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A circular coil (950 turns, radius \(=0.060 \mathrm{m}\) ) is rotating in a uniform magnetic field. At \(t=0\) s, the normal to the coil is perpendicular to the magnetic field. At \(t=0.010\) s, the normal makes an angle of \(\phi=45^{\circ}\) with the field because the coil has made one-eighth of a revolution. An average emf of magnitude \(0.065 \mathrm{V}\) is induced in the coil. Find the magnitude of the magnetic field at the location of the coil.

Short Answer

Expert verified
The magnitude of the magnetic field is approximately 0.052 T.

Step by step solution

01

Understanding the problem

We need to find the magnitude of the magnetic field, given a circular coil with 950 turns and a radius of 0.060 m. The coil is rotating, inducing an emf of 0.065 V, and makes an angle of 45° at t = 0.010 s after having rotated one-eighth of a revolution.
02

Formula for induced EMF

The formula for the average induced EMF in a coil is given by: \[\text{emf} = -N \frac{d\Phi}{dt}\] where \(N = 950\) is the number of turns, and \(\Phi\) is the magnetic flux.
03

Calculate Magnetic Flux Change

Magnetic flux \(\Phi\) through the coil is \(\Phi = BA\cos\theta\), where \(B\) is the magnetic field, \(A\) is the area of the coil, and \(\theta\) is the angle between the field and the normal of the coil. Initially, \(\theta = 90°\) and after \(0.010\) s, \(\theta = 45°\). The change in flux \(\Delta \Phi\) is given by: \[\Delta \Phi = B \times A \times (\cos 45° - \cos 90°)\]Using \(A = \pi r^2 = \pi (0.060)^2\).
04

Substitute and Solve for B

Substitute the values into the magnetic flux equation and solve for \(B\):\[\Delta \Phi = B \times \pi (0.060)^2 \times \left( \frac{1}{\sqrt{2}} - 0 \right)\]Using the relationship for average EMF:\[0.065 = 950 \times \frac{B \times \pi (0.060)^2 \times \frac{1}{\sqrt{2}}}{0.010}\]
05

Final Calculation

Rearrange the equation to solve for the magnetic field \(B\):\[B = \frac{0.065 \times 0.010}{950 \times \pi \times (0.060)^2 \times \frac{1}{\sqrt{2}}}\]Plug in the numbers to get the value of \(B\). Evaluate numerically for the final result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Coil
A circular coil is essentially a loop or loops of wire that have been wound in a circle or circular shape. It is often used in electromagnetic applications. The key property of a circular coil is the number of turns it has, which significantly affects its electromagnetic properties.

In this exercise, the coil has 950 turns, which means the wire has been wound around 950 times to form the coil. This large number of turns increases the coil's ability to induce or generate an electromotive force (emf) when exposed to a changing magnetic field. The radius of the coil, in this case, is 0.060 meters, which determines the size of the coil and affects the area through which the magnetic field lines pass.
  • Turns: The more turns, the greater the potential for induced emf.
  • Radius: Determines the size and area of the coil.
  • Shape: Circular shape aids in consistent distribution of magnetic field interaction.
Induced EMF
Induced emf (electromotive force) arises when a coil turns within a magnetic field, and this is described by Faraday's Law of Induction. The law states that the induced emf is equal to the rate of change of magnetic flux through a loop.

In mathematical terms, the induced emf \text{emf} is given by the formula \[\text{emf} = -N \frac{d\Phi}{dt}\], where:
  • N is the number of turns of the coil,
  • \(\frac{d\Phi}{dt}\) represents the rate of change of magnetic flux.
In our example, an average emf of 0.065 V is induced as the coil makes one-eighth of a revolution, changing orientation relative to the magnetic field. This change causes a variation in magnetic flux through the coil, which induces the emf.
  • Emf Formula: \[\text{emf} = -N \frac{d\Phi}{dt}\]
  • Understanding Change: The angle (\theta) changes as the coil rotates, leading to emf.
Magnetic Flux
Magnetic flux, represented by \(\Phi\), measures the quantity of magnetic field lines passing through a given area. For a coil, it is the product of the magnetic field \(B\), the coil's area \(A\), and the cosine of the angle ()nnn\(\theta\)n between the magnetic field and the normal to the surface of the coil.
  • Area (A): For a circular coil, \(A = \pi r^2\), where \(r\) is the radius of the coil.
  • Angle Factor: \(\cos\theta\) determines how much of the field lines pass normally through the surface.
Initially, the flux is zero at 90°, because no field lines pass perpendicularly through the coil. As the coil rotates to 45° in 0.010 s, it results in a change in flux, inducing emf.
  • Flux Change in Exercise: \[\Delta \Phi = B \times A \times (\cos 45° - \cos 90°)\]
  • Flux and Induced EMF: The change in flux over time directly influences induced emf.
Angle of Rotation
The angle of rotation in relation to the magnetic field impacts the magnetic flux through the coil. As the coil rotates, this angle changes, affecting the component of the magnetic field passing perpendicularly through the coil.

