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Argon (molecular mass \(=39.9 \mathrm{u}\) ) is a monatomic gas. Assuming that it behaves like an ideal gas at \(298 \mathrm{K}(\gamma=1.67),\) find \((\mathrm{a})\) the rms speed of argon atoms and (b) the speed of sound in argon.

Short Answer

Expert verified
The rms speed is 431 m/s and the speed of sound is 323 m/s.

Step by step solution

01

Understanding the Given Information

We are given that argon is a monatomic gas with a molecular mass of 39.9 u, behaves as an ideal gas at 298 K, and has a heat capacity ratio \(\gamma = 1.67\). We need to find the root-mean-square (rms) speed of argon atoms and the speed of sound in argon.
02

Calculate RMS Speed of Argon Atoms

The rms speed \(v_{rms}\) of a gas is calculated using the formula \(v_{rms} = \sqrt{\frac{3kT}{m}}\), where \(k\) is Boltzmann's constant \(1.38 \times 10^{-23} \text{ J/K}\), \(T\) is the temperature, and \(m\) is the mass of a single atom. First, convert the molecular mass from atomic mass units (u) to kilograms using the conversion \(1 \text{ u} = 1.660539 \times 10^{-27} \text{ kg}\). Thus, the mass of one argon atom is \(m = 39.9 \times 1.660539 \times 10^{-27} \text{ kg}\). Calculate the rms speed by substituting the values into the formula.
03

Substitute Values and Solve for RMS Speed

Substitute \(k = 1.38 \times 10^{-23} \text{ J/K}\), \(T = 298 \text{ K}\), and \(m = 39.9 \times 1.660539 \times 10^{-27} \text{ kg}\) into the rms speed formula:\[v_{rms} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 298}{39.9 \times 1.660539 \times 10^{-27}}} \].Calculate to find \(v_{rms} \approx 431 \text{ m/s}\).
04

Calculate Speed of Sound in Argon

The speed of sound in a gas is given by the formula \(v_{sound} = \sqrt{\frac{\gamma RT}{M}}\), where \(R\) is the universal gas constant \(8.314 \text{ J/(mol K)}\), \(T\) is the temperature, \(\gamma\) is the heat capacity ratio, and \(M\) is the molar mass in kg/mol. First, convert the molecular mass to molar mass by multiplying by \(10^{-3}\). Thus, \(M = 39.9 \times 10^{-3} \text{ kg/mol}\). Calculate the speed of sound by substituting the values into the formula.
05

