/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 The carbon monoxide molecule (CO... [FREE SOLUTION] | 91Ó°ÊÓ

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The carbon monoxide molecule (CO) consists of a carbon atom and an oxygen atom separated by a distance of \(1.13 \times 10^{-10} \mathrm{m}\). The mass \(m_{\mathrm{c}}\) of the carbon atom is 0.750 times the mass \(m_{\mathrm{o}}\) of the oxygen atom, or \(m_{\mathrm{C}}=0.750 \mathrm{m}_{\mathrm{o}}\). Determine the location of the center of mass of this molecule relative to the carbon atom.

Short Answer

Expert verified
The center of mass is located at approximately \(6.46 \times 10^{-11} \) m from the carbon atom.

Step by step solution

01

Understand the Center of Mass Formula

To determine the location of the center of mass (CM) of a system composed of two particles along a line joining them, use the formula: \[ x_{CM} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \] where \( x_{1} \) and \( x_{2} \) are the positions of the two masses \( m_1 \) and \( m_2 \). For this problem, take the position of the carbon atom, \( x_1 \), as x = 0 and the oxygen atom, \( x_2 \), at the distance of \( 1.13 \times 10^{-10} \) m.
02

Assign Variables and Convert to Relative Mass

Assign \( m_1 = m_{C} \) for the carbon atom and \( m_2 = m_{O} \) for the oxygen atom. Given that \( m_{C} = 0.750 m_{O} \), substituting in the formula we get, \( m_1 = 0.750 m_{O} \) and \( m_2 = m_{O} \).
03

Substitute and Simplify

Substitute the variables into the CM formula: \[ x_{CM} = \frac{(0.750 m_O \cdot 0) + (m_O \cdot 1.13 \times 10^{-10})}{0.750 m_O + m_O} \] This simplifies as all terms containing \( m_O \) can be cancelled out, leading to: \[ x_{CM} = \frac{1.13 \times 10^{-10}}{1.750} \].
04

Calculate the Center of Mass

Perform the calculation: \[ x_{CM} = \frac{1.13 \times 10^{-10}}{1.750} \approx 6.46 \times 10^{-11} \text{ m} \]. The center of mass is located at \( 6.46 \times 10^{-11} \) meters from the carbon atom towards the oxygen atom.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Carbon Monoxide Molecule
The carbon monoxide molecule (CO) is a simple diatomic molecule consisting of one carbon atom and one oxygen atom. These two atoms are bonded together, sharing electrons to form a stable molecule. This molecule is structured linearly, with a relatively short bond distance between the atoms of approximately \(1.13 \times 10^{-10}\) meters.
The masses of the two atoms differ significantly; specifically, the mass of the carbon atom is only 0.750 times that of the oxygen atom. This difference in mass affects the center of mass, which plays a critical role in understanding the physical characteristics and behavior of the molecule.
In the study of molecular physics, accurate calculations involving atomic positions and masses are essential for modeling and understanding interactions at the molecular scale.
Exploring Mass Ratio in Molecules
When discussing molecular physics, understanding mass ratios is fundamental. In the case of a carbon monoxide molecule, the mass ratio provides critical insight into how the individual masses affect the overall behavior of the molecule.
The exercise demonstrates a common scenario where the mass of one atom, the carbon, is expressed relative to another, the oxygen. Specifically, the mass of the carbon atom is 0.750 times the mass of the oxygen atom. This means that for every unit of mass of oxygen, the carbon atom has just 75% of that mass.
Understanding these ratios helps in predicting how the molecule will react to physical forces and determining the center of mass, a key factor in molecular movement and interaction.
  • Mass ratios can affect rotational behavior.
  • They influence vibrational frequencies in molecules.
  • Mass ratios are used in determining bond lengths and angles.
Introducing Molecular Physics
Molecular physics is a branch of physics focused on the study of molecules and the bonds between atoms that form them. It involves the exploration of molecular structure, dynamics, and interactions.
This field examines fundamental concepts, such as rotational and vibrational motions of molecules, which are determined by the mass and bond lengths within a molecule. Molecular interactions, governed by forces such as van der Waals forces and hydrogen bonds, are also key topics.
Calculations related to the center of mass are common in molecular physics. They are crucial because they help predict how a molecule will behave under various conditions.
  • Key models in molecular physics include the rigid rotor and harmonic oscillator models.
  • The study extends to spectroscopic techniques, which identify molecular properties and compositions.
  • These concepts have applications in understanding larger biological systems.
Calculation of the Center of Mass
The center of mass is a fundamental concept in physics, especially when analyzing systems of particles or multi-particle objects, like molecules.
In the carbon monoxide molecule, finding the center of mass involves using the formula: \[ x_{CM} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \] This formula calculates the weighted average position of the two atoms, accounting for their respective masses. For a carbon monoxide molecule:
  • Position \(x_1\) of the carbon atom is set at zero.
  • The oxygen atom is positioned at \(1.13 \times 10^{-10}\) meters.
  • Using given mass ratios, \(m_C = 0.750 m_O\), and substituting these into the formula, simplifies the calculation.
The resulting calculation gives a center of mass at approximately \(6.46 \times 10^{-11}\) meters from the carbon atom, positioning it closer to the heavier oxygen atom. This asymmetry is typical in diatomic molecules with unequal masses, affecting rotational dynamics and molecular interactions.

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Most popular questions from this chapter

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