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Two ideal gases have the same mass density and the same absolute pressure. One of the gases is helium (He), and its temperature is \(175 \mathrm{K}\). The other gas is neon (Ne). What is the temperature of the neon?

Short Answer

Expert verified
The temperature of neon is 35 K.

Step by step solution

01

Understand the Given Information

We are given two ideal gases with the same mass density and pressure. Helium (He) has a known temperature of 175K. We need to find the temperature of Neon (Ne).
02

Apply the Ideal Gas Law

The ideal gas law is given by \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the universal gas constant, and \( T \) is temperature. Since pressure is the same for both gases, we can write: \( n_{He}RT_{He} = n_{Ne}RT_{Ne} \).
03

Consider the Mass Density

Since mass density is the same, \( \frac{M_{He}}{V} = \frac{M_{Ne}}{V} \), where \( M \) is molar mass. For helium, \( M_{He} = 4 \: g/mol \), and for neon, \( M_{Ne} = 20 \: g/mol \). The number of moles is given by \( n = \frac{M}{M_{mol}} \), where \( M_{mol} \) is the molar mass.
04

Relate the Densities and Temperatures

From the density relationship, \( \frac{n_{He} \, M_{He}}{V} = \frac{n_{Ne} \, M_{Ne}}{V} \), which implies \( n_{He} \, M_{He} = n_{Ne} \, M_{Ne} \). Substituting the ideal gas equation, \( M_{He} \, R \, T_{He} = M_{Ne} \, R \, T_{Ne} \).
05

Solve for Neon Temperature

Simplify the equation from the previous step: \( 4 \, R \, 175 = 20 \, R \, T_{Ne} \). Solving for \( T_{Ne} \), we find \( T_{Ne} = \frac{4 \times 175}{20} = 35 \: K \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Density
Mass density refers to how much mass is contained within a certain volume of a substance. For gases, this concept might be less intuitive than for liquids or solids, but it remains a critical parameter. Mass density, denoted by \( \rho \), can be mathematically expressed as the mass \( m \) of the substance divided by its volume \( V \): \[ \rho = \frac{m}{V} \]For ideal gases, mass density can also be related to the number of moles \( n \) and molar mass \( M_{mol} \) using the equation: \[ \rho = \frac{n \cdot M_{mol}}{V} \]In the problem context, both helium and neon gases have equal mass densities and pressures. This implies that their ratio of mass to volume is the same, even though their molecular compositions differ. This setting allows the use of the ideal gas law to explore relationships between temperature and molar mass, which are adjusted to maintain this equal-density condition.
  • Helium: \( M_{He} = 4 \, \text{g/mol} \)
  • Neon: \( M_{Ne} = 20 \, \text{g/mol} \)
By understanding that the densities are equal, we can directly relate the temperatures of these gases through their molar masses as seen in the further solution steps.
Absolute Pressure
Absolute pressure is a measure of gas pressure without any relation to atmospheric pressure. It's an essential component in the ideal gas law, expressed as \( P \) in the equation \( PV = nRT \), where \( n \) is the number of moles, \( R \) is the universal gas constant, and \( T \) is the temperature. It's important to note that absolute pressure is always positive and differs from gauge pressure, which considers ambient atmospheric pressure. In the context of the exercise, both helium and neon gases are subjected to the same absolute pressure, enabling further deductions about their temperatures if other factors like density are controlled.Understanding absolute pressure helps us:
  • Precisely determine the behavior and state of gases in controlled environments.
  • Apply theoretical calculations, such as the one above, to real-world situations.
In this exercise, knowing that both gases have identical absolute pressures allows us to equate their respective manipulated ideal gas equations, finding the new temperature with relative ease.
Molar Mass
Molar mass is the mass of a given substance divided by the amount of substance, typically expressed in grams per mole (g/mol). It serves as a bridge between the macroscopic and atomic scale, representing the mass of one mole of that substance’s molecules or atoms. For the ideal gas law computations, molar mass is critical in determining properties such as density and volume, as well as translating between mass and number of moles.In this scenario:
  • Helium has a molar mass of \( 4 \, \text{g/mol} \)
  • Neon has a molar mass of \( 20 \, \text{g/mol} \)
This difference in molar masses informs how temperatures adjust to maintain equal densities across gases with similar absolute pressures. In our problem, by equating the temperatures and considering molar masses, we utilized the equation \( M_{He} \, T_{He} = M_{Ne} \, T_{Ne} \) to work out that neon's temperature is considerably lower than helium's, at only 35K while maintaining equivalent mass densities.

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Most popular questions from this chapter

In outer space the density of matter is extremely low, about one atom per \(\mathrm{cm}^{3} .\) The matter is mainly hydrogen atoms \((m=1.67 \times \mathrm{m}\) \(10^{-27} \mathrm{kg}\) ) whose rms speed is \(260 \mathrm{m} / \mathrm{s} .\) A cubical box, \(2.0 \mathrm{m}\) on a side, is placed in outer space, and the hydrogen atoms are allowed to enter. Concepts: (i) Why do hydrogen atoms exert a force on the wall of the box? (ii) Do the atoms generate a pressure on the walls of the box? (iii) Do hydrogen atoms in outer space have a temperature? If so, how is the temperature related to the microscopic properties of the atoms? Calculations: (a) What is the magnitude of the force that the atoms exert on one wall of the box? (b) Determine the pressure that the atoms exert. (c) Does outer space have a temperature and, if so, what is it?

A cubical box with each side of length \(0.300 \mathrm{m}\) contains 1.000 moles of neon gas at room temperature \((293 \mathrm{K}) .\) What is the average rate (in atoms/s) at which neon atoms collide with one side of the container? The mass of a single neon atom is \(3.35 \times 10^{-26} \mathrm{kg}\).

It takes 0.16 g of helium (He) to fill a balloon. How many grams of nitrogen \(\left(\mathrm{N}_{2}\right)\) would be required to fill the balloon to the same pressure, volume, and temperature?

A young male adult takes in about \(5.0 \times 10^{-4} \mathrm{m}^{3}\) of fresh air during a normal breath. Fresh air contains approximately \(21 \%\) oxygen. Assuming that the pressure in the lungs is \(1.0 \times 10^{5}\) Pa and that air is an ideal gas at a temperature of \(310 \mathrm{K},\) find the number of oxygen molecules in a normal breath.

The active ingredient in the allergy medication Claritin contains carbon (C), hydrogen (H), chlorine (Cl), nitrogen (N), and oxygen (O). Its molecular formula is \(\mathrm{C}_{22} \mathrm{H}_{23} \mathrm{ClN}_{2} \mathrm{O}_{2} .\) The standard adult dosage utilizes \(1.572 \times 10^{19}\) molecules of this species. Determine the mass (in grams) of the active ingredient in the standard dosage.

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