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In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of \(3: 59.4 \mathrm{s}(3 \mathrm{min}\) and \(59.4 \mathrm{s}) .\) In 1999 the Moroccan runner Hicham el-Guerrouj set a record of 3: 43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?

Short Answer

Expert verified
El-Guerrouj would have won by 116 meters.

Step by step solution

01

Convert Time to Seconds

Convert both runners' times into seconds for easier calculation. Bannister's time of 3 minutes and 59.4 seconds can be converted as follows: \[ 3 \text{ minutes} = 180 \text{ seconds} \] \[ 180 \text{ seconds} + 59.4 \text{ seconds} = 239.4 \text{ seconds}\] El-Guerrouj's time is already given in seconds: 3 minutes and 43.13 seconds, which is \[ 3 \text{ minutes} = 180 \text{ seconds} \]\[ 180 \text{ seconds} + 43.13 \text{ seconds} = 223.13 \text{ seconds} \]
02

Determine Average Speed

The length of a mile is approximately 1609 meters. We will calculate the average speed of both runners in meters per second (m/s). For Bannister:\[ \text{Average Speed} = \frac{1609 \text{ m}}{239.4 \text{ s}} \approx 6.72 \text{ m/s} \]For El-Guerrouj:\[ \text{Average Speed} = \frac{1609 \text{ m}}{223.13 \text{ s}} \approx 7.21 \text{ m/s} \]
03

Calculate Distance Covered by Each Runner in 239.4 Seconds

We need to find how far each runner would have run after 239.4 seconds (Bannister's total race time) using their respective average speeds.El-Guerrouj's distance in 239.4 seconds is:\[ \text{Distance} = 7.21 \text{ m/s} \times 239.4 \text{ s} \approx 1725 \text{ meters} \]Bannister's distance is simply the length of a mile:\[ \text{Distance} = 1609 \text{ meters} \]
04

Compute the Winning Margin

Determine the difference between the distances covered by El-Guerrouj and Bannister.\[ \text{Winning Margin} = 1725 \text{ meters} - 1609 \text{ meters} = 116 \text{ meters} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Speed Calculation
Understanding how to calculate average speed is vital in solving physics problems concerning motion. Average speed is calculated by dividing the total distance covered by the total time taken. When a person or object travels a certain distance over a period, knowing its speed tells us how fast it was moving on average.

In our example, both Roger Bannister and Hicham el-Guerrouj covered the distance of a mile, which is approximately 1609 meters, but in different times. By dividing 1609 meters by Bannister's time of 239.4 seconds, we find his average speed to be 6.72 meters per second (m/s). Whereas, el-Guerrouj's average speed comes out to be about 7.21 m/s.
  • The formula for average speed is: \ \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]
  • Average speed gives a general idea of how fast someone goes over an entire trip or race.
Knowing these average speeds allows us to compare who would have won if the race conditions were aligned.
Unit Conversion
Converting units helps us compare measurements easily. In physics, converting time measurements from minutes to seconds is common to keep calculations straightforward.

For instance, when dealing with athletes' times, it's easier to calculate speeds in meters per second (m/s) rather than miles per hour or any other unit. Start by converting all time into seconds. One minute is equivalent to 60 seconds, so any time given in minutes and seconds needs to be converted:
  • Roger Bannister's time: 3 minutes equals 180 seconds. Thus, his total time is 180 + 59.4 = 239.4 seconds.
  • Hicham el-Guerrouj's time: 3 minutes equals 180 seconds. Thus, his time is 180 + 43.13 = 223.13 seconds.
Changing units makes it simpler to plug values into equations and directly compare times or speeds without error.
Distance Formula
The distance formula plays a crucial role in determining how far someone has traveled given their speed and time.

