/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A flat coil of wire has an area ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A flat coil of wire has an area \(A, N\) turns, and a resistance \(R\). It is situated in a magnetic field, such that the normal to the coil is parallel to the magnetic field. The coil is then rotated through an angle of \(90^{\circ},\) so that the normal becomes perpendicular to the magnetic field. The coil has an area of \(1.5 \times 10^{-3} \mathrm{m}^{2}, 50\) turns, and a resistance of \(140 \Omega .\) During the time while it is rotating, a charge of \(8.5 \times 10^{-5} \mathrm{C}\) flows in the coil. What is the magnitude of the magnetic field?

Short Answer

Expert verified
The magnetic field magnitude is approximately 0.159 T.

Step by step solution

01

Understanding the Problem

We have a coil of wire that is initially parallel to a magnetic field and is rotated to be perpendicular to it. The coil's area, number of turns, resistance, and the charge that flows through it during this rotation are given. We need to find the magnitude of the magnetic field.
02

Recall Faraday's Law of Electromagnetic Induction

Faraday's law states that the induced electromotive force (EMF, \( \varepsilon \)) in a circuit is equal to the rate of change of magnetic flux through the circuit. Mathematically, it is \( \varepsilon = -N \frac{d\Phi}{dt} \), where \( \Phi \) is the magnetic flux.
03

Calculate Change in Magnetic Flux

The change in magnetic flux (\( \Delta \Phi \)) as the coil rotates from parallel to perpendicular is given by \( \Delta \Phi = N \Delta (B\cdot A\cdot cos(\theta)) \). Since \( \theta \) changes from \(0^{\circ}\) to \(90^{\circ}\), the cosine term changes from 1 to 0. So, \( \Delta \Phi = NBA \).
04

Relate Charge to Induced EMF

The induced charge \(Q\) is related to the EMF and resistance by \( Q = \frac{\varepsilon}{R} \). Combining this with Faraday's law, \( \varepsilon = \frac{\Delta \Phi}{t} \), we get \( Q = \frac{NBA}{R} \).
05

Solve for Magnetic Field B

Rearrange the equation \( Q = \frac{NBA}{R} \) to solve for \( B \). This gives \( B = \frac{QR}{NA} \). Plug in the known values: \( Q = 8.5 \times 10^{-5} \mathrm{C} \), \( R = 140 \Omega \), \( N = 50 \), \( A = 1.5 \times 10^{-3} \mathrm{m}^2 \). So, \( B = \frac{(8.5\times 10^{-5})(140)}{(50)(1.5 \times 10^{-3})} \).
06

