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Electrons move through a certain electric circuit at an average speed of \(1.1 \times 10^{-2} \mathrm{m} / \mathrm{s} .\) How long (in minutes) does it take an electron to traverse \(1.5 \mathrm{m}\) of wire in the filament of a light bulb?

Short Answer

Expert verified
Approximately 2.27 minutes.

Step by step solution

01

Identify the Given Values

We are given the average speed of the electrons as \(1.1 \times 10^{-2} \text{ m/s}\) and the distance they need to travel as \(1.5 \text{ m}\). Our goal is to find the time it takes in minutes for an electron to traverse this distance.
02

Use the Speed Formula

The basic formula for speed is \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \). We need to rearrange this formula to solve for time: \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \).
03

Substitute the Values into the Formula

Substitute the given values into the formula: \( \text{Time} = \frac{1.5 \text{ m}}{1.1 \times 10^{-2} \text{ m/s}} \).
04

Calculate the Time in Seconds

Calculate the time it takes for the electron to traverse 1.5 meters: \( \text{Time} = \frac{1.5}{1.1 \times 10^{-2}} \approx 136.36 \text{ seconds}\).
05

Convert Time from Seconds to Minutes

Since the answer needs to be in minutes, convert the time from seconds to minutes: \(136.36 \text{ seconds} = \frac{136.36}{60} \approx 2.27 \text{ minutes}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Speed
In electric circuits, the movement of electrons is crucial. Electrons are negatively charged particles that flow through conductors, such as wires, to create an electric current. The speed of electrons in a circuit is relatively slow compared to the speed of electrical signals, which travel near the speed of light.

For instance, in the given problem, electrons move at an average speed of \(1.1 \times 10^{-2} \text{ m/s}\). This means that in one second, an electron covers a little more than a centimeter. This speed may seem slow, but with a vast number of electrons moving through the circuit, the electrical signal communicates almost instantly.

Understanding electron speed is important because it helps us calculate how long it takes for an electron to traverse a specific distance within a circuit, as discussed in the problem.
Distance and Time Calculations
When calculating the time it takes for an electron to travel a certain distance, the speed formula becomes quite handy. The basic formula to remember is:
  • Speed = \(\frac{\text{Distance}}{\text{Time}}\)
This formula can be rearranged to calculate time:
  • Time = \(\frac{\text{Distance}}{\text{Speed}}\)
In this example, the distance the electron needs to travel is 1.5 meters. To find the travel time, simply divide this distance by the speed of the electron. Substituting the given values, the equation becomes:
  • Time = \(\frac{1.5 \text{ m}}{1.1 \times 10^{-2} \text{ m/s}}\)
  • = 136.36 seconds

This calculation shows how mathematical equations enable us to connect the real-world distance traveled by electrons to the time it takes to complete that journey in a circuit.
Conversion of Units
Often, it's necessary to convert units for the convenience of understanding or reporting results. Converting time from seconds to minutes is a common task in physics and everyday life.

Since there are 60 seconds in a minute, we can convert seconds into minutes by dividing the total seconds by 60. In this problem, the calculated time in seconds was approximately 136.36 seconds. To convert this:*
  • Minutes = \(\frac{136.36 \text{ seconds}}{60}\)
  • = 2.27 minutes
Thus, the electron will take approximately 2.27 minutes to traverse the 1.5 meters in the light bulb filament.

Understanding unit conversion is key in physics as it ensures accuracy and consistency across different types of measurements. It is a vital skill that helps bridge the gap between calculated results and the practical world interpretation.

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Most popular questions from this chapter

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of \(6.0 \mathrm{m} / \mathrm{s}\) in \(1.5 \mathrm{s} .\) Assuming that the player accelerates uniformly, determine the distance he runs.

While standing on a bridge \(15.0 \mathrm{m}\) above the ground, you drop a stone from rest. When the stone has fallen \(3.20 \mathrm{m},\) you throw a second stone straight down. What initial velocity must you give the second stone if they are both to reach the ground at the same instant? Take the downward direction to be the negative direction.

An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of \(+15 \mathrm{m} / \mathrm{s}\) and measures a time of \(20.0 \mathrm{s}\) before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet?

In a historical movie, two knights on horseback start from rest \(88.0 \mathrm{m}\) apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of \(0.300 \mathrm{m} / \mathrm{s}^{2},\) while Sir Alfred's has a magnitude of \(0.200 \mathrm{m} / \mathrm{s}^{2} .\) Relative to Sir George's starting point, where do the knights collide?

A motorcycle has a constant acceleration of \(2.5 \mathrm{m} / \mathrm{s}^{2} .\) Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a) 21 to \(31 \mathrm{m} / \mathrm{s},\) and (b) 51 to \(61 \mathrm{m} / \mathrm{s} ?\)

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