The concept of calculating distance can be represented with a simple formula:
  • Distance = Speed × Time \ \[ \text{Distance} = \text{Speed} \times \text{Time} \]
In our example, knowing el-Guerrouj's speed and using Roger Bannister’s total time, we can calculate how much further el-Guerrouj would have run in Bannister's time. By multiplying el-Guerrouj’s speed (7.21 m/s) by the time Bannister took (239.4 seconds), we get the distance el-Guerrouj could cover, which is approximately 1725 meters. This is compared against Bannister's mile, 1609 meters.

Using this formula, one can effectively calculate and understand the margin by which one runner would outpace another.
Historical Athletic Records
Breaking athletic records is a testament to human endurance and evolution in sports. Historical records like the ones mentioned—Roger Bannister's sub-four-minute mile in 1954 and Hicham el-Guerrouj’s even faster mile in 1999—showcase progression in human fitness and training methodologies over time.

These record-breaking moments are not just about setting new benchmarks but also about inspiring future athletes to achieve the seemingly impossible.
  • Bannister's achievement broke pre-existing psychological barriers by proving that running a mile in under four minutes was possible.
  • Subsequent records like el-Guerrouj's are examples of how this mindset, combined with advances in training, allowed for even faster times.
Understanding these milestones in sports history helps students realize how physics principles can enhance athletic performance and recognize the hard work and dedication in achieving record-breaking speeds.

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Most popular questions from this chapter

A locomotive is accelerating at \(1.6 \mathrm{m} / \mathrm{s}^{2} .\) It passes through a \(20.0-\mathrm{m}-\) wide crossing in a time of \(2.4 \mathrm{s} .\) After the locomotive leaves the crossing, how much time is required until its speed reaches \(32 \mathrm{m} / \mathrm{s} ?\)

The initial velocity and acceleration of four moving objects at a given instant in time are given in the following table. Determine the final speed of each of the objects, assuming that the time elapsed since \(t=0\) s is 2.0 s. $$ \begin{array}{lcc} & \text { Initial velocity } v_{0} & \text { Acceleration } a \\\\\hline \text { (a) } & +12 \mathrm{m} / \mathrm{s} & +3.0 \mathrm{m} / \mathrm{s}^{2} \\\\\hline \text { (b) } & +12 \mathrm{m} / \mathrm{s} & -3.0 \mathrm{m} / \mathrm{s}^{2} \\\\\hline \text { (c) } & -12 \mathrm{m} / \mathrm{s} & +3.0 \mathrm{m} / \mathrm{s}^{2} \\\\\hline \text { (d) } & -12 \mathrm{m} / \mathrm{s} & -3.0 \mathrm{m} / \mathrm{s}^{2} \\ \hline\end{array}$$

The Kentucky Derby is held at the Churchill Downs track in Louisville, Kentucky. The track is one and one-quarter miles in length. One of the most famous horses to win this event was Secretariat. In 1973 he set a Derby record that would be hard to beat. His average acceleration during the last four quarter-miles of the race was \(+0.0105 \mathrm{m} / \mathrm{s}^{2}\). His velocity at the start of the final mile \((x=+1609 \mathrm{m})\) was about \(+16.58 \mathrm{m} / \mathrm{s} .\) The acceleration, although small, was very important to his victory. To assess its effect, determine the difference between the time he would have taken to run the final mile at a constant velocity of \(+16.58 \mathrm{m} / \mathrm{s}\) and the time he actually took. Although the track is oval in shape, assume it is straight for the purpose of this problem.

An Australian emu is running due north in a straight line at a speed of \(13.0 \mathrm{m} / \mathrm{s}\) and slows down to a speed of \(10.6 \mathrm{m} / \mathrm{s}\) in \(4.0 \mathrm{s}\). (a) What is the direction of the bird's acceleration? (b) Assuming that the acceleration remains the same, what is the bird's velocity after an additional \(2.0 \mathrm{s}\) has elapsed?

A cheetah is hunting. Its prey runs for \(3.0 \mathrm{s}\) at a constant velocity of \(+9.0 \mathrm{m} / \mathrm{s} .\) Starting from rest, what constant acceleration must the cheetah maintain in order to run the same distance as its prey runs in the same time?

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