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Near the surface of Venus, the rms speed of carbon dioxide molecules \(\left(\mathrm{CO}_{2}\right)\) is \(650 \mathrm{m} / \mathrm{s} .\) What is the temperature (in kelvins) of the atmosphere at that point?

Short Answer

Expert verified
The temperature is approximately 746 K.

Step by step solution

01

Understand the Formula for RMS Speed

The root-mean-square (RMS) speed formula for a gas is given by \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( v_{rms} \) is the RMS speed, \( k \) is the Boltzmann constant \( (1.38 \times 10^{-23} \, \text{J/K}) \), \( T \) is the temperature in Kelvin, and \( m \) is the mass of one molecule of the gas. The molecular mass of \( \text{CO}_2 \) in kilograms can be found using its molar mass.
02

Convert Molar Mass to Molecular Mass

The molar mass of \( \text{CO}_2 \) is \( 44.01 \, \text{g/mol} \). To find the molecular mass \( m \), convert this to kilograms per molecule by dividing by Avogadro's number \( 6.022 \times 10^{23} \), and converting grams to kilograms:\[ m = \frac{44.01 \, \text{g/mol}}{6.022 \times 10^{23} \, \text{molecules/mol}} \times \frac{1 \, \text{kg}}{1000 \, \text{g}} = 7.3087 \times 10^{-26} \, \text{kg} \]
03

Rearrange the RMS Speed Equation

Rearrange the formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \) to solve for the temperature \( T \):\[ T = \frac{v_{rms}^2 \cdot m}{3k} \]
04

Substitute Known Values

Substitute the known values into the rearranged equation:\( v_{rms} = 650 \, \text{m/s} \), \( m = 7.3087 \times 10^{-26} \, \text{kg} \), and \( k = 1.38 \times 10^{-23} \, \text{J/K} \):\[ T = \frac{(650 \, \text{m/s})^2 \times 7.3087 \times 10^{-26} \, \text{kg}}{3 \times 1.38 \times 10^{-23} \, \text{J/K}} \]
05

Calculate the Temperature

Perform the calculation:1. \( 650^2 = 422500 \)2. \( 422500 \times 7.3087 \times 10^{-26} = 3.088 \times 10^{-20} \)3. \( 3 \times 1.38 \times 10^{-23} = 4.14 \times 10^{-23} \)4. \( \frac{3.088 \times 10^{-20} \text{ J}}{4.14 \times 10^{-23} \text{ J/K}} = 745.89 \, \text{K} \)Therefore, the temperature is approximately \( 746 \, \text{K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Root-Mean-Square Speed
Root-mean-square speed (often abbreviated as RMS speed) is a concept in physics that helps us understand how gas molecules move. Imagine each molecule in a gas zipping around in different directions and at different speeds. The RMS speed essentially gives us an average speed for these molecules.
The formula for calculating the RMS speed is: \[ v_{rms} = \sqrt{\frac{3kT}{m}} \] where:
  • \( v_{rms} \) is the RMS speed, which we measure in meters per second (m/s).
  • \( k \) is the Boltzmann constant, which we'll talk about in the next section.
  • \( T \) is the temperature in Kelvin (K).
  • \( m \) is the mass of a single molecule in kilograms (kg).
This calculation helps predict how fast molecules travel at a given temperature, which is useful for understanding gases behavior in different environments, like the atmosphere on Venus.
Boltzmann Constant
The Boltzmann constant \( k \) is crucial in the world of thermodynamics and kinetic theory. Named after the physicist Ludwig Boltzmann, this constant connects the microscopic world of atoms and molecules to macroscopic physical properties like temperature and energy.
In the definition of RMS speed, the Boltzmann constant \( k \) is used to relate the temperature of a gas to the energy of its molecules. Its value is approximately \( 1.38 \times 10^{-23} \text{ J/K} \). This means for every Kelvin increase in temperature, each molecule's energy increases by this amount, in Joules.
By using this constant, we can analyze how individual particles behave in relation to temperature, making it an important component in RMS speed calculations. If you're examining things like Venus' atmosphere, which is quite hot, the Boltzmann constant helps link these extremely active molecules to the temperatures we calculate.
Molecular Mass Conversion
To find the mass of a single molecule, such as Carbon Dioxide (\( \text{CO}_2 \)), we need to convert its molar mass, which is often listed in grams per mole, to an individual molecular mass in kilograms. This is because the RMS speed formula requires the mass of a single molecule.
Here's how we do it for \( \text{CO}_2 \):
  • The molar mass given is 44.01 g/mol.
  • We convert this to kilograms by dividing by 1000, so that becomes 0.04401 kg/mol.
  • Then, we divide this by Avogadro's number \( 6.022 \times 10^{23} \), as it represents the number of molecules in a mole, to get the mass of a single molecule:
  • \[ m = \frac{0.04401 \text{ kg/mol}}{6.022 \times 10^{23} \text{ molecules/mol}} \approx 7.3087 \times 10^{-26} \text{ kg} \]
Understanding this conversion is key to calculating molecular speeds and consequently temperatures, taking microscopic masses and making them manageable for equations involving gases.
Venus Atmosphere
Venus, the second planet from the Sun, has an atmosphere that offers a stern contrast to Earth. It’s a thick soup dominated by carbon dioxide (\( \text{CO}_2 \)). Due to its thick atmosphere, Venus experiences the hottest surface temperatures in our solar system.
The kind of calculations we discussed, like finding RMS speeds, are particularly insightful on Venus. They help researchers understand how hot and dynamic the atmosphere really is. With an average surface temperature around 740 K (or close to 467 °C), these calculations using RMS speeds can validate such conditions of intense heat.
The knowledge of RMS speed and molecular mass conversion helps scientists predict other factors in Venus' atmosphere, such as wind speeds and energy distribution. Even though Venus is covered in thick clouds, these fundamental calculations allow us to make educated predictions about its surface conditions and atmospheric behavior.

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Most popular questions from this chapter

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