/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 A 42 -kg block of ice at \(0^{\c... [FREE SOLUTION] | 91Ó°ÊÓ

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A 42 -kg block of ice at \(0^{\circ} \mathrm{C}\) is sliding on a horizontal surface. The initial speed of the ice is \(7.3 \mathrm{m} / \mathrm{s}\) and the final speed is \(3.5 \mathrm{m} / \mathrm{s} .\) Assume that the part of the block that melts has a very small mass and that all the heat generated by kinetic friction goes into the block of ice. Determine the mass of ice that melts into water at \(0^{\circ} \mathrm{C}\).

Short Answer

Expert verified
Approximately 0.00258 kg, or 2.58 grams, of ice melts.

Step by step solution

01

Calculate Initial Kinetic Energy

The initial kinetic energy (KE) of the ice block can be found using the formula:\[ KE_{initial} = \frac{1}{2} m v_{initial}^2 \]where \(m = 42 \text{ kg}\) and \(v_{initial} = 7.3 \text{ m/s}\). Substituting these values:\[ KE_{initial} = \frac{1}{2} \times 42 \times (7.3)^2 \approx 1,118.07 \text{ J}\]
02

Calculate Final Kinetic Energy

The final kinetic energy of the ice block can be calculated using the formula:\[ KE_{final} = \frac{1}{2} m v_{final}^2 \]where \(v_{final} = 3.5 \text{ m/s}\). Substituting the known values:\[ KE_{final} = \frac{1}{2} \times 42 \times (3.5)^2 \approx 257.25 \text{ J}\]
03

Calculate Kinetic Energy Lost

The kinetic energy lost during the slowing down of the ice block is the difference between the initial and final kinetic energies:\[ KE_{lost} = KE_{initial} - KE_{final} \]Substituting values from previous steps:\[ KE_{lost} = 1,118.07 \text{ J} - 257.25 \text{ J} = 860.82 \text{ J}\]
04

Calculate Heat Required to Melt Ice

The heat required to melt a mass \(m_{ice}\) of ice into water at \(0^{\circ} \text{C}\) can be determined using the equation:\[ Q = m_{ice} L_f \]where \(L_f = 334,000 \text{ J/kg}\) is the latent heat of fusion for ice. Given that all lost kinetic energy converts into heat:\[ 860.82 \text{ J} = m_{ice} \times 334,000 \text{ J/kg} \]
05

Solve for Mass of Ice that Melts

Rearrange the equation from the previous step to solve for \(m_{ice}\):\[ m_{ice} = \frac{860.82}{334,000} \approx 0.00258 \text{ kg}\]
06

Conclusion

The mass of ice that melts into water at \(0^{\circ} \text{C}\) is approximately \(0.00258 \text{ kg}\), or 2.58 grams. This shows how kinetic energy transforms into thermal energy, causing a small fraction of the ice to melt.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. In the case of our sliding ice block, the kinetic energy comes from the block's mass and velocity. When an object is in motion, its kinetic energy can be calculated using the formula:\[ KE = \frac{1}{2} m v^2 \]where \(m\) is the mass of the object and \(v\) is its velocity. This equation tells us that kinetic energy is dependent on both the mass of the object and the square of its velocity. This means that a small increase in speed can cause a significant increase in kinetic energy.
Consider the ice block example: Initially, it moves with a velocity of \(7.3 \, \text{m/s}\), giving it significant energy. As it slows to \(3.5 \, \text{m/s}\), its kinetic energy decreases. This lost energy does not vanish; it converts into other forms, such as heat, which plays a crucial role in the melting process of ice.
Latent Heat of Fusion
Latent heat of fusion is the heat energy required to change a unit mass of a substance from solid to liquid without changing its temperature. For ice, this value is defined as \(334,000 \, \text{J/kg}\).This value is exceptionally high, which means a significant amount of energy is needed to melt ice, despite the temperature staying constant at \(0^\circ \text{C}\). In our exercise, when the kinetic energy of the ice block is converted to heat, it facilitates the melting of a portion of the ice. The equation we use is:\[ Q = m_{ice} \, L_f \]where \(Q\) is the heat energy absorbed (from the lost kinetic energy), \(m_{ice}\) is the mass of the ice to melt, and \(L_f\) is the latent heat of fusion. By rearranging the equation to solve for \(m_{ice}\), we can find how much of the ice melts based on the energy available.
Melting of Ice
Melting of ice is a phase change where ice (solid) transforms into water (liquid) without a change in temperature. This process occurs at a constant temperature of \(0^\circ \text{C}\) because the energy is used in breaking the bonds between water molecules within the ice to form liquid water.Here's how it applies in our ice block exercise:
  • As the ice block slows down, it loses kinetic energy.
  • This lost energy is converted into heat which contributes to the melting process.
  • The latent heat of fusion quantifies exactly how much energy is required to convert a certain mass of ice into water, with no temperature change.

Therefore, even a slight reduction in the speed of the ice block can release enough energy to melt a small amount of ice, as seen in the precise calculations given. Understanding the melting process helps underline the broader principle that energy, while transferring from one form to another, is conserved throughout physical processes.

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Most popular questions from this chapter

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