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The magnetic flux that passes through one turn of a 12 -turn coil of wire changes to 4.0 from \(9.0 \mathrm{Wb}\) in a time of \(0.050 \mathrm{s}\). The average induced current in the coil is 230 A. What is the resistance of the wire?

Short Answer

Expert verified
The resistance of the wire is approximately 5.22 ohms.

Step by step solution

01

Understand the Problem Variables

We know that the magnetic flux changes from 9.0 Wb (initial flux, \( \Phi_i \)) to 4.0 Wb (final flux, \( \Phi_f \)) through a coil with 12 turns. The change occurs in 0.050 s and the induced current is 230 A. We need to find the resistance of the wire.
02

Calculate the Change in Magnetic Flux

The change in magnetic flux, \( \Delta\Phi \), is given by \( \Delta\Phi = \Phi_f - \Phi_i \). Substituting the given values, we get \( \Delta\Phi = 4.0 \text{ Wb} - 9.0 \text{ Wb} = -5.0 \text{ Wb} \).
03

Determine the Induced EMF Using Faraday's Law

According to Faraday's Law of Electromagnetic Induction, the induced electromotive force (EMF) in a coil is given by \( \varepsilon = -N \frac{\Delta\Phi}{\Delta t} \), where \( N \) is the number of turns (12 in this case) and \( \Delta t \) is the time interval (0.050 s). So, \( \varepsilon = -12 \frac{-5.0 \text{ Wb}}{0.050 \text{ s}} \).
04

Calculate the Induced EMF

Plug in the values to get \( \varepsilon = -12 \times \frac{-5.0}{0.050} = 1200 \text{ V} \). Since the negative signs cancel, the magnitude of the EMF is 1200 V.
05

Use Ohm's Law to Find the Resistance

Ohm's Law states that \( V = IR \), where \( V \) is the voltage (EMF in this case), \( I \) is the current, and \( R \) is the resistance. Rearranging for \( R \), we have \( R = \frac{V}{I} \). Substituting the values, \( R = \frac{1200}{230} \).
06

Calculate the Resistance

Perform the calculation: \( R = \frac{1200}{230} \approx 5.22 \text{ ohms} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a fundamental concept in electromagnetism, representing the quantity of magnetic field passing through a given area. It is denoted by the symbol \( \Phi \), and is calculated by the product of the magnetic field \( B \), the area \( A \), and the cosine of the angle \( \theta \) between them. Mathematically, it is expressed as: \[ \Phi = B \cdot A \cdot \cos(\theta) \]When the magnetic flux passing through a coil changes, it can induce an electromotive force (EMF) in the coil. This principle is the cornerstone of electromagnetic induction, explaining the transformation of magnetic energy into electrical energy.
The flux is measured in webers (Wb), indicating the strength of the magnetic field's influence over the area. A decrease or increase in magnetic flux over time leads to an induced voltage, which is explored further in Faraday's Law.
Faraday's Law
Faraday's Law of Electromagnetic Induction reveals how changing magnetic flux through a coil induces an electromotive force (EMF). The induced EMF is proportional to the rate at which the magnetic flux changes over time. The formula for Faraday's Law is:\[ \varepsilon = -N \frac{\Delta\Phi}{\Delta t} \]where \( \varepsilon \) is the induced EMF, \( N \) is the number of turns in the coil, \( \Delta\Phi \) is the change in magnetic flux, and \( \Delta t \) is the time interval of the change.
Faraday's Law highlights the importance of the rate of change; a rapid change in flux results in a larger EMF. The negative sign in the equation signifies Lenz's Law, indicating that the induced EMF creates a current that opposes the change in flux.
In this exercise, the change in magnetic flux is calculated, and by applying Faraday's Law, we determine the magnitude of the induced EMF to be 1200 V.
Ohm's Law
Ohm's Law is a fundamental principle in electrical circuits, expressing the relationship between voltage (V), current (I), and resistance (R). The formula is simple but powerful:\[ V = IR \]This equation tells us that voltage across a conductor is equal to the current flowing through it, multiplied by its resistance. In the context of our problem, the induced EMF acts as the voltage (V). By knowing the current (230 A, as given) and the induced voltage (1200 V), we can solve for the resistance of the wire.
Ohm's Law is crucial for understanding how electrical circuits function, allowing us to determine unknown parameters when two others are known. This aspect of the law is used to calculate the resistance in this scenario, which turns out to be approximately 5.22 ohms.
Induced EMF
Induced EMF is at the heart of electromagnetic induction, arising from a change in magnetic flux. The change can be in the magnitude of the magnetic field, the area of the loop, or the orientation of the field with respect to the loop. This induced EMF drives currents in conductors and is the principle underlying devices like transformers and generators.
As calculated using Faraday's Law, the magnitude of the induced EMF is considerable in this exercise, reaching 1200 V due to the swiftly changing magnetic flux in the 12-turn coil. This significant EMF subsequently causes a sizable current of 230 A to flow through the circuit.
  • This induced EMF demonstrates how we can convert energy from a changing magnetic field into electrical energy.
  • It's essential in many applications, including power generation and electromagnetic braking.
Understanding the concept of induced EMF helps grasp how energy transformations occur seamlessly in electromagnetic systems.

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Most popular questions from this chapter

The rechargeable batteries for a laptop computer need a much smaller voltage than what a wall socket provides. Therefore, a transformer is plugged into the wall socket and produces the necessary voltage for charging the batteries. The batteries are rated at \(9.0 \mathrm{V},\) and a current of \(225 \mathrm{mA}\) is used to charge them. The wall socket provides a voltage of \(120 \mathrm{V}\). (a) Determine the turns ratio of the transformer. (b) What is the current coming from the wall socket? (c) Find the average power delivered by the wall socket and the average power sent to the batteries.

A generator is connected across the primary coil \(\left(N_{p}\right.\) turns) of a transformer, while a resistance \(R_{2}\) is connected across the secondary coil \(\left(N_{\mathrm{s}}\right.\) turns). This circuit is equivalent to a circuit in which a single resistance \(R_{1}\) is connected directly across the generator, without the transformer. Show that \(R_{1}=\left(N_{p} / N_{\mathrm{s}}\right)^{2} R_{2},\) by starting with Ohm's law as applied to the secondary coil.

A constant current of \(I=15 \mathrm{A}\) exists in a solenoid whose inductance is \(L=3.1 \mathrm{H}\). The current is then reduced to zero in a certain amount of time. (a) If the current goes from 15 to \(0 \mathrm{A}\) in a time of \(75 \mathrm{ms},\) what is the emf induced in the solenoid? (b) How much electrical energy is stored in the solenoid? (c) At what rate must the electrical energy be removed from the solenoid when the current is reduced to \(0 \mathrm{A}\) in a time of \(75 \mathrm{ms}\) ? Note that the rate at which energy is removed is the power.

A generator uses a coil that has 100 turns and a \(0.50-\mathrm{T}\) magnetic field. The frequency of this generator is \(60.0 \mathrm{Hz},\) and its emf has an rms value of \(120 \mathrm{V}\). Assuming that each turn of the coil is a square (an approximation), determine the length of the wire from which the coil is made.

In a television set the power needed to operate the picture tube comes from the secondary of a transformer. The primary of the transformer is connected to a \(120-\mathrm{V}\) receptacle on a wall. The picture tube of the television set uses \(91 \mathrm{W}\), and there is \(5.5 \mathrm{mA}\) of current in the secondary coil of the transformer to which the tube is connected. Find the turns ratio \(N_{\Omega} / N_{\mathrm{p}}\) of the transformer.

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