/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Two disks are rotating about the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two disks are rotating about the same axis. Disk A has a moment of inertia of \(3.4 \mathrm{kg} \cdot \mathrm{m}^{2}\) and an angular velocity of \(+7.2 \mathrm{rad} / \mathrm{s} .\) Disk \(\mathrm{B}\) is rotating with an angular velocity of \(-9.8 \mathrm{rad} / \mathrm{s}\). The two disks are then linked together without the aid of any external torques, so that they rotate as a single unit with an angular velocity of \(-2.4 \mathrm{rad} / \mathrm{s}\). The axis of rotation for this unit is the same as that for the separate disks. What is the moment of inertia of disk B?

Short Answer

Expert verified
The moment of inertia of disk B is \(4.41 \, \text{kg} \cdot \text{m}^2\).

Step by step solution

01

Identify Known Values

We know the moment of inertia of disk A, \(I_A = 3.4 \, \text{kg} \cdot \text{m}^2\). The angular velocities before linking are \(\omega_A = +7.2 \, \text{rad/s}\) for disk A and \(\omega_B = -9.8 \, \text{rad/s}\) for disk B. After linking, the combined angular velocity is \(\omega_f = -2.4 \, \text{rad/s}\).
02

Apply Conservation of Angular Momentum

When no external torque acts on a system, the total angular momentum before and after an event remains constant. For this system, the angular momentum before linking must equal the angular momentum after linking. This can be expressed by the equation: \(I_A \omega_A + I_B \omega_B = (I_A + I_B) \omega_f\).
03

Substitute Known Values and Solve for \(I_B\)

Insert the known values into the conservation equation: \(3.4 \times 7.2 + I_B(-9.8) = (3.4 + I_B)(-2.4)\). Simplify and solve this equation for \(I_B\).
04

Simplify the Equation

Simplify \(3.4 \times 7.2 = 24.48\). Substitute this into the equation: \[24.48 - 9.8I_B = -8.16 - 2.4I_B\]. Then, gather all terms with \(I_B\) on one side and constant terms on the other.
05

Solve for \(I_B\)

Re-arrange the equation to \(24.48 + 8.16 = 9.8I_B - 2.4I_B\) which leads to \(32.64 = 7.4I_B\). Solve for \(I_B\) by dividing both sides by 7.4: \(I_B = \frac{32.64}{7.4} = 4.41 \, \text{kg} \cdot \text{m}^2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia is often referred to as the rotational equivalent of mass in linear motion. It measures how difficult it is to change the rotation of an object about a particular axis.
The moment of inertia depends on both the object's mass and its shape, as well as the axis about which it's rotating. - Formula: It's usually expressed in the form \( I = \sum m_i r_i^2 \), where \( m_i \) is the mass of each particle and \( r_i \) is the distance of each particle from the axis of rotation.- Units: The standard unit for moment of inertia in the International System of Units (SI) is \( ext{kg} \, \text{m}^2 \).In practice, calculating the moment of inertia can be straightforward for simple shapes like rods or spheres. However, it can be more complex for irregular objects. In exercises like the one above, you're often given the moment of inertia and must use it to solve problems related to rotational dynamics.
Angular Velocity
Angular velocity describes how fast an object is rotating. The concept is quite similar to linear velocity, but instead of moving through space, the object is rotating around an axis.
This can be either a point inside the object or a point outside the object in some rare cases. Angular velocity is a vector quantity, meaning it has both a magnitude and a direction. - Formula: If \( \theta \) is the angular displacement and \( t \) is the time taken, then the angular velocity \( \omega \) is \( \omega = \frac{d\theta}{dt} \).- Units: It is measured in radians per second (rad/s) in the SI system.Usually, problems like the one you've encountered will give you the angular velocities before and after a certain event, allowing you to apply the conservation of momentum principles for rotational motion. It helps us determine the resulting angular velocity or other quantities like the moment of inertia.
Rotational Dynamics
Rotational dynamics covers the forces and torques and their effects on rotation. Just as forces cause changes in linear motion, torques produce changes in rotational motion. Understanding rotational dynamics requires grasping how torques interact with objects' moments of inertia.
- Formula: The core equation linking these concepts is Newton's second law for rotation, \( \tau = I \alpha \), where \( \tau \) is torque, \( I \) is the moment of inertia, and \( \alpha \) is the angular acceleration.- Conservation: A critical concept in rotational dynamics is the conservation of angular momentum, which states that if no external torques act on a system, its angular momentum remains constant. This principle is perfectly demonstrated in your exercise, where the total angular momentum before and after the disks are linked remains the same.Rotational dynamics allow us to predict how rotating bodies will behave under various conditions, which is essential for understanding both theoretical physics and practical engineering problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A particle is located at each corner of an imaginary cube. Each edge of the cube is \(0.25 \mathrm{m}\) long. and each particle has a mass of \(0.12 \mathrm{kg}\) What is the moment of inertia of these particles with respect to an axis that lies along one edge of the cube?

A solid cylindrical disk has a radius of 0.15 \(\mathrm{m}\). It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a \(45-N\) force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of \(120 \mathrm{rad} / \mathrm{s}^{2}\) What is the mass of the disk?

A 15.0-m length of hose is wound around a reel, which is initially at rest. The moment of inertia of the reel is \(0.44 \mathrm{kg} \cdot \mathrm{m}^{2}\), and its radius is \(0.160 \mathrm{m} .\) When the reel is turning. friction at the axle exerts a torque of magnitude \(3.40 \mathrm{N} \cdot \mathrm{m}\) on the reel. If the hose is pulled so that the tension in it remains a constant \(25.0 \mathrm{N}\), how long does it take to completely unwind the hose from the reel? Neglect the mass and thickness of the hose on the reel, and assume that the hose unwinds without slipping.

A 9.75-m ladder with a mass of 23.2 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of \(245 \mathrm{N}\). At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of \(1.80 \mathrm{rad} / \mathrm{s}^{2}\) about an axis passing through the bottom end of the ladder. The ladder's center of gravity lics halfway between the top and bottom ends. (a) What is the net torque acting on the ladder? (b) What is the ladder's moment of inertia?

A helicopter has two blades (see Figure 8.11 ); each blade has a mass of \(240 \mathrm{kg}\) and can be approximated as a thin rod of length \(6.7 \mathrm{m} .\) The blades are rotating at an angular speed of \(44 \mathrm{rad} / \mathrm{s}\). (a) What is the total moment of inertia of the two blades about the axis of rotation? (b) Determine the rotational kinetic energy of the spinning blades.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.