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Two gratings A and B have slit separations \(d_{A}\) and \(d_{\mathrm{B}},\) respectively. They are used with the same light and the same observation screen. When grating A is replaced with grating B, it is observed that the first-order maximum of \(\mathrm{A}\) is exactly replaced by the second-order maximum of B. (a) Determine the ratio \(d_{\mathrm{B}} / d_{\mathrm{A}}\) of the spacings between the slits of the gratings. (b) Find the next two principal maxima of grating A and the principal maxima of B that exactly replace them when the gratings are switched. Identify these maxima by their order numbers.

Short Answer

Expert verified
The ratio \(d_B/d_A = 2\). Maxima orders are 4 (for \(m_A=2\)) and 6 (for \(m_A=3\)) for grating B.

Step by step solution

01

Understand the Diffraction Condition

For a diffraction grating, the condition for maxima is given by the formula \(d \sin \theta = m \lambda\), where \(d\) is the slit separation, \(m\) is the order of maximum, \(\theta\) is the angle of diffraction, and \(\lambda\) is the wavelength of light. This formula will be used to determine the relationship between the slit separations of two gratings that produce maxima at the same position.
02

Find Ratio \(d_B/d_A\) for First Maximum of A and Second Maximum of B

Given that the first-order maximum of grating A coincides with the second-order maximum of grating B, apply the condition for maxima: \(d_A \sin \theta = 1\lambda\) and \(d_B \sin \theta = 2\lambda\). Since the maxima coincide, the angles \(\theta\) are the same, allowing us to equate these expressions:\[d_A = \frac{d_B}{2}\]Solving for the ratio \(\frac{d_B}{d_A}\) gives us:\[\frac{d_B}{d_A} = 2\]
03

Determine Next Two Maxima of Grating A

To find the next two principal maxima of grating A, we need to determine when its order maxima coincides with those of grating B. The next principal maxima for grating A occur at the second and third orders: \(m_A = 2, 3\).
04

Find Corresponding Maxima for Grating B

For grating B, we need to find the orders \(m_B\) such that its maxima coincides with those of 'grating A's next two maxima. Using the derived ratio \(d_B = 2d_A\), solve:- For \(m_A = 2\), \(d_A \sin \theta = 2\lambda\): - Corresponding B is \(2d_A \sin \theta = m_B \lambda\) \(\Rightarrow\) \(m_B = 4\).- For \(m_A = 3\), \(d_A \sin \theta = 3\lambda\): - Corresponding B is \(2d_A \sin \theta = m_B \lambda\) \(\Rightarrow\) \(m_B = 6\).
05

Summarize the Results

- The ratio of the slit spacings \(\frac{d_B}{d_A} = 2\).- For the second order max of A (\(m_A = 2\)), the corresponding max is the fourth order of B (\(m_B = 4\)).- For the third order max of A (\(m_A = 3\)), the corresponding max is the sixth order of B (\(m_B = 6\)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slit Separation
Slit separation refers to the distance between two consecutive slits in a diffraction grating. This spacing, commonly denoted by the symbol \(d\), plays a crucial role in determining the diffraction pattern produced by the grating. The slit separation directly affects the angles at which different orders of diffraction maxima occur. The relationship between slit separation, the angle of diffraction \(\theta\), and the order of the maximum \(m\) can be expressed using the formula:
  • \(d \sin \theta = m \lambda\)
Here, \(\lambda\) is the wavelength of the light used.

If the slit separation changes, it can lead to a shift in the angular positions of the diffraction maxima observed on a screen. In this exercise, we used the slit separations \(d_A\) and \(d_B\) of gratings A and B to find that \(d_B\) is double \(d_A\), meaning that the separation between slits in grating B is twice as large as in grating A.
Angular Diffraction
Angular diffraction is the bending of light waves as they pass through the slits of a diffraction grating. This bending creates angles \(\theta\) at which the light is diffracted. The angle is measured from the normal line (perpendicular) to the plane of the grating surface. The equation \(d \sin \theta = m \lambda\) relates the angle of diffraction to the slit separation and the wavelength of the light.

Here's what you should know about angular diffraction:
  • Smaller slit separations result in larger diffraction angles for the same order \(m\).
  • The angles at which the maxima occur increase with the order \(m\).
Understanding these angles is crucial because they determine where on a screen the brightness or peak occurs, which is referred to as a diffraction maximum.
Diffraction Maxima
Diffraction maxima are points of maximum brightness or intensity in a diffraction pattern. These occur when the path difference between light waves passing through adjacent slits leads to constructive interference. This condition is mathematically described by:
  • \(d \sin \theta = m \lambda\)
For light of a single wavelength, diffraction maxima can be observed at specific angles that satisfy this condition. Each integer \(m\) represents a different order of maximum, with \(m=1\) being the first diffraction maximum, \(m=2\) the second, and so on.

In this exercise, the condition helped us establish which orders of maxima from the different gratings coincided when one grating was replaced with another.
Order of Maximum
The order of maximum \(m\) indicates which bright band in the diffraction pattern is being referred to. Each order corresponds to the integer \(m\) within the equation \(d \sin \theta = m \lambda\).

Here's a breakdown of its role:
  • The first order maximum \(m=1\) occurs at the smallest angle where constructive interference is seen.
  • Higher-order maxima \(m=2, 3, ...\) occur at larger angles.
In this exercise, we saw that the first order maximum of grating A coincided with the second order maximum of grating B, which helped in calculating their slit spacing ratio. To match maxima between two gratings with different slit separations, knowing which orders coincide is key. This understanding allows for precise predictions about where maxima from different gratings will appear on an observation screen.

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Most popular questions from this chapter

Two diffraction gratings, A and B, are located at the same distance from the observation screens. Light with the same wavelength \(\lambda\) is used for each. The separation between adjacent principal maxima for grating A is \(2.7 \mathrm{cm},\) and for grating \(\mathrm{B}\) it is \(3.2 \mathrm{cm} .\) Grating \(\mathrm{A}\) has 2000 lines per meter. How many lines per meter does grating \(\mathrm{B}\) have? (Hint: The diffraction angles are small enough that the approximation \(\sin \theta \approx \tan \theta \operatorname{can}\) be used. \()\)

A flat observation screen is placed at a distance of \(4.5 \mathrm{m}\) from a pair of slits. The separation on the screen between the central bright fringe and the first-order bright fringe is \(0.037 \mathrm{m} .\) The light illuminating the slits has a wavelength of \(490 \mathrm{nm} .\) Determine the slit separation.

Two in-phase sources of waves are separated by a distance of \(4.00 \mathrm{m}\). These sources produce identical waves that have a wavelength of \(5.00 \mathrm{m}\). On the line between them, there are two places at which the same type of interference occurs. (a) Is it constructive or destructive interference, and (b) where are the places located?

The same diffraction grating is used with two different wave-lengths of light, \(\lambda_{A}\) and \(\lambda_{\mathrm{B}} .\) The fourth-order principal maximum of light A exactly overlaps the third-order principal maximum of light B. Find the ratio \(\lambda_{N} / \lambda_{\mathrm{B}}\)

A soap film \((n=1.33)\) is \(465 \mathrm{nm}\) thick and lies on a glass plate \((n=1.52) .\) Sunlight, whose wavelengths (in vacuum) extend from 380 to \(750 \mathrm{nm},\) travels through the air and strikes the film perpendicularly. For which wavelength(s) in this range does destructive interference cause the film to look dark in reflected light?

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