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At the bottom of an old mercury-in-glass thermometer is a \(45-\mathrm{mm}^{3}\) reservoir filled with mercury. When the thermometer was placed under your tongue, the warmed mercury would expand into a very narrow cylindrical channel, called a capillary, whose radius was \(1.7 \times 10^{-2} \mathrm{mm}\). Marks were placed along the capillary that indicated the temperature. Ignore the thermal expansion of the glass and determine how far (in \(\mathrm{mm}\) ) the mercury would expand into the capillary when the temperature changed by \(1.0 \mathrm{C}^{\circ}\)

Short Answer

Expert verified
The mercury expands approximately 90.57 mm into the capillary.

Step by step solution

01

Determine the Mercury Volume Expansion Coefficient

Mercury has a volume expansion coefficient, denoted as \( \beta \), which is approximately \( 1.82 \times 10^{-4} \, \text{per} \, ^\circ \text{C} \). This coefficient describes how much the volume of mercury expands per degree Celsius change in temperature.
02

Calculate Change in Mercury Volume

The change in volume, \( \Delta V \), of mercury can be calculated using its initial volume and the volume expansion equation:\[ \Delta V = \beta \times V_0 \times \Delta T \]Where \( V_0 = 45 \, \text{mm}^3 \) is the initial volume of the mercury, \( \Delta T = 1.0 \, ^\circ \text{C} \) is the temperature change, and \( \beta = 1.82 \times 10^{-4} \, \text{per} \, ^\circ \text{C} \). Substituting in these values:\[ \Delta V = 1.82 \times 10^{-4} \times 45 \times 1.0 = 0.00819 \, \text{mm}^3 \].
03

Calculate the Capillary Length Expansion

Given the cylindrical shape of the capillary channel, the length \( L \) that the mercury expands into can be calculated using the formula for the volume of a cylinder:\[ \Delta V = \pi r^2 L \]Solving for \( L \):\[ L = \frac{\Delta V}{\pi r^2} \]Where \( r = 1.7 \times 10^{-2} \, \text{mm} \). Substitute \( \Delta V = 0.00819 \, \text{mm}^3 \) and \( r \):\[ L = \frac{0.00819}{\pi (1.7 \times 10^{-2})^2} \approx 90.57 \, \text{mm} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume Expansion Coefficient
The volume expansion coefficient is an important concept when discussing materials that expand due to heat. In the context of a mercury thermometer, it refers to how the volume of mercury changes with temperature variations. This coefficient is denoted as \( \beta \) and describes how much a given volume of a substance will expand per degree Celsius increase in temperature. For mercury, this coefficient is approximately \( 1.82 \times 10^{-4} \text{ per } ^\circ \text{C} \).

This means if you have an amount of mercury, and you change its temperature by 1 degree Celsius, the volume will increase by a fraction calculated using \( \beta \). Knowing this value allows us to predict how the volume of mercury in a thermometer will expand, giving us a useful way to measure temperature changes.
Mercury Thermometer
A mercury thermometer consists of a glass tube that holds mercury, a liquid metal. Mercury was traditionally used in thermometers because it expands uniformly with temperature changes, making it an accurate medium for measuring temperature shifts.

Here's how it works:
  • The reservoir at the bottom holds a specific volume of mercury.
  • The capillary tube allows the expanded mercury to rise, where marked lines indicate temperature.
When the thermometer is exposed to heat, such as placed under the tongue, the mercury expands, moving up the capillary tube. This movement corresponds to a precise temperature reading, thanks to the volume expansion properties.
Cylindrical Capillary
The cylindrical capillary is a crucial part of a mercury thermometer. It is the thin, hollow tube through which the mercury rises as it expands. The shape and size of the capillary influence the sensitivity and accuracy of the temperature measurement.

In the context of thermal expansion, the expansion of the mercury for a temperature rise pushes it up this narrow channel. Each temperature change results in a specific amount of volume expansion, which is then translated into a distance the mercury rises in the tube. The radius of the capillary, in this case, is small at \( 1.7 \times 10^{-2} \) mm, amplifying even minute expansions in volume to measurable lengths.
Temperature Change
Temperature change refers to the increase or decrease in thermal energy within a material. In a mercury thermometer, this is the change that causes the mercury to expand and rise within the capillary tube.

An important part of this concept is how materials respond to these changes. For the thermometer:
  • A rise in temperature increases thermal energy, causing mercury to expand.
  • This expansion results in a measurable movement along the thermometer’s scale.
Understanding the relationship between temperature change and thermal expansion helps explain why the mercury moves within the thermometer and how this movement correlates with temperature readings.

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Most popular questions from this chapter

Water at \(23.0^{\circ} \mathrm{C}\) is sprayed onto \(0.180 \mathrm{kg}\) of molten gold at \(1063^{\circ} \mathrm{C}\) (its melting point). The water boils away, forming steam at \(100.0^{\circ} \mathrm{C}\) and leaving solid gold at \(1063^{\circ} \mathrm{C} .\) What is the minimum mass of water that must be used?

A piece of glass has a temperature of \(83.0^{\circ} \mathrm{C} .\) Liquid that has a temperature of \(43.0^{\circ} \mathrm{C}\) is poured over the glass, completely covering it, and the temperature at equilibrium is \(53.0^{\circ} \mathrm{C} .\) The mass of the glass and the liquid is the same. Ignoring the container that holds the glass and liquid and assuming that the heat lost to or gained from the surroundings is negligible, determine the specific heat capacity of the liquid.

Two bars of identical mass are at \(25^{\circ} \mathrm{C}\). One is made from glass and the other from another substance. The specific heat capacity of glass is \(840 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right) .\) When identical amounts of heat are supplied to each, the glass bar reaches a temperature of \(88^{\circ} \mathrm{C},\) while the other bar reaches \(250.0^{\circ} \mathrm{C}\). What is the specific heat capacity of the other substance?

An unknown material has a normal melting/freezing point of \(-25.0^{\circ} \mathrm{C},\) and the liquid phase has a specific heat capacity of \(160 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right)\) One-tenth of a kilogram of the solid at \(-25.0{ }^{\circ} \mathrm{C}\) is put into a \(0.150-\mathrm{kg}\) aluminum calorimeter cup that contains \(0.100 \mathrm{kg}\) of glycerin. The temperature of the cup and the glycerin is initially \(27.0^{\circ} \mathrm{C} .\) All the unknown material melts, and the final temperature at equilibrium is \(20.0^{\circ} \mathrm{C} .\) The calorimeter neither loses energy to nor gains energy from the external environment. What is the latent heat of fusion of the unknown material?

The vapor pressure of water at \(10^{\circ} \mathrm{C}\) is \(1300 \mathrm{Pa}\). (a) What percentage of atmospheric pressure is this? Take atmospheric pressure to be \(1.013 \times 10^{5}\) Pa. (b) What percentage of the total air pressure at \(10^{\circ} \mathrm{C}\) is due to water vapor when the relative humidity is \(100 \% ?\) (c) The vapor pressure of water at \(35^{\circ} \mathrm{C}\) is 5500 Pa. What is the relative humidity at this temperature if the partial pressure of water in the air has not changed from what it was at \(10^{\circ} \mathrm{C}\) when the relative humidity was \(100 \% ?\)

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