Calculate the Final Result

Plug in the values to calculate \( B \):\[ B = \frac{(8.5 \times 10^{-5})(140)}{(50)(1.5 \times 10^{-3})} = \frac{(1.19 \times 10^{-2})}{(7.5 \times 10^{-2})} = 0.159 \mathrm{T} \].Thus, the magnitude of the magnetic field is approximately \( 0.159 \mathrm{T} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is an important concept in understanding how changing magnetic fields can induce electric currents. Think of magnetic flux as the total magnetic field passing through a specific area. When you have a coil of wire and a magnetic field, the flux is a measure of how much of the field penetrates the coil.
Magnetic flux (\( \Phi \) ) is calculated using the formula \( \Phi = B \, A \, \cos(\theta) \), where \( B \) is the magnetic field strength, \( A \) is the area of the coil, and \( \theta \) is the angle between the field and the perpendicular to the coil.
  • When \( \theta = 0^{\circ} \), the magnetic field is fully aligned with the coil's normal, and the flux is maximized.
  • If \( \theta = 90^{\circ} \), the field is perpendicular to the normal, resulting in zero flux through the coil.
The change in this magnetic flux as a coil is moved or rotated is what leads to electromagnetic induction. This is a fundamental principle behind Faraday's Law.
Induced Charge
Induced charge is the electric charge that flows in response to a change in the magnetic environment surrounding a coil. When a coil experiences a change in magnetic flux, it may produce an electromotive force (EMF), causing charges to move through the circuit.
This flow of charge can be calculated using the relationship \( Q = \frac{\varepsilon}{R} \), where \( Q \) is the total charge, \( \varepsilon \) is the induced EMF, and \( R \) is the resistance of the circuit.
In the context of our coil, a certain amount of charge, represented in coulombs, moves around the coil when its orientation with respect to the magnetic field changes. This movement of charge is a direct consequence of the change in magnetic flux over time. The key point here is that changes in magnetic conditions can generate electric currents and move charges, a core idea in electromechanics.
Electromotive Force (EMF)
The electromotive force (EMF) is essentially the voltage generated by changing magnetic fields. It's called "force," but it's actually an energy per charge, measured in volts. EMF is responsible for pushing electric charges around a circuit, and it's induced wherever there's a change in magnetic flux.
According to Faraday's Law, the EMF induced in a coil is given by \( \varepsilon = -N \frac{d\Phi}{dt} \), which tells us that EMF is directly proportional to the rate at which the magnetic flux changes. The negative sign is indicative of Lenz's Law, implying that the induced EMF will always work to oppose the change in flux.
In practical terms:
  • Faster changes in flux result in higher EMFs.
  • The more loops or turns (\( N \)) in the coil, the greater the induced EMF.
EMF is the key player in converting mechanical motion (like a rotating coil) to electrical energy. Understanding EMF is central to exploring concepts in generators and transformers.
Coil of Wire in a Magnetic Field
The interaction between a coil of wire and a magnetic field is a classic setup for studying electromagnetic phenomena. When a coil is placed in a magnetic field, and either the field or the coil's orientation changes, interesting things happen due to electromagnetic induction.
Here's how it works:
  • As the coil rotates, the angle between the coil and the magnetic field changes. This alters the amount of magnetic flux passing through the coil.
  • A change in magnetic flux induces an electromotive force (EMF), which can cause electric currents to flow if the circuit is closed.
  • The coil's characteristics, such as its number of turns (\( N \)), area (\( A \)), and resistance (\( R \)), influence the magnitude of the induced EMF and the resulting current.
This principle is harnessed in devices like electric generators, where mechanical energy (from rotation) is converted into electrical energy, providing power to our everyday devices. It underlies much of the technology we see in our world today.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Coil 1 is a flat circular coil that has \(N_{1}\) turns and a radius \(R_{1}\). At its center is a much smaller flat, circular coil that has \(N_{2}\) turns and radius \(R_{2}\). The planes of the coils are parallel. Assume that coil 2 is so small that the magnetic field due to coil 1 has nearly the same value at all points covered by the area of coil \(2 .\) Determine an expression for the mutual inductance between these two coils in terms of \(\mu_{0}, N_{1}, R_{1}, N_{2},\) and \(R_{2}\)

Indicate the direction of the electric field between the plates of the parallel plate capacitor shown in the drawing if the magnetic field is decreasing in time. Give your reasoning.

A magnetic field is passing through a loop of wire whose area is \(0.018 \mathrm{m}^{2} .\) The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of \(0.20 \mathrm{T} / \mathrm{s}\) (a) Determine the magnitude of the emf induced in the loop. (b) Suppose that the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in \(\mathrm{m}^{2} / \mathrm{s}\) ) should the area be changed at the instant when \(B=1.8 \mathrm{T}\) if the induced emf is to be zero? Explain whether the area is to be enlarged or shrunk.

The plane of a flat, circular loop of wire is horizontal. An external magnetic field is directed perpendicular to the plane of the loop. The magnitude of the external magnetic field is increasing with time. Because of this increasing magnetic field, an induced current is flowing clockwise in the loop, as viewed from above. What is the direction of the external magnetic field? Justify your conclusion.

Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addition, assume that your house is the only one using electric power. At a substation the primary coil of a step-down transformer (turns ratio \(=1: 29\) ) receives the voltage from the high-voltage transmission line. Because of your usage, a current of \(48 \mathrm{mA}\) exists in the primary coil of this transformer. The secondary coil is connected to the primary of another step-down transformer (turns ratio \(=1: 32\) ) somewhere near your house, perhaps up on a telephone pole. The secondary coil of this transformer delivers a \(240-\mathrm{V}\) emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.