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Two gratings A and B have slit separations \(d_{\lambda}\) and \(d_{\mathrm{B}},\) respectively. They are used with the same light and the same observation screen. When grating A is replaced with grating \(\mathrm{B},\) it is observed that the first-order maximum of \(A\) is exactly replaced by the second-order maximum of B. (a) Determine the ratio \(d_{\mathrm{B}} / d_{\mathrm{A}}\) of the spacings between the slits of the gratings. (b) Find the next two principal maxima of grating A and the principal maxima of B that exactly replace them when the gratings are switched. Identify these maxima by their order numbers.

Short Answer

Expert verified
The ratio is \(2/1\). A's next maxima are orders 2 and 3; B replaces them with orders 4 and 6.

Step by step solution

01

Understanding the Diffraction Grating Equation

The diffraction grating equation for maxima is given by: \[ d \sin(\theta) = m\lambda \] where \( d \) is the slit separation, \( \theta \) is the diffraction angle, \( m \) is the order of the maximum, and \( \lambda \) is the wavelength of light. In this problem, gratings A and B show maxima when switched at different orders.
02

Equating Conditions for Maxima Replacement

For grating A, the condition for the first-order maximum is \( d_A \sin(\theta) = 1\lambda \). For grating B, the second-order maximum condition is \( d_B \sin(\theta) = 2\lambda \). Setting these equal because they occur at the same position on the screen: \[ d_A = 2d_B \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slit Separation in a Diffraction Grating
In a diffraction grating, slit separation refers to the distance between adjacent slits. This is a key factor because it determines how the light diffracts and interferes. The diffraction grating causes incoming light waves to spread out and overlap. This results in interference patterns.
  • Larger slit separation means light waves have more room to spread, resulting in less diffraction.
  • Smaller slit separation causes light waves to bend more and overlap more closely.
Slit separation is represented by the symbol \(d\) in equations. Variations in \(d\) affect the angles and positions where light intensifies, creating maxima on a screen. Gratings with different slit separations can produce different numbers of principal maxima. This highlights the importance of knowing the exact slit spacing in experiments and calculations.
Order of Maximum
The 'order of maximum' in a diffraction grating refers to the sequence in which bright spots (maxima) appear on a screen. These are points where light waves constructively interfere. Each order corresponds to a different integer \(m\).
  • First-order maximum: The first bright spot away from the central maximum.
  • Second-order maximum: The second bright spot from the central maximum.
The order is crucial in determining where these bright spots will occur given a specific slit separation and wavelength. The relationship is given by the equation \(d \sin(\theta) = m\lambda\). Higher orders are usually less intense, and can overlap depending on slit separation and light wavelength. In the exercise, for example, replacing grating A's first-order maximum with grating B's second-order maximum shows a practical application of this concept.
Diffraction Angle
The diffraction angle \(\theta\) is the angle at which light waves emerging from a grating interfere constructively. It determines where the maxima appear on the observation screen. According to the diffraction grating equation, \(d \sin(\theta) = m\lambda\), \(\theta\) can change based on slit separation \(d\), wavelength \(\lambda\), and order of maximum \(m\).
  • Smaller slit separation leads to larger angles for the same order of maximum.
  • Higher order maxima occur at larger angles compared to lower orders.
Understanding the diffraction angle helps predict the positions of bright spots in an interference pattern. Manipulating this angle through experimental variables allows scientists to better focus or spread these spots as needed in research and practical applications.
Wavelength of Light in Diffraction Grating
The wavelength of light, denoted as \(\lambda\), is a measure of the distance between consecutive peaks of a light wave. In a diffraction grating setup, \(\lambda\) is fundamental in determining where light will constructively interfere to form maxima.
  • Longer wavelengths diffract more than shorter wavelengths, meaning they spread out over a wider area when they pass through slits.
  • Shorter wavelengths result in smaller diffraction angles for the same order of maximum.
The equation \(d \sin(\theta) = m\lambda\) shows how wavelength interacts with slit separation and order of maximum to produce bright spots. Practical uses of this relationship include identifying materials through their spectral lines and enhancing technologies, like lasers and fiber optics, by tailoring the light paths.

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Most popular questions from this chapter

A flat observation screen is placed at a distance of \(4.5 \mathrm{m}\) from a pair of slits. The separation on the screen between the central bright fringe and the first-order bright fringe is \(0.037 \mathrm{m} .\) The light illuminating the slits has a wavelength of \(490 \mathrm{nm} .\) Determine the slit separation.

A spotlight sends red light (wavelength \(=694.3 \mathrm{nm}\) ) to the moon. At the surface of the moon, which is \(3.77 \times 10^{\circ} \mathrm{m}\) away, the light strikes a reflector left there by astronauts. The reflected light returns to the earth, where it is detected. When it leaves the spotlight, the circular beam of light has a diameter of about \(0.20 \mathrm{m},\) and diffraction causes the beam to spread as the light travels to the moon. In effect, the first circular dark fringe in the diffraction pattern defines the size of the central bright spot on the moon. Determine the diameter (not the radius) of the central bright spot on the moon.

Light that has a wavelength of 668 nm passes through a slit \(6.73 \times 10^{-6} \mathrm{m}\) wide and falls on a screen that is \(1.85 \mathrm{m}\) away. What is the distance on the screen from the center of the central bright fringe to the third dark fringe on either side?

A large group of football fans comes to the game with colored cards that spell out the name of their team when held up simultaneously. Most of the cards are colored blue \(\left(\lambda_{\text {vacuum }}=480 \mathrm{nm}\right)\) When displayed, the average distance between neighboring cards is \(5.0 \mathrm{cm} .\) If the cards are to blur together into solid blocks of color when vicwed by a spectator at the other end of the stadium \((160 \mathrm{m}\) away), what must be the maximum diameter (in \(\mathrm{mm}\) ) of the spectator's pupils?

A film of oil lies on wet pavement. The refractive index of the oil exceeds that of the water. The film has the minimum nonzero thickness such that it appears dark due to destructive interference when viewed in red light (wavelength \(=640.0 \mathrm{nm}\) in vacuum). Assuming that the visible spectrum extends from 380 to \(750 \mathrm{nm},\) for which visible wavelength(s) in vacuum will the film appear bright due to constructive interference?

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