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A projectile (mass \(=0.20 \mathrm{kg}\) ) is fired at and embeds itself in a stationary target (mass \(=2.50 \mathrm{kg}\) ). With what percentage of the projectile's incident kinetic energy does the target (with the projectile in it) fly off after being struck?

Short Answer

Expert verified
The target flies off with approximately 7.41% of the projectile's initial kinetic energy.

Step by step solution

01

Calculate Initial Kinetic Energy of the Projectile

The initial kinetic energy of the projectile, before it hits the target, is given by the equation \[ KE_{i} = \frac{1}{2} m_1 v_1^2 \]where \( m_1 = 0.20 \, \text{kg} \) is the mass of the projectile and \( v_1 \) is its velocity. Since we do not have \( v_1 \), we will compute everything relative to \( v_1 \) for now.
02

Apply Conservation of Momentum

The law of conservation of momentum states that the momentum before collision equals the momentum after collision. Before collision, the total momentum is \[ p_{i} = m_1 v_1 \]After collision, the system of the projectile and target moves together, with a combined mass \( m_1 + m_2 \), where \( m_2 = 2.50 \, \text{kg} \). Let the final velocity be \( v_f \). Therefore, \[ p_{f} = (m_1 + m_2) v_f \]Equating initial and final momentum gives \[ m_1 v_1 = (m_1 + m_2) v_f \]Solving for \( v_f \), \[ v_f = \frac{m_1}{m_1 + m_2} v_1 \].
03

Calculate Final Kinetic Energy of the System

The final kinetic energy of the system (projectile + target) after the collision is:\[ KE_{f} = \frac{1}{2} (m_1 + m_2) v_f^2 \]Using the expression for \( v_f \) from Step 2, substitute to find:\[ KE_{f} = \frac{1}{2} (m_1 + m_2) \left( \frac{m_1}{m_1 + m_2} v_1 \right)^2 \]\[ KE_{f} = \frac{1}{2} \cdot (m_1 + m_2) \cdot \frac{m_1^2}{(m_1 + m_2)^2} v_1^2 \]\[ KE_{f} = \frac{1}{2} \cdot \frac{m_1^2}{m_1 + m_2} v_1^2 \].
04

Calculate Percentage of Initial Kinetic Energy Carried by the System

The percentage of the initial kinetic energy carried by the system after the collision can be found using the formula:\[ \text{Percentage} = \left( \frac{KE_{f}}{KE_{i}} \right) \times 100 \]\[ \text{Percentage} = \left( \frac{\frac{1}{2} \cdot \frac{m_1^2}{m_1 + m_2} v_1^2}{\frac{1}{2} m_1 v_1^2} \right) \times 100 \]\[ \text{Percentage} = \left( \frac{m_1}{m_1 + m_2} \right) \times 100 \]Substitute \( m_1 = 0.20 \, \text{kg} \) and \( m_2 = 2.50 \, \text{kg} \):\[ \text{Percentage} = \left( \frac{0.20}{0.20 + 2.50} \right) \times 100 \approx 7.41\% \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In the context of collision physics, the conservation of momentum is a fundamental principle. It states that the total momentum of a system remains constant if no external forces act upon it. This is crucial in projectile motion where objects collide.
When the projectile strikes the target, initially at rest, the momentum of the system must be conserved. Prior to impact, only the projectile has momentum, given by the formula \[ p_i = m_1 v_1 \] where \( m_1 \) is the mass of the projectile and \( v_1 \) its velocity.
After impact, the projectile and target move together as a single object. The combined mass now is \( m_1 + m_2 \) and their shared velocity is \( v_f \). Thus, the momentum of the system is \[ p_f = (m_1 + m_2) v_f \].
By setting the initial and final momenta equal, \( m_1 v_1 = (m_1 + m_2) v_f \), we can solve for the final velocity. This equation exemplifies that even after the collision, the motion of the system, dictated by velocity, shifts to maintain momentum balance.
Kinetic Energy
Kinetic energy refers to the energy an object possesses due to its motion. For a projectile and target, kinetic energy changes importantly because it provides insights into how energy distributes post-collision.
The initial kinetic energy \( KE_i \) of a moving projectile is \[ KE_i = \frac{1}{2} m_1 v_1^2 \].
However, once the projectile embeds in the target, the system’s kinetic energy changes to \[ KE_f = \frac{1}{2}(m_1 + m_2) v_f^2 \]. This value decreases compared to its initial state because some energy transforms into other forms, such as heat and sound, during collision.
Calculating the percentage of original kinetic energy retained: \[ \text{Percentage} = \left( \frac{KE_f}{KE_i} \right) \times 100 \].This calculation shows what fraction of the projectile's initial energy is used to move the combined mass forward, typically representing a loss compared to the projectile's initial energy.
Collision Physics
In collision physics, it's important to understand how two bodies interact upon impact. This field examines both elastic and inelastic collisions.
In our example of a projectile embedding into a target, we see an inelastic collision, where the projectile does not bounce back but instead merges with the target, causing them to stick together.
Key characteristics of inelastic collisions include:
  • Deformation of objects involved due to forces during impact.
  • Absorption of part of kinetic energy, resulting in a reduced overall kinetic energy post-collision, exemplifying energy transformation.
  • Continued motion together after collision, described by the final velocity \( v_f \) derived from the conservation of momentum.
Inelastic collisions showcase the transition of energy and momentum, offering insights into typical projectile-target scenarios.

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