/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A bowling ball (mass \(=7.2 \mat... [FREE SOLUTION] | 91Ó°ÊÓ

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A bowling ball (mass \(=7.2 \mathrm{kg}\), radius \(=0.11 \mathrm{m}\) ) and a billiard ball (mass \(=0.38 \mathrm{kg}\), radius \(=0.028 \mathrm{m}\) ) may each be treated as uniform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?

Short Answer

Expert verified
The gravitational force between the balls is approximately \(9.1 \times 10^{-9} \, \mathrm{N}\).

Step by step solution

01

Identify the relevant formula

The magnitude of the gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula is:\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where \(F\) is the gravitational force, \(G = 6.674 \times 10^{-11} \, \mathrm{N}\, \mathrm{(m/kg)^2}\) is the gravitational constant, \(m_1\) and \(m_2\) are the masses of the two objects, and \(r\) is the distance between the centers of the two objects.
02

Calculate the distance between ball centers

Since both balls are spheres, the closest distance between their centers when they touch is the sum of their radii. Therefore, the distance \( r \) is given by:\[ r = 0.11 \, \mathrm{m} + 0.028 \, \mathrm{m} = 0.138 \, \mathrm{m} \]
03

Substitute values into the formula

Using the values for \( G \), \( m_1 = 7.2 \, \mathrm{kg} \), \( m_2 = 0.38 \, \mathrm{kg} \), and \( r = 0.138 \, \mathrm{m} \), substitute these into the gravitational force equation:\[ F = \frac{(6.674 \times 10^{-11} \, \mathrm{N}(\mathrm{m/kg})^2) \cdot (7.2 \, \mathrm{kg}) \cdot (0.38 \, \mathrm{kg})}{(0.138 \, \mathrm{m})^2} \]
04

Calculate the gravitational force

Perform the calculations to find the force:\[ F = \frac{6.674 \times 10^{-11} \times 7.2 \times 0.38}{0.138^2} \approx 9.1 \times 10^{-9} \, \mathrm{N} \]The magnitude of the maximum gravitational force that the bowling ball can exert on the billiard ball is approximately \(9.1 \times 10^{-9} \, \mathrm{N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force Calculation
Gravitational force is the attractive force acting between any two masses, no matter how small. This concept was formulated by Sir Isaac Newton in his law of universal gravitation. To calculate the gravitational force between two spherical objects, we use the equation:- \( F = \frac{G \cdot m_1 \cdot m_2}{r^2} \)In this formula:- \( F \) is the gravitational force.- \( G = 6.674 \times 10^{-11} \, \text{N(m/kg)}^2 \) is the gravitational constant.- \( m_1 \) and \( m_2 \) represent the masses of the two objects.- \( r \) is the distance between the centers of the two objects.To effectively solve a gravitational problem:- Identify each object's mass.- Calculate the distance between the center points when they touch.- Substitute these values into the gravitational formula.This lets us compute the force precisely even for small objects like a bowling ball and a billiard ball.
Spherical Objects
In the realm of physics, spherical objects are often involved in calculations because they simplify the mathematical modeling of real-world problems. Objects like bowling balls and billiard balls are close enough to ideal spheres that their calculations can be simplified using simple geometry.When dealing with spherical objects, their centers provide a useful reference, as they allow us to measure the distance between objects directly. The distance between two touching spheres is simply the sum of their radii.For instance:- If a bowling ball has a radius of \( 0.11 \, \text{m} \) and a billiard ball of \( 0.028 \, \text{m} \), the distance formula becomes: - \( r = 0.11 + 0.028 = 0.138 \, \text{m} \)Understanding these principles allows us to apply consistent and predictable models when problem-solving.
Physics Problem Solving
Physics problem solving requires a systematic approach, especially when dealing with laws such as Newton's law of universal gravitation. Here's a straightforward method to tackle such problems: - **Understand the Problem:** Clearly identify what needs to be calculated, the masses involved, and the distances relevant. - **Use Formulas:** Identify which physical formulas apply and what parameters you need. - **Conduct Calculations Carefully:** Double-check each step of your arithmetic, ensuring units and values are correct. For our gravitational force problem: - We identified two spherical masses and their radii for distance calculation. - Applied Newton's gravitational formula to find the force. - Substituted and calculated carefully, step by step, to find the correct result. Such systematic methods train you to approach diverse physics problems with confidence and accuracy.

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Most popular questions from this chapter

A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne \(129-\mathrm{kg}\) laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude \(2.84 \mathrm{m} / \mathrm{s}^{2} .\) Ignoring air resistance, find the tension in the cable towing the sensor.

A skater with an initial speed of \(7.60 \mathrm{m} / \mathrm{s}\) stops propelling himself and begins to coast across the ice, eventually coming to rest. Air resistance is negligible. (a) The coefficient of kinetic friction between the ice and the skate blades is \(0.100 .\) Find the deceleration caused by kinetic friction. (b) How far will the skater travel before coming to rest?

A rocket blasts off from rest and attains a speed of \(45 \mathrm{m} / \mathrm{s}\) in \(15 \mathrm{s}\). An astronaut has a mass of 57 kg. What is the astronaut's apparent weight during takeoff?

A man seeking to set a world record wants to tow a \(109000-\mathrm{kg}\) airplane along a runway by pulling horizontally on a cable attached to the airplane. The mass of the man is \(85 \mathrm{kg},\) and the coefficient of static friction between his shoes and the runway is \(0.77 .\) What is the greatest acceleration the man can give the airplane? Assume that the airplane is on wheels that turn without any frictional resistance.

Refer to Multiple-Concept Example 10 for help in solving problems like this one. An ice skater is gliding horizontally across the ice with an initial velocity of \(+6.3 \mathrm{m} / \mathrm{s}\). The coefficient of kinetic friction between the ice and the skate blades is \(0.081,\) and air resistance is negligible. How much time elapses before her velocity is reduced to \(+2.8 \mathrm{m} / \mathrm{s} ?\)

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