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A runner weighs \(580 \mathrm{N}\) (about \(130 \mathrm{lb}\) ), and \(71 \%\) of this weight is water. (a) How many moles of water are in the runner's body? (b) How many water molecules \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) are there?

Short Answer

Expert verified
There are approximately 2333.59 moles of water and 1.405 x 10^{27} water molecules in the runner's body.

Step by step solution

01

Calculate Runner's Water Weight

First, we determine the weight of water in the runner's body by calculating 71% of the total weight. Since the runner weighs 580 N, the weight of the water is calculated as follows:\[ \text{Weight of water} = 0.71 \times 580 \text{ N} = 411.8 \text{ N} \]
02

Convert Weight to Mass in Kilograms

To find the mass of water, we convert the weight from newtons to kilograms using the relationship: weight = mass \times gravity \( (9.8 \, \text{m/s}^2) \).\[ \text{Mass of water} = \frac{411.8 \text{ N}}{9.8 \, \text{m/s}^2} = 42.02 \text{ kg} \]
03

Convert Mass to Moles of Water

Next, we calculate the number of moles of water. The molar mass of water (\(\mathrm{H_2O}\)) is approximately 18.015 g/mol. Converting kilograms to grams, the mass of water is 42,020 g.\[ \text{Moles of water} = \frac{42020 \text{ g}}{18.015 \text{ g/mol}} = 2333.59 \text{ moles} \]
04

Calculate Number of Water Molecules

Finally, we determine the total number of water molecules. Each mole consists of Avogadro's number of entities, which is approximately \(6.022 \times 10^{23}\) molecules/mol.\[ \text{Number of water molecules} = 2333.59 \times 6.022 \times 10^{23} = 1.405 \times 10^{27} \text{ molecules} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Weight Conversion
Understanding mass and weight conversion is crucial to solving problems like the one presented. Weight is a measure of the force exerted by gravity on an object, and it is measured in newtons (N). Mass, on the other hand, is the amount of matter in an object, measured in kilograms (kg). These two quantities are related by the gravitational force, which on Earth is approximately 9.8 meters per second squared \( (9.8 \, \text{m/s}^2) \).

To convert weight to mass, you can use the formula: \[ \text{mass} = \frac{\text{weight}}{\text{gravity}} \]
In this way, the weight in newtons is divided by the acceleration due to gravity to find the mass in kilograms. For example, if an object weighs 411.8 N, its mass would be 42.02 kg when divided by 9.8 m/s². This basic conversion allows you to shift between forces (weight) and matter content (mass), which is essential for further calculations involving moles and molecules.
Molar Mass
The molar mass of a substance is a key concept in chemistry that refers to the mass of one mole of a substance. It is expressed in grams per mole (g/mol). For instance, water has a molar mass of approximately 18.015 g/mol, determined by adding the atomic masses of its constituent atoms (two hydrogen atoms and one oxygen atom).

Understanding molar mass allows you to convert between the mass of a sample and the number of moles it contains, an essential step in stoichiometry and chemical calculations. The formula for this conversion is: \[ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
In the exercise, after converting the water's weight to mass, the mass (42,020 g) is divided by the molar mass of water (18.015 g/mol) to find 2333.59 moles of water. This calculation is fundamental for determining the number of molecules involved in the sample.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry, representing the number of atoms or molecules in one mole of a substance. It is approximately \(6.022 \times 10^{23}\) entities/mol. This large number allows chemists to convert between moles and the actual number of atoms or molecules, bridging the gap between macro-level measurements and the atomic world.

For example, once you know the number of moles of a substance, you can multiply it by Avogadro's number to find out how many molecules you have. In the step-by-step solution, 2333.59 moles of water are multiplied by Avogadro's number to calculate the total number of water molecules, resulting in \(1.405 \times 10^{27}\) molecules. This approach is vital for understanding and working with chemical reactions, where specific amounts of substances interact at the molecular level.

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Most popular questions from this chapter

One assumption of the ideal gas law is that the atoms or molecules themselves occupy a negligible volume. Verify that this assumption is reasonable by considering gaseous xenon (Xe). Xenon has an atomic radius of \(2.0 \times 10^{-10} \mathrm{m} .\) For STP conditions, calculate the percentage of the total volume occupied by the atoms.

The mass of a hot-air balloon and its occupants is \(320 \mathrm{kg}\) (excluding the hot air inside the balloon). The air outside the balloon has a pressure of \(1.01 \times 10^{5}\) Pa and a density of \(1.29 \mathrm{kg} / \mathrm{m}^{3}\). To lift off, the air inside the balloon is heated. The volume of the heated balloon is \(650 \mathrm{m}^{3} .\) The pressure of the heated air remains the same as the pressure of the outside air. To what temperature (in kelvins) must the air be heated so that the balloon just lifts off? The molecular mass of air is 29 u.

Two moles of an ideal gas are placed in a container whose volume is \(8.5 \times 10^{-3} \mathrm{m}^{3} .\) The absolute pressure of the gas is \(4.5 \times 10^{5} \mathrm{Pa} .\) What is the average translational kinetic energy of a molecule of the gas?

A tank contains \(11.0 \mathrm{g}\) of chlorine gas \(\left(\mathrm{Cl}_{2}\right)\) at a temperature of \(82^{\circ} \mathrm{C}\) and an absolute pressure of \(5.60 \times 10^{5} \mathrm{Pa} .\) The mass per mole of \(\mathrm{Cl}_{2}\) is \(70.9 \mathrm{g} / \mathrm{mol}\) (a) Determine the volume of the tank. (b) Later, the temperature of the tank has dropped to \(31^{\circ} \mathrm{C}\) and, due to a leak, the pressure has dropped to \(3.80 \times 10^{5}\) Pa. How many grams of chlorine gas have leaked out of the tank?

The volume of an ideal gas is held constant. Determine the ratio \(P_{2} / P_{1}\) of the final pressure to the initial pressure when the temperature of the gas rises (a) from 35.0 to \(70.0 \mathrm{K}\) and (b) from 35.0 to \(70.0^{\circ} \mathrm{C}\).

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