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(a) Objects A and B have the same mass of \(3.0 \mathrm{kg}\). They melt when \(3.0 \times 10^{4} \mathrm{J}\) of heat is added to object \(\mathrm{A}\) and when \(9.0 \times 10^{4} \mathrm{J}\) is added to object B. Determine the latent heat of fusion for the substance from which each object is made. (b) Find the heat required to melt object A when its mass is \(6.0 \mathrm{kg}\).

Short Answer

Expert verified
The latent heat of fusion is 10,000 J/kg for A and 30,000 J/kg for B. To melt 6.0 kg of A, 60,000 J is required.

Step by step solution

01

Understanding Latent Heat of Fusion

The latent heat of fusion is the amount of heat required to change a solid into a liquid without changing its temperature. It can be calculated using the formula: \( L = \frac{Q}{m} \) where \( Q \) is the heat added and \( m \) is the mass of the object.
02

Calculate Latent Heat for Object A

For Object A with a mass of \(3.0 \text{ kg}\) and heat added \(3.0 \times 10^{4} \text{ J}\), the latent heat of fusion is calculated as: \[ L_A = \frac{3.0 \times 10^{4} \text{ J}}{3.0 \text{ kg}} = 10^{4} \text{ J/kg} \]
03

Calculate Latent Heat for Object B

For Object B with the same mass \(3.0 \text{ kg}\) and heat added \(9.0 \times 10^{4} \text{ J}\), the latent heat of fusion is: \[ L_B = \frac{9.0 \times 10^{4} \text{ J}}{3.0 \text{ kg}} = 3 \times 10^{4} \text{ J/kg} \]
04

Understanding the Heat Required for a Different Mass

The heat required to melt an object with a different mass, keeping the substance's latent heat constant, can be found using the formula: \( Q = L \times m \).
05

Calculate Heat for Melting 6.0 kg of Object A

Given \( m = 6.0 \text{ kg} \) and \( L_A = 10^{4} \text{ J/kg} \), the heat required to melt the new mass is: \[ Q_A = 10^{4} \text{ J/kg} \times 6.0 \text{ kg} = 6.0 \times 10^{4} \text{ J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is the process of energy being moved from one body or system to another. It occurs due to a temperature difference between the two objects or systems. In the case of melting ice or any transition involving phase changes, the energy transfer manifests as the substance reaching its latent heat of fusion. This transfer is crucial for understanding how materials behave when heated.
Heat can transfer via three main methods:
  • Conduction: Direct transfer through a substance when molecules or atoms collide.
  • Convection: Involves the movement of fluid masses. Heat carried by the fluid moves from one location to another.
  • Radiation: Transfer of energy through electromagnetic waves, without the need for a medium.
In our exercise, heat is transferred to both objects to cause a phase change from solid to liquid. It's essential to note that during the phase change, even as heat continues to transfer into the substance, its temperature remains constant until the change is complete.
Specific Heat
Specific heat is an important concept that refers to the amount of heat per unit mass required to raise the temperature of a substance by one degree Celsius. It tells us how resistant a material is to changing its temperature.

In formulas, specific heat is represented as:\[Q = mc\Delta T\]where:
  • \(Q\) is the heat energy added.
  • \(m\) is the mass.
  • \(c\) is the specific heat capacity.
  • \(\Delta T\) is the change in temperature.
For the objects in our problem, the specific heat is not directly involved since we are dealing with the latent heat of fusion. However, it’s crucial to understand that specific heat comes into play before and after the phase change, when the temperature of the material changes. The use of latent heat addresses the heat added with no change in temperature, unlike specific heat, which sees temperature change.
Phase Change
A phase change refers to the transition of a substance from one state of matter to another, such as from solid to liquid, liquid to gas, etc. This change involves energy or heat but does not affect the temperature until the transition is complete.
When melting, the energy added to a substance is absorbed without a rise in temperature, and this amount of heat is what we refer to as the latent heat of fusion. The key processes in phase changes are:
  • Freezing: Liquid to solid.
  • Melting: Solid to liquid. In our example, Object A and B are experiencing melting.
  • Vaporization: Liquid to gas.
  • Condensation: Gas to liquid.
  • Sublimation: Solid to gas.
  • Deposition: Gas to solid.
Understanding phase changes helps us grasp why energy is needed to transition between states. This is critical in the context of latent heat, as it explains why different materials require different amounts of energy for the same phase change.

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Most popular questions from this chapter

At the bottom of an old mercury-in-glass thermometer is a \(45-\mathrm{mm}^{3}\) reservoir filled with mercury. When the thermometer was placed under your tongue, the warmed mercury would expand into a very narrow cylindrical channel, called a capillary, whose radius was \(1.7 \times 10^{-2} \mathrm{mm}\). Marks were placed along the capillary that indicated the temperature. Ignore the thermal expansion of the glass and determine how far (in \(\mathrm{mm}\) ) the mercury would expand into the capillary when the temperature changed by \(1.0 \mathrm{C}^{\circ}\)

Water at \(23.0^{\circ} \mathrm{C}\) is sprayed onto \(0.180 \mathrm{kg}\) of molten gold at \(1063^{\circ} \mathrm{C}\) (its melting point). The water boils away, forming steam at \(100.0^{\circ} \mathrm{C}\) and leaving solid gold at \(1063^{\circ} \mathrm{C} .\) What is the minimum mass of water that must be used?

One rod is made from lead and another from quartz. The rods are heated and experience the same change in temperature. The change in length of each rod is the same. If the initial length of the lead rod is \(0.10 \mathrm{m},\) what is the initial length of the quartz rod?

Occasionally, huge icebergs are found floating on the ocean's currents. Suppose one such iceberg is \(120 \mathrm{km}\) long, \(35 \mathrm{km}\) wide, and \(230 \mathrm{m}\) thick. (a) How much heat would be required to melt this iceberg (assumed to be at \(0^{\circ} \mathrm{C}\) ) into liquid water at \(0^{\circ} \mathrm{C}\) ? The density of ice is \(917 \mathrm{kg} / \mathrm{m}^{3}\). (b) The annual energy consumption by the United States is about \(1.1 \times 10^{20}\) J. If this energy were delivered to the iceberg every year, how many years would it take before the ice melted?

The latent heat of vaporization of \(\mathrm{H}_{2} \mathrm{O}\) at body temperature \(\left(37.0^{\circ} \mathrm{C}\right)\) is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} .\) To cool the body of a \(75-\mathrm{kg}\) jogger [average specific heat capacity \(\left.=3500 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right)\right]\) by \(1.5 \mathrm{C}^{\circ},\) how many kilograms of water in the form of sweat have to be evaporated?

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