/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 During an all-night cram session... [FREE SOLUTION] | 91Ó°ÊÓ

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During an all-night cram session, a student heats up a one-half liter \(\left(0.50 \times 10^{-3} \mathrm{m}^{3}\right)\) glass (Pyrex) beaker of cold coffee. Initially, the temperature is \(18^{\circ} \mathrm{C},\) and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to \(92^{\circ} \mathrm{C} .\) The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

Short Answer

Expert verified
7.77 × 10^{-6} m^3 of coffee spills out.

Step by step solution

01

Understand the Problem

We need to calculate how much coffee spills out of the beaker when its temperature is increased from 18\(^{ ext{o}}\)C to 92\(^{ ext{o}}\)C. The beaker is initially full, so any volume expansion of the coffee will result in spillage.
02

Identify Given Values

The initial volume of the coffee is \(V_0 = 0.50 \times 10^{-3} \: \text{m}^3\). We know the temperature change \(\Delta T = 92^{ ext{o}}\text{C} - 18^{ ext{o}}\text{C} = 74^{ ext{o}}\text{C}\). The coefficient of volume expansion of water, used for coffee, is approximately \(\beta \approx 210 \times 10^{-6} \: \text{°C}^{-1}\).
03

Use the Volume Expansion Formula

The formula for volume expansion due to temperature change is \(\Delta V = \beta V_0 \Delta T\). Here, \(\Delta V\) is the change in volume of the coffee, which equals the volume of coffee that spills out.
04

Substitute the Known Values

Substitute \(\beta = 210 \times 10^{-6} \: \text{°C}^{-1}\), \(V_0 = 0.50 \times 10^{-3} \: \text{m}^3\), and \(\Delta T = 74^{ ext{o}}\text{C}\) into the formula: \[ \Delta V = 210 \times 10^{-6} \times 0.50 \times 10^{-3} \times 74 \].
05

Calculate the Volume of Spilled Coffee

Calculate the result: \[ \Delta V = 210 \times 10^{-6} \times 0.50 \times 10^{-3} \times 74 = 7.77 \times 10^{-6} \: \text{m}^3\]. This is the volume of coffee that spills out.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume Expansion Formula
When a fluid is heated or cooled, its volume tends to change. This phenomenon is known as thermal expansion. Fluids like coffee expand when heated, which can cause overflow if the container is not able to hold the increased volume. To determine how much a fluid expands due to temperature changes, we use the volume expansion formula.

This formula is expressed as \( \Delta V = \beta V_0 \Delta T \), where:
  • \( \Delta V \) is the change in volume. It represents how much the fluid's volume increases.
  • \( V_0 \) is the initial volume of the fluid. It's where we start when calculating how much more space the fluid will take up.
  • \( \beta \) is the coefficient of volume expansion, specific to each fluid.
  • \( \Delta T \) is the change in temperature, calculated by subtracting the initial temperature from the final temperature.

Understanding this formula allows us to predict how much a fluid will expand when the temperature changes. Using this knowledge can prevent us from making a mess when heating fluids in containers like a coffee beaker.
Coefficient of Volume Expansion
The coefficient of volume expansion \( \beta \) is a crucial factor that tells us how much a material or fluid will expand or contract when its temperature changes. It is usually expressed in \( \text{°C}^{-1} \). For fluids like water (or coffee, which has a similar expansion behavior), \( \beta \) is typically around \( 210 \times 10^{-6} \text{°C}^{-1} \). This small number indicates that for each degree Celsius the temperature changes, the fluid's volume changes by a very tiny fraction.

Each substance has a unique \( \beta \). This means some substances expand more than others for the same temperature change. For liquids, knowing the \( \beta \) helps predict spillage when heated, as was seen in our coffee example.

This value is important for engineers and scientists who work with different fluids and materials, especially in designing containers and systems that need to handle temperature fluctuations without spilling or worse, failing altogether.
Temperature Change in Fluids
In the discussion of thermodynamics and thermal expansion, temperature change \( \Delta T \) plays a pivotal role. Temperature change affects how substances expand or contract. It is the difference between the initial temperature and the final temperature of the fluid.
  • In our exercise, the initial temperature of coffee was 18°C and the final temperature was 92°C. The temperature change \( \Delta T \) is calculated as 92°C - 18°C, which equals 74°C.

This change signifies how much the thermal energy within the fluid has increased.

Understanding \( \Delta T \) is necessary to foresee the potential expansion of any fluid. More significant temperature changes generally lead to greater volume changes. This knowledge is used in various applications, from culinary practices to large scale industrial processes, ensuring safety and efficiency are maintained.

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Most popular questions from this chapter

A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 240 Calories ( 1 Calorie \(=4186\) J). What mass of perspiration would one have to lose to get rid of this energy? At body temperature, the latent heat of vaporization of water is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} .\)

When the temperature of a coin is raised by \(75 \mathrm{C}^{\circ},\) the coin's diameter increases by \(2.3 \times 10^{-5} \mathrm{m} .\) If the original diameter of the coin is \(1.8 \times 10^{-2} \mathrm{m},\) find the coefficient of linear expansion.

A 42 -kg block of ice at \(0^{\circ} \mathrm{C}\) is sliding on a horizontal surface. The initial speed of the ice is \(7.3 \mathrm{m} / \mathrm{s}\) and the final speed is \(3.5 \mathrm{m} / \mathrm{s} .\) Assume that the part of the block that melts has a very small mass and that all the heat generated by kinetic friction goes into the block of ice. Determine the mass of ice that melts into water at \(0^{\circ} \mathrm{C}\).

On the moon the surface temperature ranges from \(375 \mathrm{K}\) during the day to \(1.00 \times 10^{2} \mathrm{K}\) at night. What are these temperatures on the (a) Celsius and (b) Fahrenheit scales?

A thick, vertical iron pipe has an inner diameter of \(0.065 \mathrm{m}\). A thin aluminum disk, heated to a temperature of \(85^{\circ} \mathrm{C},\) has a diameter that is \(3.9 \times 10^{-5} \mathrm{m}\) greater than the pipe's inner diameter. The disk is laid on top of the open upper end of the pipe, perfectly centered on it, and allowed to cool. What is the temperature of the aluminum disk when the disk falls into the pipe? Ignore the temperature change of the pipe.

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