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In outer space the density of matter is extremely low, about one atom per \(\mathrm{cm}^{3} .\) The matter is mainly hydrogen atoms \((m=1.67 \times \mathrm{m}\) \(10^{-27} \mathrm{kg}\) ) whose rms speed is \(260 \mathrm{m} / \mathrm{s} .\) A cubical box, \(2.0 \mathrm{m}\) on a side, is placed in outer space, and the hydrogen atoms are allowed to enter. Concepts: (i) Why do hydrogen atoms exert a force on the wall of the box? (ii) Do the atoms generate a pressure on the walls of the box? (iii) Do hydrogen atoms in outer space have a temperature? If so, how is the temperature related to the microscopic properties of the atoms? Calculations: (a) What is the magnitude of the force that the atoms exert on one wall of the box? (b) Determine the pressure that the atoms exert. (c) Does outer space have a temperature and, if so, what is it?

Short Answer

Expert verified
Atoms exert force by momentum change; pressure is force per area; outer space temperature is about 294 K.

Step by step solution

01

Understanding why atoms exert force

Hydrogen atoms exert force on the walls of the box because they collide with the walls and change momentum. According to Newton's second law, force is related to the change in momentum over time. As atoms strike and rebound off the walls, they exert a force on the wall.
02

Pressure generation by atoms

Pressure is defined as force per unit area. Since the hydrogen atoms collide with the walls of the box, they collectively exert a force over the surface area of that wall, creating a pressure. Therefore, the atoms do generate pressure on the walls of the box.
03

Relationship between temperature and atomic properties

Hydrogen atoms in outer space do have a temperature. Temperature relates to the average kinetic energy of the particles. For gases, the temperature is related to the rms speed (root mean square speed) of the atoms and their mass through the equation: \( T = \frac{m \cdot v_{rms}^2}{3k} \), where \(T\) is temperature, \(m\) is the mass of the atoms, \(v_{rms}\) is the rms speed, and \(k\) is the Boltzmann constant.
04

Calculate the number of atoms inside the box

The box has a volume of \( 2^3 = 8 \text{ m}^3 \), which is equal to \( 8 \times 10^6 \text{ cm}^3 \). Given a density of 1 atom per \( \text{cm}^3 \), the total number of hydrogen atoms inside the box is \( 8 \times 10^6 \) atoms.
05

Force exerted by atoms on the wall

The force exerted by atoms can be found using \( F = \Delta p / \Delta t \). The change in momentum \( \Delta p = 2 m v_{rms} \) for one atom because it rebounds, because the change in direction counts as two changes (entering and exiting). Assuming the collision rate is \( N \cdot v_{rms} / (2L) \) for \( N \) atoms over the box length \( L \), we have \( F = N \cdot v_{rms} / (2L) \times 2m \cdot v_{rms} = mNv_{rms}^2 / L \). Substituting the values, \( F = 1.67 \times 10^{-27} \cdot 8 \times 10^6 \cdot (260)^2 / 2 \approx 9.03 \times 10^{-16} \text{ N} \).
06

Calculate pressure exerted by atoms

Pressure \( P \) is defined as force over area \( A \), \( P = F / A \). The area \( A \) of one wall of the cubical box is \( 4 \text{ m}^2 \). Using the previously calculated force, \( P = 9.03 \times 10^{-16} / 4 = 2.26 \times 10^{-16} \text{ N/m}^2 \).
07

Determine the temperature in outer space

The temperature \( T \) is related to the kinetic energy of the rms speed of hydrogen atoms. Using the equation \( T = \frac{m \cdot v_{rms}^2}{3k} \), where \( k = 1.38 \times 10^{-23} \text{ J/K} \), substitute values \( T = \frac{1.67 \times 10^{-27} \times 260^2}{3 \times 1.38 \times 10^{-23}} \approx 294 \text{ K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

RMS Speed
The *root mean square (RMS) speed* refers to the average speed of particles in a gas. It provides insight into how fast the gas atoms or molecules move.
The concept is rooted in kinetic theory of gases, where gases are considered as a collection of rapidly moving atoms or molecules.
- The formula for RMS speed is given by \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where:
  • \( v_{rms} \) is the RMS speed of the particles.
  • \( k \) is the Boltzmann constant \( (1.38 \times 10^{-23} \text{ J/K}) \).
  • \( T \) is the temperature in Kelvin.
  • \( m \) is the mass of a single particle.

