/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 An observer stands \(25 \mathrm{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An observer stands \(25 \mathrm{m}\) behind a marksman practicing at a rifle range. The marksman fires the rifle horizontally, the speed of the bullets is \(840 \mathrm{m} / \mathrm{s},\) and the air temperature is \(20^{\circ} \mathrm{C} .\) How far does each bullet travel before the observer hears the report of the rifle? Assume that the bullets encounter no obstacles during this interval, and ignore both air resistance and the vertical component of the bullets" motion.

Short Answer

Expert verified
Each bullet travels approximately 61.32 m before the observer hears the shot.

Step by step solution

01

Determine the speed of sound

The speed of sound in air at a temperature of \(20^{\circ}\text{C}\) is approximately \(343 \text{ m/s}\). This can be found from reference tables or using the formula \( v = 331.3 + 0.6\times T \), where \( T \) is the temperature in Celsius.
02

Calculate the time it takes for sound to reach the observer

The observer stands \(25\text{ m}\) behind the marksman. The time it takes for sound to travel this distance is calculated using the formula \( t = \frac{d}{v} \), where \( d = 25\text{ m} \) and \( v = 343 \text{ m/s} \). Thus, \( t = \frac{25}{343} \approx 0.073\text{ seconds} \).
03

Calculate the distance traveled by the bullet during this time

Since the speed of the bullet is \(840\text{ m/s}\), the distance \(d_b\) traveled by the bullet in \(0.073\text{ seconds}\) can be found using the formula \( d_b = v_b \times t \), where \( v_b = 840\text{ m/s} \). Hence, \( d_b = 840 \times 0.073 = 61.32\text{ m} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed of Sound
The speed of sound is a fascinating aspect of physics that involves how sound waves travel through different mediums. In air, at room temperature, the speed of sound is approximately 343 meters per second (m/s). This speed is not constant; it varies depending on factors like air temperature and pressure. A general formula to calculate the speed of sound in air, based on temperature, is \[v = 331.3 + 0.6 \times T \]where \( v \) is the speed of sound and \( T \) is the air temperature in degrees Celsius.
  • For every increase of 1 degree Celsius, the speed of sound increases by about 0.6 m/s.
  • At 20°C, typical room temperature, sound travels at 343 m/s in air, which is crucial for calculating how quickly sound reaches a given distance.
Understanding the speed of sound helps predict how long it takes for someone to hear a sound after it is produced by a source such as a rifle. This knowledge is fundamental when you need to calculate how far a moving object like a bullet will travel before the sound reaches an observer.
Bullet Velocity
When considering bullet velocity, or the speed at which a bullet travels, it's crucial to note its consistency and impact on calculations. In this exercise, the bullet's velocity is given as 840 m/s. This speed remains consistent throughout the bullet's flight because we are ignoring factors like air resistance and gravity's pull on its vertical motion.
  • Bullet velocity is significantly higher than the speed of sound, which means the bullet will travel a considerable distance in a short period.
  • By knowing the velocity, we can calculate how far a bullet would travel in any given time frame.
These calculations are essential for understanding the difference in perception versus actual events—like hearing the rifle's report after the bullet has already traveled far. Bullet velocity is one of the critical factors when calculating distances in physics problems like this one.
Distance Calculation
Distance calculation is a key concept often used to determine how far an object moves over a given period. In the context of the exercise, we calculate the distance a bullet travels before the observer hears the shot fired from the rifle.
First, we must determine the time it takes for sound to travel from the rifle to the observer. This is done using the formula:\[t = \frac{d}{v}\]where \( d \) is the distance from the marksman to the observer (25 m), and \( v \) is the speed of sound (343 m/s). Hence, \( t \approx 0.073 \) seconds.
  • This time calculation represents the delay in the observer hearing the rifle's report.
Next, calculate how far the bullet has traveled in this time:\[d_b = v_b \times t\]where \( v_b \) is the bullet velocity (840 m/s), and \( t \) is the time calculated. Plugging in the values gives:\[d_b = 840 \times 0.073 = 61.32 \text{ meters}\]
  • This distance shows how far the bullet has traveled when the sound reaches the observer.
Overall, distance calculation integrates various values to reach a conclusion, serving as a vital part of physics problem-solving.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawater where the speed of sound is \(1522 \mathrm{m} / \mathrm{s}\). When the dolphin is swimming directly away at \(8.0 \mathrm{m} / \mathrm{s},\) the marine biologist measures the number of clicks occurring per second to be at a frequency of 2500 Hz. What is the difference (in \(\mathrm{Hz}\) ) between this frequency and the number of clicks per second actually emitted by the dolphin?

The siren on an ambulance is emitting a sound whose frequency is \(2450 \mathrm{Hz} .\) The speed of sound is \(343 \mathrm{m} / \mathrm{s} .\) (a) If the ambulance is stationary and you (the "observer") are sitting in a parked car, what are the wavelength and the frequency of the sound you hear? (b) Suppose that the ambulance is moving toward you at a speed of \(26.8 \mathrm{m} / \mathrm{s} .\) Determine the wavelength and the frequency of the sound you hear. (c) If the ambulance is moving toward you at a speed of \(26.8 \mathrm{m} / \mathrm{s}\) and you are moving toward it at a speed of \(14.0 \mathrm{m} / \mathrm{s}\) find the wavelength and frequency of the sound you hear.

Two trucks travel at the same speed. They are far apart on adjacent lanes and approach each other essentially head-on. One driver hears the horn of the other truck at a frequency that is 1.14 times the frequency he hears when the trucks are stationary. The speed of sound is \(343 \mathrm{m} / \mathrm{s}\). At what speed is each truck moving?

A Mysterious Underwater Object. You and your team are on a reconnaissance mission in a submarine exploring a mysterious object in the cold waters of the Weddell Sea, off the coast of Antarctica. The sonar indicates that the object, which had otherwise been moving erratically, has changed course and is now on a direct collision course with your sub. The captain issues an "all stop" order, bringing the sub to a halt relative to the water. The sonar operator "pings" the object, which amounts to sending a short blast of sound in the direction of the object. The emitted sound wave has a frequency of \(1550 \mathrm{Hz}\) and a speed of \(1552 \mathrm{m} / \mathrm{s}\) (the speed of sound in seawater). The sound reflects from the object and returns \(2.582 \mathrm{s}\) after it was emitted from your sub, and its frequency has shifted to \(1598 \mathrm{Hz}\). (a) How far from the sub was the object when the sound reflected from it? (b) What is the object's speed? (c) How long after you receive the return signal will it take the object to reach your submarine?

Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticeable, but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of \(750 \mathrm{km}\) and traveled a distance of \(3700 \mathrm{km}\) in \(5.3 \mathrm{h}\). (a) What was the speed (in \(\mathrm{m} / \mathrm{s}\) ) of the wave? For reference, the speed of a 747 jetliner is about \(250 \mathrm{m} / \mathrm{s}\). Find the wave's (b) frequency and (c) period.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.