/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 A Water slide is constructed so ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A Water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water \(5.00 \mathrm{m}\) from the end of the slide in a time of 0.500 s after leaving the slide. Ignoring friction and air resistance, find the height \(H\) in the drawing.

Short Answer

Expert verified
The height of the slide is approximately 1.23 meters.

Step by step solution

01

Understanding Horizontal Motion

Since the swimmer hits the water 5.00 m from the end of the slide in a time of 0.500 s, we can find the horizontal velocity \( v_x \). The horizontal motion equation is \( \text{distance} = \text{velocity} \times \text{time} \). So, \( 5.00 = v_x \times 0.500 \). Solving for \( v_x \), we get \( v_x = \frac{5.00}{0.500} = 10 \, \text{m/s} \).
02

Analyzing Vertical Motion

The swimmer falls vertically under gravity from the height \( H \) to the water in 0.500 s. Using the equation for vertical motion \( H = \frac{1}{2} g t^2 \), where \( g \approx 9.81 \, \text{m/s}^2 \) and \( t = 0.500 \, \text{s} \), we calculate the vertical distance. Substitute the given values: \( H = \frac{1}{2} \times 9.81 \times (0.500)^2 \).
03

Calculating the Height

Continue from Step 2: \( H = \frac{1}{2} \times 9.81 \times 0.25 = 1.22625 \, \text{m} \). Round this to \( H \approx 1.23 \, \text{m} \). Thus, the height from the slide to the water is approximately 1.23 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

horizontal velocity
Horizontal velocity describes how fast an object travels along the horizontal axis. In projectile motion, it's essential because it helps determine how far an object will travel horizontally before landing. Imagine someone sliding horizontally off the end of a water slide. Their initial horizontal velocity is dictated by how fast they exit the slide.

Given a person hits the water at a horizontal distance of 5.00 meters in 0.500 seconds, we can calculate their horizontal velocity using the formula:
  • \(\text{distance} = \text{velocity} \times \text{time} \)
Plugging in the numbers, we get:
  • \(5.00 = v_x \times 0.500\)
This simplifies to a horizontal velocity \(v_x\) of 10 meters per second.

Once calculated, this velocity remains constant throughout the motion if air resistance is ignored, meaning we'll use the same value to determine how far the swimmer travels horizontally until they splash into the water.
vertical motion
Vertical motion deals with the movement of an object along the vertical axis, which is influenced mainly by gravity. For a swimmer sliding off a water slide, the vertical motion refers to how the swimmer falls due to gravity after leaving the slide.

When an object is in free fall, the height of the fall can be determined using the formula for vertical motion determined by gravity:
  • \(H = \frac{1}{2} g t^2\)
The term \(g\) represents gravity (approximately \(9.81 \text{m/s}^2\) on Earth), and \(t\) is the time taken, in this case, 0.500 seconds.

Substituting the known values into the formula provides a measure of how far the swimmer drops from the slide height to the water surface. After performing the calculation, we find that the fall height or \(H\) is approximately 1.23 meters. This calculated height is the vertical distance over which the swimmer moves under the influence of gravity alone.
gravity
Gravity is an ever-present force pulling objects toward the center of the Earth. In projectile motion, like our sliding swimmer, gravity is the force responsible for their acceleration in the vertical direction.

On Earth, gravity provides a constant acceleration of \(9.81 \text{m/s}^2\), affecting all objects in free fall equally. In the case of the swimmer, once they leave the water slide and begin to descend, gravity dictates their vertical motion. Despite moving forward horizontally, the swimmer's downward motion accelerates steadily due to gravitational attraction.

This consistent force allows us to calculate different parameters of motion, including how long it will take the swimmer to reach the water and how high the end of the slide is from the water's surface. Understanding the role of gravity in vertical motion provides clarity on why certain equations, like \(H = \frac{1}{2} g t^2\), are used to predict distances in projectile motion scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 75.0-kg man is riding an escalator in a shopping mall. The escalator moves the man at a constant velocity from ground level to the floor above, a vertical height of \(4.60 \mathrm{m} .\) What is the work done on the man by (a) the gravitational force and (b) the escalator?

The cheetah is one of the fastest-accelerating animals, because it can go from rest to \(27 \mathrm{m} / \mathrm{s}\) (about \(60 \mathrm{mi} / \mathrm{h}\) ) in \(4.0 \mathrm{s}\). If its mass is \(110 \mathrm{kg}\), determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of \(4.5 \times 10^{4} \mathrm{kg},\) and the force causes its speed to change from 7100 to \(5500 \mathrm{m} / \mathrm{s}\). (a) What is the work done by the force? (b) If the asteroid slows down over a distance of \(1.8 \times 10^{6} \mathrm{m},\) determine the magnitude of the force.

A 67.0 -kg person jumps from rest off a \(3.00-\mathrm{m}\) -high tower straight down into the water. Neglect air resistance. She comes to rest \(1.10 \mathrm{m}\) under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

A gymnast is swinging on a high bar. The distance between his waist and the bar is \(1.1 \mathrm{m},\) as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.