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A flat circular coil with 105 turns, a radius of \(4.00 \times 10^{-2} \mathrm{m},\) and a resistance of \(0.480 \Omega\) is exposed to an external magnetic field that is directed perpendicular to the plane of the coil. The magnitude of the external magnetic field is changing at a rate of \(\Delta B / \Delta t=0.783 \mathrm{T} / \mathrm{s},\) thereby inducing a current in the coil. Find the magnitude of the magnetic field at the center of the coil that is produced by the induced current.

Short Answer

Expert verified
The magnetic field produced by the induced current at the center of the coil is approximately \( 2.25 \times 10^{-2} \, \text{T} \).

Step by step solution

01

Understand the Problem

We are given a circular coil with certain parameters and an external magnetic field changing over time. This changing field induces an electromotive force (EMF) and current in the coil. Our task is to find the magnetic field produced by this induced current at the center of the coil.
02

Identify the Relevant Formula for EMF

First, we need to find the induced EMF in the coil. The formula to use is Faraday's Law of Induction: \( \text{EMF} = -N \frac{\Delta B}{\Delta t} \), where \( N \) is the number of turns in the coil, and \( \frac{\Delta B}{\Delta t} \) is the rate of change of the magnetic field.
03

Calculate the Induced EMF

Using the formula from Step 2, substitute the given values: \( N = 105 \) and \( \frac{\Delta B}{\Delta t} = 0.783 \, \text{T/s} \).\[ \text{EMF} = -105 \times 0.783 = -82.215 \, \text{V} \].The negative sign indicates the direction of EMF as per Lenz's Law, but the magnitude is \( 82.215 \, \text{V} \).
04

Find the Induced Current

Ohm's Law relates the induced EMF to the current through the resistance: \( I = \frac{\text{EMF}}{R} \), where \( R = 0.480 \, \Omega \).\[ I = \frac{82.215}{0.480} = 171.281 \, \text{A} \].
05

Determine the Formula for the Magnetic Field Produced by Current

The magnetic field at the center of a single circular loop due to a current is given by \( B = \frac{\mu_0 I}{2R} \), where \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m/A} \), and \( R \) is the radius of the loop. Since our coil has multiple turns, the formula becomes \( B = \frac{\mu_0 N I}{2R} \).
06

Calculate the Magnetic Field

Substitute the known values: \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m/A} \), \( N = 105 \), \( I = 171.281 \, \text{A} \), and \( R = 4.00 \times 10^{-2} \, \text{m} \).\[ B = \frac{(4\pi \times 10^{-7}) \times 105 \times 171.281}{2 \times 4.00 \times 10^{-2}} \].Simplify to find \( B \approx 2.25 \times 10^{-2} \, \text{T} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced Electromotive Force
The concept of induced electromotive force (EMF) is central to understanding electromagnetic induction. According to Faraday's Law of Induction, an EMF is induced in a coil when the magnetic field around it changes over time. The formula representing this principle is \( \text{EMF} = -N \frac{\Delta B}{\Delta t} \), where \( N \) is the number of turns in the coil, and \( \frac{\Delta B}{\Delta t} \) stands for the rate of change of the magnetic field.
This law suggests that a moving or changing magnetic field can produce an electric potential, or EMF, in the material of the coil.
The negative sign in the formula denotes Lenz's Law, which indicates that the induced EMF will always act to oppose the change in the magnetic field that created it.
  • Faraday's Law was a groundbreaking discovery, showing the relationship between changing magnetic fields and electricity generation.
  • It explains why electric generators work by turning mechanical energy into electrical energy.
  • The induced EMF can be used to power circuits, as seen in many electromechanical devices in our daily lives.
Ohm's Law
Ohm's Law is a fundamental principle in electric circuits and relates voltage (or EMF), current, and resistance. The formula \( I = \frac{\text{EMF}}{R} \) explains how the current \( I \) flowing through a conductor between two points is determined by the voltage \( \text{EMF} \) across it and the resistance \( R \) of the conductor.
This law serves as a cornerstone for understanding how electrical circuits function, especially in the context of induced currents.
  • It helps determine the current that flows due to the induced EMF, which is critical in applications like transformers and motors.
  • The law is applicable in DC and AC circuits, giving insights into circuit design and analysis.
  • Electrical resistance, measured in ohms, indicates how much a material resists the flow of electric current.
A firm grasp of Ohm's Law is essential for any beginner in electronics, as it helps solve for unknowns in circuit systems.
Magnetic Field Calculation
Calculating the magnetic field produced by a current-carrying coil involves understanding both the geometry of the coil and the current flowing through it.
For a circular loop, Biot-Savart Law gives us the equation \( B = \frac{\mu_0 I}{2R} \), where \( \mu_0 \) is the permeability of free space, \( I \) is the current, and \( R \) is the radius of the loop.
In the case of a coil with multiple turns, this is modified to accommodate the number of turns \( N \): \( B = \frac{\mu_0 N I}{2R} \). This formula shows that the magnetic field at the center of a coil is proportional to the current and the number of turns, and inversely proportional to the radius.
  • The magnetic field is stronger with more turns and a higher current.
  • Reducing the coil's radius increases the magnetic field strength, assuming the same current.
It is useful to note that this formula is primarily used for ideal conditions and that real-world factors can alter the precise magnetic field calculated.
Coil Inductance
Coil inductance is a property of a coil that defines its ability to oppose changes in current due to magnetic fields. Measured in henrys (H), inductance depends on factors such as the number of turns, the coil's radius, and the material inside the coil.
Inductance effects are significantly encountered in circuits where coils, or inductors, are used to store energy in the form of magnetic fields.
  • Inductance causes a delay in current changes, which can smooth out variations in electrical supply, thus stabilizing circuits.
  • The efficiency of transformers and electromagnets heavily relies on their inductance.
To design circuits with desired reactive properties, a clear understanding of inductance, along with how it interacts with capacitance and resistance, is crucial.
It enables creating filters, oscillators, and many forms of AC circuits that are foundational in communication technology.

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Most popular questions from this chapter

The coil of a generator has a radius of \(0.14 \mathrm{m} .\) When this coil is unwound, the wire from which it is made has a length of \(5.7 \mathrm{m}\). The magnetic field of the generator is \(0.20 \mathrm{T},\) and the coil rotates at an angular speed of \(25 \mathrm{rad} / \mathrm{s} .\) What is the peak emf of this generator?

Two coils of wire are placed close together. Initially, a current of 2.5 A exists in one of the coils, but there is no current in the other. The current is then switched off in a time of \(3.7 \times 10^{-2}\) s. During this time, the average emf induced in the other coil is \(1.7 \mathrm{V}\). What is the mutual inductance of the two-coil system?

A long, current-carrying solenoid with an air core has 1750 turns per meter of length and a radius of \(0.0180 \mathrm{m} .\) A coil of 125 turns is wrapped tightly around the outside of the solenoid, so it has virtually the same radius as the solenoid. What is the mutual inductance of this system?

You need to design a \(60.0-\mathrm{Hz}\) ac generator that has a maximum emf of \(5500 \mathrm{V}\). The generator is to contain a 150 -turn coil that has an area per turn of \(0.85 \mathrm{m}^{2} .\) What should be the magnitude of the magnetic field in which the coil rotates?

The magnetic flux that passes through one turn of a 12 -turn coil of wire changes to 4.0 from \(9.0 \mathrm{Wb}\) in a time of \(0.050 \mathrm{s}\). The average induced current in the coil is 230 A. What is the resistance of the wire?

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