This equation tells us that the RMS speed is influenced by both the temperature and the mass of the particles.
Higher temperatures result in higher RMS speeds since particles move faster as they gain thermal energy.
For hydrogen atoms in space, their RMS speed of 260 m/s indicates the rapid movement even in the low-density environment of outer space.
Understanding RMS speed helps in comprehending how kinetic energy translates into particle movement and, ultimately, into measurable physical phenomena such as pressure.
Atomic Pressure
In the context of gases like hydrogen in outer space, *pressure* is the result of many atoms colliding with and exerting force on a surface.
The pressure generated by these collisions is calculated using \( P = \frac{F}{A} \), where:
  • \( P \) is the pressure.
  • \( F \) is the force exerted by atoms.
  • \( A \) is the surface area upon which the force is applied.

In our example of hydrogen atoms entering a cubical box, they create pressure through their continuous collisions with the box walls.
Each collision involves a change in the momentum of the atom, which transmits an impulse and thereby exerts a force on the surface.
Despite the very low density of atoms in space, the accumulated effect of many such collisions over time results in measurable pressure, albeit a tiny one, around \( 2.26 \times 10^{-16} \text{ N/m}^2 \).
Pressure is a fundamental concept in kinetic theory because it provides a tangible link between microscopic particle dynamics and macroscopic physical measurements.
Temperature and Kinetic Energy
Temperature in the kinetic theory of gases is a measure of *the average kinetic energy* of the gas particles. It's an important link between microscopic behavior and macroscopic observations.
Kinetic energy in this context is given by \( KE = \frac{1}{2} m v^2 \), where:
  • \( m \) is the mass of an individual particle.
  • \( v \) is the velocity of the particle.

The temperature of a gas, therefore, relates directly to how energetically its particles are moving.
The relation between temperature \( T \) and RMS speed \( v_{rms} \) is written as \( T = \frac{m \cdot v_{rms}^2}{3k} \).
This equation highlights the dependence of temperature on microscopic factors like mass and velocity.
For hydrogen atoms floating freely in outer space, this relationship indicates a temperature, as calculated to be 294 K.
Thus, even in the vacuum of space, where there are few particles, each one's speed is sufficient to attribute a temperature associated with their kinetic energy.
Understanding the relationship between temperature and kinetic energy gives us insights into thermal properties of substances across different environments.

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Most popular questions from this chapter

A container holds 2.0 mol of gas. The total average kinetic energy of the gas molecules in the container is equal to the kinetic energy of an \(8.0 \times 10^{-3}-\mathrm{kg}\) bullet with a speed of \(770 \mathrm{m} / \mathrm{s}\). What is the Kelvin temperature of the gas?

A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon contains \(0.034 \mathrm{m}^{3}\) of helium at an absolute pressure of \(1.2 \times 10^{5} \mathrm{Pa} .\) The cylinder contains helium at an absolute pressure of \(1.6 \times 10^{7} \mathrm{Pa}\) and has a volume of \(0.0031 \mathrm{m}^{3} .\) The temperature of the helium in the tank and in the balloons is the same and remains constant. What is the maximum number of balloons that can be filled?

When you push down on the handle of a bicycle pump, a piston in the pump cylinder compresses the air inside the cylinder. When the pressure in the cylinder is greater than the pressure inside the inner tube to which the pump is attached, air begins to flow from the pump to the inner tube. As a biker slowly begins to push down the handle of a bicycle pump, the pressure inside the cylinder is \(1.0 \times 10^{5} \mathrm{Pa}\), and the piston in the pump is \(0.55 \mathrm{m}\) above the bottom of the cylinder. The pressure inside the inner tube is \(2.4 \times 10^{5}\) Pa. How far down must the biker push the handle before air begins to flow from the pump to the inner tube? Ignore the air in the hose connecting the pump to the inner tube, and assume that the temperature of the air in the pump cylinder does not change.

A gas fills the right portion of a horizontal cylinder whose radius is \(5.00 \mathrm{cm} .\) The initial pressure of the gas is \(1.01 \times 10^{5} \mathrm{Pa}\) A frictionless movable piston separates the gas from the left portion of the cylinder, which is evacuated and contains an ideal spring, as the drawing shows. The piston is initially held in place by a pin. The spring is initially unstrained, and the length of the gas-filled portion is \(20.0 \mathrm{cm} .\) When the pin is removed and the gas is allowed to expand, the length of the gas-filled chamber doubles. The initial and final temperatures are equal. Determine the spring constant of the spring.

Compressed air can be pumped underground into huge caverns as a form of energy storage. The volume of a cavern is \(5.6 \times 10^{5} \mathrm{m}^{3},\) and the pressure of the air in it is \(7.7 \times 10^{6}\) Pa. Assume that air is a diatomic ideal gas whose internal energy \(U\) is given by \(U=\frac{5}{2} n R T .\) If one home uses \(30.0 \mathrm{kW} \cdot \mathrm{h}\) of energy per day, how many homes could this internal energy serve for one day?

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