Substitute Values and Solve for Speed of Sound

Substitute \(\gamma = 1.67\), \(R = 8.314 \text{ J/(mol K)}\), \(T = 298 \text{ K}\), and \(M = 39.9 \times 10^{-3} \text{ kg/mol}\) into the speed of sound formula:\[v_{sound} = \sqrt{\frac{1.67 \times 8.314 \times 298}{39.9 \times 10^{-3}}} \].Calculate to find \(v_{sound} \approx 323 \text{ m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rms speed
The root-mean-square (rms) speed is a measure of the speed of particles in a gas, and it gives an idea of the average motion of atoms or molecules within the gas. For an ideal gas, the rms speed is calculated using the equation:
  • \( v_{rms} = \sqrt{\frac{3kT}{m}} \)
Here, \( k \) is Boltzmann's constant, \( T \) is the absolute temperature in Kelvin, and \( m \) is the mass of a single particle.
The formula represents the average kinetic energy per particle, related to its temperature. It allows scientists to understand how fast particles are moving in response to their thermal energy. This speed is crucial in understanding diffusion, gas pressure, and thermal conductivity in gases.
speed of sound
The speed of sound in a gas is an important concept in physics and can be determined with the formula:
  • \( v_{sound} = \sqrt{\frac{\gamma RT}{M}} \)
In this equation, \( \gamma \) is the heat capacity ratio (also known as adiabatic index), \( R \) is the universal gas constant, \( T \) is the temperature, and \( M \) is the molar mass of the gas.
The speed of sound depends on the medium through which it travels. It is faster in solids, slower in liquids, and slowest in gases because of their differing densities and elastic properties. In gases, as temperature rises, the speed of sound increases, demonstrating the dependency on thermal energy, which causes particles to move faster, transmitting sound waves more rapidly.
Boltzmann's constant
Boltzmann's constant \( k \) is a fundamental physical constant that relates the average kinetic energy of particles in a gas with the temperature of the gas. Its value is approximately \( 1.38 \times 10^{-23} \text{ J/K} \).
It is a bridge between macroscopic and microscopic physics, linking thermodynamic quantities with atomic-scale properties. This constant is essential in the derivation of both the ideal gas law and the kinetic theory of gases. When calculating the rms speed or other thermodynamic properties, Boltzmann's constant plays a crucial role in ensuring that the equations relate thermal and motion characteristics appropriately.
molecular mass
Molecular mass is a bulk property representing the mass of a given molecule. It's usually expressed in atomic mass units (u) for precision. For practical calculations, we often convert it to kilograms using the conversion factor:
  • \( 1 \text{ u} = 1.660539 \times 10^{-27} \text{ kg} \)
This conversion is necessary when inserting the mass into equations like the rms speed formula.
Knowledge of molecular mass allows the calculation of the molar mass, crucial for determining the density and behavior of gases under varying conditions. It reflects how much an individual molecule of the substance weighs, aiding in various calculations in both chemistry and physics, particularly when dealing with gases.
heat capacity ratio
The heat capacity ratio, often represented by \( \gamma \), is the ratio of the heat capacity at constant pressure \( C_p \) to the heat capacity at constant volume \( C_v \). The formula is:
  • \( \gamma = \frac{C_p}{C_v} \)
This ratio is crucial for processes involving thermodynamic activities such as adiabatic processes, where no heat is transferred to or from the gas.
For monatomic gases like argon, the value of \( \gamma \) is typically close to 1.67. It influences the speed of sound in gases because it affects how much a gas can be compressed or expanded when experiencing pressure waves. Understanding \( \gamma \) helps in studying phenomena like sound propagation, shock waves, and engine cycles in thermodynamics.

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Most popular questions from this chapter

An observer stands \(25 \mathrm{m}\) behind a marksman practicing at a rifle range. The marksman fires the rifle horizontally, the speed of the bullets is \(840 \mathrm{m} / \mathrm{s},\) and the air temperature is \(20^{\circ} \mathrm{C} .\) How far does each bullet travel before the observer hears the report of the rifle? Assume that the bullets encounter no obstacles during this interval, and ignore both air resistance and the vertical component of the bullets" motion.

A car is parked \(20.0 \mathrm{m}\) directly south of a railroad crossing. A train is approaching the crossing from the west, headed directly east at a speed of \(55.0 \mathrm{m} / \mathrm{s}\). The train sounds a short blast of its \(289-\mathrm{Hz}\). horn when it reaches a point \(20.0 \mathrm{m}\) west of the crossing. What frequency does the car's driver hear when the horn blast reaches the car? The speed of sound in air is \(343 \mathrm{m} / \mathrm{s} .\)

The security alarm on a parked car goes off and produces a frequency of \(960 \mathrm{Hz}\). The speed of sound is \(343 \mathrm{m} / \mathrm{s}\). As you drive toward this parked car, pass it, and drive away, you observe the frequency to change by \(95 \mathrm{Hz}\) Al what speed are you driving?

The volume control on a surround-sound amplifier is adjusted so the sound intensity level at the listening position increases from 23 to 61 dB. What is the ratio of the final sound intensity to the original sound intensity?

A hunter is standing on flat ground between two vertical cliffs that are directly opposite one another. He is closer to one cliff than to the other. He fires a gun and, after a while, hears three echoes. The second echo arrives \(1.6 \mathrm{s}\) after the first, and the third echo arrives \(1.1 \mathrm{s}\) after the second. Assuming that the speed of sound is \(343 \mathrm{m} / \mathrm{s}\) and that there are no reflections of sound from the ground, find the distance between the cliffs.

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