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A car makes a trip due north for three-fourths of the time and due south one- fourth of the time. The average northward velocity has a magnitude of \(27 \mathrm{m} / \mathrm{s},\) and the average southward velocity has a magnitude of \(17 \mathrm{m} / \mathrm{s} .\) What is the average velocity (magnitude and direction) for the entire trip?

Short Answer

Expert verified
The average velocity is 16 m/s north.

Step by step solution

01

Define Average Velocity

The average velocity of a trip is calculated by the formula: \( v_{avg} = \frac{\Delta x}{t_{total}} \) where \( \Delta x \) is the total displacement and \( t_{total} \) is the total time of travel.
02

Determine Total Time

Let the total time of the trip be \( t \). The car travels north for \( \frac{3}{4}t \) and south for \( \frac{1}{4}t \).
03

Calculate Northward Displacement

The northward displacement \( x_{north} \) is the product of velocity and time: \( x_{north} = 27 \mathrm{m/s} \times \frac{3}{4}t = \frac{81}{4}t \) m.
04

Calculate Southward Displacement

The southward displacement \( x_{south} \) is given by: \( x_{south} = 17 \mathrm{m/s} \times \frac{1}{4}t = \frac{17}{4}t \) m.
05

Calculate Total Displacement

Total displacement \( \Delta x \) is the difference between northward and southward displacements: \( \Delta x = x_{north} - x_{south} = \frac{81}{4}t - \frac{17}{4}t = \frac{64}{4}t = 16t \) m.
06

Calculate Average Velocity

Substitute \( \Delta x \) and \( t_{total} = t \) into the average velocity formula: \( v_{avg} = \frac{16t}{t} = 16 \) m/s.
07

Determine Direction of Average Velocity

Since the displacement is positive (16t), the average velocity direction is north.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement Calculation
Displacement is a measure of how far an object is from its starting point and in which direction. It considers the starting and ending positions, not the path taken. In this exercise, displacement is vital in figuring out the average velocity.
Imagine you are driving a car north, then south. The car's movement north adds to the displacement, while moving south takes away from it, because you're moving in the opposite direction.
  • Northward Displacement: The trip takes three-fourth of the total time, moving at 27 m/s. The northward displacement is calculated by multiplying speed and time: \( x_{north} = 27 \text{ m/s} \times \frac{3}{4}t = \frac{81}{4}t \text{ m} \).
  • Southward Displacement: During the one-fourth time period heading south, at 17 m/s. This displacement is \( x_{south} = 17 \text{ m/s} \times \frac{1}{4}t = \frac{17}{4}t \text{ m} \).
Finally, the total displacement is the difference between these two, calculated as \( \Delta x = \frac{81}{4}t - \frac{17}{4}t = 16t \text{ m} \), showing net movement to the north.
Northward and Southward Velocities
Northward and southward velocities represent how fast an object moves in each specific direction. In this problem, understanding these speeds is crucial to calculating displacement and average velocity.
  • Northward Velocity: The car travels north with an average velocity of 27 m/s. It's moving north for three-quarters of the trip duration. This longer period northward means it greatly affects the overall displacement and average velocity calculations.
  • Southward Velocity: The car moves south at 17 m/s, but only for one-quarter of the time. This velocity contributes less to the total displacement because it is both slower and for a shorter time frame.
Ultimately, the faster and longer northward movement results in a net positive displacement, indicating that the car ends up further north than its starting point after the trip.
Travel Time Calculation
Calculating the travel time is crucial as it allows us to determine both the displacements and ultimately the average velocity. Travel time directly influences the resulting displacements due to how long the car travels in each direction.
Assume the entire trip duration is denoted by \( t \). Here:
  • Northward Time: The car is traveling north for three-fourth of total time, or \( \frac{3}{4}t \).
  • Southward Time: The car travels south for one-fourth of the time, or \( \frac{1}{4}t \).
This arrangement is important because it sets the foundation for calculating the separate displacements. The time spent going north is key as it accounts for more influence over the final displacement compared to the southward time segment. Once you have the total travel time \( t \), you can substitute it into the formula for average velocity to determine how fast and in which direction the car traveled on average over the entire distance.

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Most popular questions from this chapter

A car is traveling at a constant speed of \(33 \mathrm{m} / \mathrm{s}\) on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is \(2.5 \mathrm{km}\) away?

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