/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A cylindrical glass of water \(\... [FREE SOLUTION] | 91Ó°ÊÓ

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A cylindrical glass of water \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) has a radius of \(4.50 \mathrm{cm}\) and a height of \(12.0 \mathrm{cm} .\) The density of water is \(1.00 \mathrm{g} / \mathrm{cm}^{3} .\) How many moles of water molecules are contained in the glass?

Short Answer

Expert verified
There are approximately 14.1 moles of water in the glass.

Step by step solution

01

Determine Volume of the Cylinder

The volume of a cylinder can be calculated using the formula \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height. Substituting the values given, \( r = 4.5 \) cm and \( h = 12.0 \) cm, we find:\[V = \pi (4.5)^2 (12.0)\]Calculate this to find the volume of the cylinder.
02

Calculate the Mass of Water

Using the formula for volume found in Step 1 and the density of water (\(1.00 \text{ g/cm}^3\)), we can calculate the mass of water in the cylinder. The mass \( m \) is given by:\[m = V \times \text{density}\]Substitute the volume from Step 1 to find the mass of water in grams.
03

Convert Mass to Moles

To convert the mass of water to moles, we use the molar mass of water \( \text{H}_2\text{O} \), which is approximately \(18.02 \text{ g/mol}\). The number of moles \( n \) is given by:\[n = \frac{m}{\text{molar mass}}\]Substitute the mass from Step 2 and calculate the moles of water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylinder Volume Calculation
To determine the volume of a cylindrical glass of water, we need to use the formula for the volume of a cylinder. This formula is:\[ V = \pi r^2 h \]where:
  • \( V \) is the volume.
  • \( r \) is the radius of the base.
  • \( h \) is the height of the cylinder.
In this exercise, the glass of water has a radius \( r = 4.50 \text{ cm} \) and a height \( h = 12.0 \text{ cm} \). Substituting these values into the formula gives:\[ V = \pi (4.5)^2 (12.0) \]First, square the radius: \( (4.5)^2 = 20.25 \). Then multiply by the height \( 12.0 \):\[ 20.25 \times 12.0 = 243.0 \]Finally, multiply this by \( \pi \):\[ V = 243.0 \times \pi \approx 763.407 \text{ cm}^3 \]Thus, the volume of the cylinder is approximately \( 763.407 \text{ cm}^3 \).
Density of Water
Density is an important concept in physics and chemistry because it relates the mass of a substance to its volume. For water, the density is typically given as \( 1.00 \text{ g/cm}^3 \). This means each cubic centimeter of water has a mass of 1 gram.To find the mass of water in the glass, we use the volume calculated earlier. The formula to find mass from volume and density is:\[ m = V \times \text{density} \]Substitute the previously calculated volume \( V \approx 763.407 \text{ cm}^3 \) into the formula:\[ m = 763.407 \times 1.00 = 763.407 \text{ g} \]Therefore, the mass of water in the glass is approximately \( 763.407 \text{ g} \). This step is crucial because it provides the mass needed to convert to moles.
Mass to Moles Conversion
Converting mass to moles is a common calculation in chemistry that allows us to understand how many particles, such as molecules, are present in a given mass. With water, this involves using the molar mass. The number of moles \( n \) can be found by dividing the mass \( m \) by the molar mass \( M \):\[ n = \frac{m}{M} \]In this case, the mass \( m \) of the water is approximately \( 763.407 \text{ g} \), as calculated previously. The molar mass of water is \( 18.02 \text{ g/mol} \).Substitute the values into the equation:\[ n = \frac{763.407}{18.02} \approx 42.38 \text{ moles} \]Hence, the glass contains approximately \( 42.38 \text{ moles} \) of water. This tells us the amount of water molecules in the glass, using Avogadro’s number for conversions to the actual number of molecules later.
Molar Mass of Water
Understanding molar mass is crucial in chemistry, as it enables the transition from a macroscopic scale to a microscopic scale by linking grams to moles. For water (\( \text{H}_2\text{O} \)), the molar mass is derived from the atomic masses of hydrogen and oxygen.Water consists of two hydrogen atoms and one oxygen atom. The atomic mass of hydrogen is approximately \( 1.01 \text{ g/mol} \), and for oxygen, it's about \( 16.00 \text{ g/mol} \). Therefore, the molar mass \( M \) of water is calculated as follows:\[ M = (2 \times 1.01) + 16.00 = 18.02 \text{ g/mol} \]This means that one mole of water weighs \( 18.02 \text{ g} \), an essential piece of information when calculating moles from given mass. This molar mass allows us to relate the mass of a sample to the number of molecules it contains through conversions with Avogadro's number.

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Most popular questions from this chapter

A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon contains \(0.034 \mathrm{m}^{3}\) of helium at an absolute pressure of \(1.2 \times 10^{5} \mathrm{Pa} .\) The cylinder contains helium at an absolute pressure of \(1.6 \times 10^{7} \mathrm{Pa}\) and has a volume of \(0.0031 \mathrm{m}^{3} .\) The temperature of the helium in the tank and in the balloons is the same and remains constant. What is the maximum number of balloons that can be filled?

The active ingredient in the allergy medication Claritin contains carbon (C), hydrogen (H), chlorine (Cl), nitrogen (N), and oxygen (O). Its molecular formula is \(\mathrm{C}_{22} \mathrm{H}_{23} \mathrm{ClN}_{2} \mathrm{O}_{2} .\) The standard adult dosage utilizes \(1.572 \times 10^{19}\) molecules of this species. Determine the mass (in grams) of the active ingredient in the standard dosage.

Two ideal gases have the same mass density and the same absolute pressure. One of the gases is helium (He), and its temperature is \(175 \mathrm{K}\). The other gas is neon (Ne). What is the temperature of the neon?

You and your team have been given the task of preparing a gas piston device that is to be deployed to the bottom of the Southern Sea, beneath the Brunt Ice Shelf off the coast of Antarctica. The inner volume of the cylinder has a diameter of \(9.00 \mathrm{cm}\) and a length of \(25.0 \mathrm{cm},\) and is fitted with a movable piston that compresses the argon (Ar) gas that it contains. Before deployment, the piston is located and held at the very top of the cylinder, providing the maximum volume for the gas. When the device is submerged, however, the piston will move inward due to the water pressure created by the depth, and the change in temperature of the gas. The device is to be taken to a depth of \(350 \mathrm{m}\) in salt water (density \(\rho=1.03\) \(\left.\mathrm{g} / \mathrm{cm}^{3}\right)\) at a temperature of \(33.0^{\circ} \mathrm{F} .\) If the maximum allowable compression distance of the piston is \(13.0 \mathrm{cm},\) what is the minimum gas pressure that must be attained when the device is filled at the surface (at atmospheric pressure and \(T=59.0^{\circ} \mathrm{F}\) ) to prevent the maximum displacement of the piston from exceeding its maximum ( \(13.0 \mathrm{cm}\) ) when submerged to a depth of \(350 \mathrm{m} ?\)

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