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A clay vase on a potter's wheel expericnces an angular acceleration of \(8.00 \mathrm{rad} / \mathrm{s}^{2}\) due to the application of a \(10.0-\mathrm{N} \cdot \mathrm{m}\) net torque. Find the total moment of inertia of the vase and potter's wheel.

Short Answer

Expert verified
The moment of inertia is 1.25 kg·m².

Step by step solution

01

Understanding the Definitions

The moment of inertia, denoted as \( I \), is the quantity to be found, representing the resistance to rotation. Given the net torque (\( \tau \)) of 10.0 N·m and the angular acceleration (\( \alpha \)) of 8.00 rad/s², we need to utilize the relationship between these quantities.
02

Recall the Formula for Torque

The formula that connects torque \( \tau \), moment of inertia \( I \), and angular acceleration \( \alpha \) is:\[\tau = I \alpha\]
03

Solve for the Moment of Inertia

Rearrange the formula to solve for the moment of inertia \( I \):\[I = \frac{\tau}{\alpha}\]Substitute the given values (\( \tau = 10.0 \) N·m and \( \alpha = 8.00 \) rad/s²) into the formula:\[I = \frac{10.0}{8.00} = 1.25 \text{ kg·m²}\]
04

Interpretation of Result

The total moment of inertia of the vase and potter's wheel is 1.25 kg·m². This means it resists changes in its rotational motion with this quantity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is a fundamental concept when studying rotational motion. It measures how quickly an object's rotational speed changes over time, akin to how linear acceleration measures the change in speed for objects moving in a straight line. Angular acceleration is typically denoted by the symbol \(\alpha\) and is measured in radians per second squared (rad/s²).

The formula \[ \tau = I \alpha \] where \(\tau\) is torque and \(I\) is the moment of inertia, directly relates angular acceleration to these other important concepts. In this equation:
  • \(\tau\) is the torque applied to the system.
  • \(I\) is the moment of inertia, representing how much the object resists changes in its rotational motion.
  • \(\alpha\) is the angular acceleration.
By rearranging this equation to \( \alpha = \frac{\tau}{I} \), you can see that an increase in torque leads to a higher angular acceleration, provided the moment of inertia remains constant.
Torque
Torque is a measure of the rotational force applied to an object. It plays a crucial role in rotational motion, similar to how force affects linear motion. Torque is often denoted by the symbol \(\tau\) and is measured in Newton-meters (N·m). This measurement comes from multiplying the force applied by the distance from the pivot point at which it is applied.

To understand torque intuitively, imagine trying to open a door. If you push near the hinge, you must push harder to open it, while pushing at the edge requires less effort. This is because torque depends on both the force applied and the lever arm distance.

The formula for torque is:\[ \tau = r \times F \]where:
  • \(r\) is the lever arm, the distance from the pivot point to where the force is applied.
  • \(F\) is the force applied.
This principle is essential in understanding how forces cause objects to rotate, and it helps to determine the moment of inertia as well as angular acceleration.
Rotational Motion
Rotational motion refers to the movement of an object around a central point or axis. It's a fundamental concept in physics that describes how objects spin, turn, or rotate. This kind of motion can be observed in everyday situations, like a spinning top or a ceiling fan.

There are several key terms associated with rotational motion to understand fully how it works:
  • Rotational velocity: Indicates how fast an object rotates, measured in radians per second (rad/s).
  • Angular acceleration: Shows how quickly the rotational velocity of an object changes.
  • Moment of inertia: Represents the object's resistance to changes in its rotational state, much like mass in linear motion.
  • Torque: The force causing the rotation.
Rotational motion differs from linear motion in that all points in the rotating body maintain a fixed position relative to each other. Understanding these concepts is crucial when analyzing how the rotational forces and movements affect objects and systems in physics.

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Most popular questions from this chapter

One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has a length of \(0.80 \mathrm{m}\) and is uniform. It is hanging vertically straight downward. The end of the rod nearest the floor is given a linear speed \(v_{0,}\) so that the rod begins to rotate upward about the pivot. What must be the value of \(v_{0}\) such that the rod comes to a momentary halt in a straight-up orientation, exactly opposite to its initial orientation?

As seen from above, a playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the ground grabs onto one of the bars on the carousel very close to its outer edge and climbs aboard. Thus, this person begins with an angular speed of zero and ends up with a nonzero angular speed, which means that he underwent a counterclockwise angular acceleration. The carousel has a radius of \(1.50 \mathrm{m},\) an initial angular speed of \(3.14 \mathrm{rad} / \mathrm{s},\) and a moment of inertia of \(125 \mathrm{kg} \cdot \mathrm{m}^{2} .\) The mass of the person is \(40.0 \mathrm{kg} .\) Find the final angular speed of the carousel after the person climbs aboard.

Two disks are rotating about the same axis. Disk A has a moment of inertia of \(3.4 \mathrm{kg} \cdot \mathrm{m}^{2}\) and an angular velocity of \(+7.2 \mathrm{rad} / \mathrm{s} .\) Disk \(\mathrm{B}\) is rotating with an angular velocity of \(-9.8 \mathrm{rad} / \mathrm{s}\). The two disks are then linked together without the aid of any external torques, so that they rotate as a single unit with an angular velocity of \(-2.4 \mathrm{rad} / \mathrm{s}\). The axis of rotation for this unit is the same as that for the separate disks. What is the moment of inertia of disk B?

A uniform board is leaning against a smooth vertical wall. The board is at an angle \(\theta\) above the horizontal ground. The coefficient of static friction between the ground and the lower end of the board is 0.650 . Find the smallest value for the angle \(\theta\), such that the lower end of the board does not slide along the ground.

Conceptual Example 13 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of \(125 \mathrm{kg} \cdot \mathrm{m}^{2}\). When one person is standing on the carousel at a distance of \(1.50 \mathrm{m}\) from the center, the carousel has an angular velocity of 0.600 rad/s. However, as this person moves inward to a point located \(0.750 \mathrm{m}\) from the center, the angular velocity increases to \(0.800 \mathrm{rad} / \mathrm{s} .\) What is the person's mass?

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