In this problem, the coil's normal initially is perpendicular (90°) to the field, yielding no magnetic flux through. As the coil turns to 45° in 0.010 seconds, the magnetic flux through the coil begins to change, causing an induced emf.
  • Angular Change: Influences the rate of change of magnetic flux.
  • 45-Degree Position: Marks a substantial change in flux compared to the initial perpendicular orientation.
  • Rotation Impact: The faster the rotation, the greater the rate of change in flux, thus higher induced emf.
Understanding how angles impact the magnetic flux and subsequent emf is essential in applications involving rotating coils in magnetic fields, such as electric generators.

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Most popular questions from this chapter

Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bicycle generator presses against the bike tire and turns the coil of the generator at an angular speed that is 38 times as great as the angular speed of the tire itself. Each tire has a radius of \(0.300 \mathrm{m}\). The coil consists of 125 turns, has an area of \(3.86 \times 10^{-3} \mathrm{m}^{2},\) and rotates in a \(0.0900-\mathrm{T}\) magnetic field. The bicycle starts from rest and has an acceleration of \(+0.550 \mathrm{m} / \mathrm{s}^{2} .\) What is the peak emf produced by the generator at the end of 5.10 s?

The coil of a generator has a radius of \(0.14 \mathrm{m} .\) When this coil is unwound, the wire from which it is made has a length of \(5.7 \mathrm{m}\). The magnetic field of the generator is \(0.20 \mathrm{T},\) and the coil rotates at an angular speed of \(25 \mathrm{rad} / \mathrm{s} .\) What is the peak emf of this generator?

In a television set the power needed to operate the picture tube comes from the secondary of a transformer. The primary of the transformer is connected to a \(120-\mathrm{V}\) receptacle on a wall. The picture tube of the television set uses \(91 \mathrm{W}\), and there is \(5.5 \mathrm{mA}\) of current in the secondary coil of the transformer to which the tube is connected. Find the turns ratio \(N_{\Omega} / N_{\mathrm{p}}\) of the transformer.

During a 72 -ms interval, a change in the current in a primary coil occurs. This change leads to the appearance of a \(6.0-\mathrm{mA}\) current in a nearby secondary coil. The secondary coil is part of a circuit in which the resistance is \(12 \Omega\). The mutual inductance between the two coils is \(3.2 \mathrm{mH}\). What is the change in the primary current?

Reconfiguring a Transformer. You and your team are exploring an abandoned science facility on the coast of western Antarctica when a large storm hits, and it is clear that you will be stuck there for a few days. You and the others search for supplies and find a generator and a tank of fuel. Having electrical power would allow you to keep your communication devices operational and make your stay more comfortable. A team member gets the generator running, but there is a complication: The output of the generator is \(50 \mathrm{Hz}\) at \(440 \mathrm{VAC}(\mathrm{RMS}),\) and your devices require \(60 \mathrm{Hz}, 110 \mathrm{VAC}(\mathrm{RMS})\) The electrical power in many European countries runs on \(240 \mathrm{V}\) at \(50 \mathrm{Hz},\) so a few of your team members have converters. However, \(440 \mathrm{V}\) is still too high to use them. You search and eventually find a large transformer that, according to a worn tag on its case, is designed to step down from \(5000 \mathrm{V}\) to \(880 \mathrm{V}\). The tag also indicates that its primary coil has 1500 turns, but you cannot read the number of turns in the secondary coil. (a) How many turns should its secondary coil have? (b) It will be a difficult job, but you can change the number of primary turns by cutting some of them out. How many turns should you leave on the primary coil so that, with the primary connected to \(440 \mathrm{V},\) the secondary outputs \(240 \mathrm{V}\) (so that you can use the \(240 \mathrm{V}\) to \(110 \mathrm{V}\) converters)? (c) You find that the current at the source (i.e., that connected to the primary) is limited to a maximum of \(20.0 \mathrm{A}\). What is the maximum current limit through the secondary coil? (d) What is the maximum average power available at the secondary coil?

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