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An amplified guitar has a sound intensity level that is \(14 \mathrm{dB}\) greater than the same unamplified sound. What is the ratio of the amplified intensity to the unamplified intensity?

Short Answer

Expert verified
The ratio is approximately 25.12.

Step by step solution

01

Understand the Decibel Scale

The sound intensity level in decibels (dB) is given by the formula \( L = 10 \log_{10} \left(\frac{I}{I_0}\right) \), where \( L \) is the sound level in dB, \( I \) is the intensity of the sound, and \( I_0 \) is the reference intensity. When the intensity level increases by a certain amount in dB, this corresponds to a multiplicative change in the actual intensity.
02

Define the Intensities

Let \( I_u \) be the intensity of the unamplified sound and \( I_a \) be the intensity of the amplified sound. We know that the sound intensity level difference between the amplified and unamplified sound is \( 14 \, \mathrm{dB} \).
03

Relate Intensity Levels

The relationship between the two intensities with respect to their sound levels is given by: \( 10 \log_{10} \left( \frac{I_a}{I_0} \right) - 10 \log_{10} \left( \frac{I_u}{I_0} \right) = 14 \). This simplifies to \( 10 \log_{10} \left( \frac{I_a}{I_u} \right) = 14 \).
04

Solve for the Intensity Ratio

Divide both sides of the equation by 10 to get \( \log_{10} \left( \frac{I_a}{I_u} \right) = 1.4 \). Converting back from logarithmic form gives us \( \frac{I_a}{I_u} = 10^{1.4} \).
05

Calculate the Result

Use a calculator to find \( 10^{1.4} \). This yields approximately \( 25.12 \). Hence, the intensity of the amplified sound is about 25.12 times greater than the intensity of the unamplified sound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Scale
Every sound we hear can be measured using the decibel scale, which is crucial for understanding sound intensity levels. The decibel scale is logarithmic, meaning it represents sound intensity levels in a way that accommodates the enormous range of sound intensities we can hear—from the faintest whisper to the roar of a jet engine. The formula used to calculate the sound level in decibels is \( L = 10 \log_{10} \left(\frac{I}{I_0}\right) \), where \( L \) is the sound level in decibels, \( I \) is the sound intensity, and \( I_0 \) is the reference intensity, often chosen as the threshold of hearing.

When an intensity increases by a certain number of decibels, it doesn't increase linearly. Instead, each increment of 10 dB corresponds to a tenfold increase in intensity. In our exercise, the sound level increased by 14 dB when the guitar sound was amplified. This increase is exponential due to the properties of the logarithmic decibel scale.
Logarithmic Functions in Physics
Logarithms play a valuable role in physics, particularly when dealing with phenomena like sound, where quantities vary over a wide range. The decibel formula is grounded in logarithmic functions.

For example, when we state that \( 10 \log_{10}x \) is used in the formula for sound, that logarithm compresses a wide range of intensity values into a manageable scale. This is because the human ear perceives sound levels logarithmically. A known result of this function applied in the context of sound intensity is that when intensities are compared, the equation can be rearranged to express the relationship between two different intensities:
  • If \( 10 \log_{10} \left(\frac{I_a}{I_u}\right) = 14 \), we simplified it to \( \log_{10} \left(\frac{I_a}{I_u}\right) = 1.4 \).
  • This allows us to conclude that the ratio of the two intensities is \( 10^{1.4} \).
Thus, logarithmic functions help us translate the changes in physical quantities into more understandable scales.
Sound Amplification
Sound amplification is a process that involves increasing the intensity of sound waves. When a sound, such as an electric guitar, is run through an amplifier, the goal is to increase its loudness. The relationship between unamplified and amplified sounds can be illustrated using the decibel scale.

In the exercise we tackled, the amplified sound was 14 dB louder than the unamplified sound, showing a significant increase in intensity.
  • This 14 dB increase corresponds to the sound's intensity being magnified by approximately 25.12 times, as calculated by \( 10^{1.4} \).
  • The amplification process causes the electrical signals corresponding to the sound to be multiplied, resulting in more robust sound waves.
By comprehending the concepts of decibel and logarithmic relationships in physics, we gain a deeper understanding of how sound amplification works and how loudness is scientifically measured.

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