei lose energy by emitting radiation. It occurs as atoms transition to a more stable state.
There are several types of radioactive decay, including alpha decay, beta decay, and gamma decay. In alpha decay, an unstable nucleus releases an alpha particle, decreasing its atomic number by two and its mass number by four. This process can transform the original element into a completely different element.
Radioactive decay is a random process at the single-atom level, but predictable in large quantities, which is why we can measure half-lives— the time it takes for half of a sample of radioactive atoms to decay. Understanding these processes is crucial in fields like nuclear physics, medicine, and energy production.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. The faster an object moves, the more kinetic energy it has. This concept is crucial in understanding particles in motion, such as alpha particles emitted during radioactive decay.
The kinetic energy of a particle is determined by its mass and velocity, expressed with the equation: \[ KE = \frac{1}{2}mv^2 \] In the case of an alpha particle being emitted, it has a given amount of kinetic energy, often described in electron volts (eV) or its multiples like mega-electron volts (MeV). In our context, the alpha particle has kinetic energy equivalent to \(7.8 \times 10^{-13}\, \text{Joules} \) or approximately \(4.9\, \text{MeV} \).
Recognizing and calculating kinetic energy helps us understand the potential impacts the particle can have when interacting with its environment, contributing to concepts like nuclear transmutation in radioactive decay.
Einstein's Equation
Einstein's mass-energy equivalence equation, \(E = mc^2\), is one of the most celebrated and fundamental relationships in physics. It indicates that mass can be converted into energy and vice versa. In this equation, \(E\) stands for energy, \(m\) for mass, and \(c\) for the speed of light in a vacuum (approximately \(3 \times 10^8\, \text{m/s}\)).
This equation revolutionized our understanding of energy and mass, emphasizing that even a small amount of mass can correspond to a significant amount of energy, as seen in nuclear reactions.
In the context of radioactive decay, when an alpha particle is emitted, its kinetic energy—\(7.8 \times 10^{-13} \text{J}\)—can be converted back into mass using Einstein's equation. Solving \(E = mc^2\) with the given kinetic energy, we find the mass equivalent to this energy is approximately \(8.67 \times 10^{-30}\, \text{kg}\). This demonstrates the profound link between mass and energy, illustrating why nuclear processes release massive amounts of energy.

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Most popular questions from this chapter

What is the magnitude of the relativistic momentum of a proton with a relativistic total energy of \(2.7 \times 10^{-10} \mathrm{J} ?\)

ssm A particle known as a pion lives for a short time before breaking apart into other particles. Suppose that a pion is moving at a speed of \(0.990 c\), and an observer who is stationary in a laboratory measures the pion's lifetime to be \(3.5 \times 10^{-8}\) s. (a) What is the lifetime according to a hypothetical person who is riding along with the pion? (b) According to this hypothetical person, how far does the laboratory move before the pion breaks apart?

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