/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A gymnast is swinging on a high ... [FREE SOLUTION] | 91Ó°ÊÓ

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A gymnast is swinging on a high bar. The distance between his waist and the bar is \(1.1 \mathrm{m},\) as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.

Short Answer

Expert verified
The gymnast's speed at the bottom is approximately 4.65 m/s.

Step by step solution

01

Understand the Concept

Begin by recognizing that the problem can be approached using the principle of conservation of energy. At the top of the swing, all the energy is in the form of gravitational potential energy, and at the bottom, it is all converted to kinetic energy since friction is ignored.
02

Write the Energy Conservation Equation

At the top of the swing, the gymnast's potential energy is maximum and kinetic energy is zero (since the speed is zero). As he swings to the bottom, the potential energy converts into kinetic energy. Using the equation:\[ mgh = \frac{1}{2}mv^2 \]where \(h\) is the height of the swing (1.1 m), \(v\) is the velocity at the bottom, and \(g\) is the acceleration due to gravity (approximately 9.81 m/s²).
03

Cancel Out Mass from the Equation

Since mass \(m\) appears on both sides of the equation, it can be cancelled out:\[ gh = \frac{1}{2}v^2 \]
04

Solve for Velocity

Rearrange the equation to solve for \(v\):\[ v^2 = 2gh \]\[ v = \sqrt{2gh} \]
05

Substitute Known Values and Calculate

Substitute \(g = 9.81 \text{ m/s}^2\) and \(h = 1.1 \text{ m}\):\[ v = \sqrt{2 \times 9.81 \times 1.1} \]\[ v = \sqrt{21.582} \]\[ v \approx 4.65 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. In simple terms, the higher an object is, the more potential energy it has. In our gymnast's case, at the top of the swing, all of his energy is potential energy because he is at the height of 1.1 meters, and his speed is zero. The formula for gravitational potential energy is given by:
  • \[ PE = mgh \]
  • Where \( m \) is mass, \( g \) is acceleration due to gravity (which is approximately 9.81 m/s² on Earth), and \( h \) is the height above the reference point.
At the top of the swing, this potential energy is at its maximum because of the height. This energy will later transform into kinetic energy as the gymnast swings down, as long as no energy is lost to friction or other external forces.
Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. If an object is moving, it is said to have kinetic energy. When our gymnast is at the bottom of the swing, his potential energy will completely convert into kinetic energy. The formula for kinetic energy is:
  • \[ KE = \frac{1}{2}mv^2 \]
  • Where \( m \) is mass and \( v \) is velocity.
The conversion between potential energy and kinetic energy is perfectly described by the principle of conservation of energy: the total energy in an isolated system remains constant. This means, as the gymnast swings down, neglecting air resistance and friction, the potential energy decreases while the kinetic energy increases. At the lowest point, all of the gymnast's energy is kinetic energy.
Acceleration due to Gravity
Acceleration due to gravity is a constant force that pulls objects toward the center of the Earth. On Earth, this acceleration is approximately 9.81 m/s². This means that for every second an object is in free fall, its velocity increases by about 9.81 m/s if air resistance is negligible. In our gymnast scenario, this constant is crucial because it affects how quickly potential energy is converted into kinetic energy as the gymnast swings downward.Understanding how acceleration due to gravity influences energy conversion helps in predicting the motion and speed of the gymnast at different points in the swing. The acceleration due to gravity not only influences the speed but also the kinetic energy of the gymnast. Hence, knowing this constant helps to precisely calculate his speed at the bottom of the swing using:
  • \[ v = \sqrt{2gh} \]
Here, by substituting with \( g = 9.81 \, \text{m/s}^2 \) and \( h = 1.1 \, \text{m} \), we find the velocity at the bottom of the swing to be approximately 4.65 m/s, showing that gravity is a key player in motion analysis.

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