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ssm A tiny ball (mass \(=0.012 \mathrm{kg}\) ) carries a charge of \(-18 \mu \mathrm{C}\). What electric field (magnitude and direction) is needed to cause the ball to float above the ground?

Short Answer

Expert verified
The required electric field is 6533.33 N/C downward.

Step by step solution

01

Understanding the Problem

To make the ball float, the upward electric force must equal the downward gravitational force. The electric field should have the appropriate magnitude and direction to balance the weight of the ball.
02

Calculating the Gravitational Force

The gravitational force exerted on the ball is given by the formula \( F_g = m imes g \), where \( m = 0.012 \) kg is the mass of the ball, and \( g = 9.8 \, \text{m/s}^2 \) is the acceleration due to gravity. Calculating this gives: \( F_g = 0.012 \times 9.8 = 0.1176 \, \text{N} \).
03

Using Electric Force Formula

The electric force \( F_e \) is given by the formula \( F_e = q imes E \), where \( q = -18 \, \mu C = -18 \times 10^{-6} \, C \) is the charge of the ball, and \( E \) is the magnitude of the electric field. To float, \( F_e = F_g \).
04

Solving for the Electric Field

Set \( F_e = F_g \) and solve for \( E \): \( qE = 0.1176 \). Thus, \( E = \frac{0.1176}{-18 \times 10^{-6}} = 6533.33 \, \text{N/C} \). The direction of \( E \) must be downward since the charge is negative, and the electric force should be upward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Force
Electric force is an interaction between charged particles. It is described by Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In simpler terms, charged objects push or pull each other and the strength of this force depends on how much charge they have and how far apart they are.
For this particular problem, an electric force is used to balance out the gravitational force. To calculate it, we use the formula \( F_e = q \times E \), where \( q \) is the charge and \( E \) is the electric field. Here, the charge \( q \) is \(-18\, \mu C \), which is equal to \(-18 \times 10^{-6} \) Coulombs. The necessary electric field strength can be calculated when you equate the electric force \( F_e \) to the gravitational force \( F_g \).
This balance is crucial because it keeps the ball floating, showing how electric forces can counteract the forces of gravity.
Gravitational Force
Gravitational force is what pulls objects towards each other, and on Earth, it pulls objects towards the ground. This force is described by the equation \( F_g = m \times g \), where \( m \) is the mass and \( g \) is the acceleration due to gravity. For the tiny ball in this problem, its mass is \( 0.012 \) kg.
On Earth, the acceleration due to gravity \( g \) is approximately \( 9.8 \, \text{m/s}^2 \). Thus, the gravitational force acting on the ball can be calculated as \( F_g = 0.012 \times 9.8 = 0.1176 \, \text{N} \). This force pulls the ball downward and needs to be balanced by an equal upward force for the ball to float.
The interplay between gravitational force and electric force highlights the balancing act needed to achieve floating or equilibrium conditions.
Floating Condition
To achieve the floating condition, the upward electric force must exactly balance the downward gravitational force. This means that for the ball to float, \( F_e = F_g \). Floating occurs when forces are balanced, creating a net force of zero. This can be understood by looking at equilibrium states where the sum of forces acting on an object is zero.
In practical terms, for the ball with a mass of \( 0.012 \, \text{kg} \) to float, an electric field must be applied with the right magnitude and direction. We calculated that the needed electric field is \( 6533.33 \, \text{N/C} \), directed downward because the ball's charge is negative. Charge signs are important, as they determine the direction of the electric force.
  • If the charge is positive, an electric field directed upward would be needed to counteract gravity.
  • If the charge is negative, like in this case, a downward electric field causes an upward force on the negatively charged ball.
This balancing act of forces is why the ball stays suspended or floats above the ground.

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Most popular questions from this chapter

A proton and an electron are moving due east in a constant electric field that also points due east. The electric field has a magnitude of \(8.0 \times 10^{4} \mathrm{N} / \mathrm{C} .\) Determine the magnitude of the acceleration of the proton and the electron.

Four identical metal spheres have charges of \(q_{\mathrm{A}}=-8.0 \mu \mathrm{C}\), \(q_{\mathrm{B}}=-2.0 \mu \mathrm{C}, q_{\mathrm{C}}=+5.0 \mu \mathrm{C},\) and \(q_{\mathrm{D}}=+12.0 \mu \mathrm{C}\) (a) Two of the spheres are brought together so they touch, and then they are separated. Which spheres are they, if the final charge on each one is \(+5.0 \mu \mathrm{C} ?\) (b) In a similar manner, which three spheres are brought together and then separated, if the final charge on each of the three is \(+3.0 \mu \mathrm{C} ?(\mathrm{c})\) The final charge on each of the three separated spheres in part (b) is \(+3.0 \mu \mathrm{C}\). How many electrons would have to be added to one of these spheres to make it electrically neutral?

Conceptual Example 13 deals with the hollow spherical conductor in Figure \(18.30 .\) The conductor is initially electrically neutral, and then a charge \(+q\) is placed at the center of the hollow space. Suppose the conductor initially has a net charge of \(+2 q\) instead of being neutral. What is the total charge on the interior and on the exterior surface when the \(+q\) charge is placed at the center?

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of \(+20.0 \mu \mathrm{C}\) and the instrument indicates that the electric force exerted on it is \(40.0 \mu \mathrm{N}\), due east. What are the magnitude and direction of the electric field? (b) What are the magnitude and direction of the electric field if the object has a charge of \(-10.0 \mu \mathrm{C}\) and the instrument indicates that the force is \(20.0 \mu \mathrm{N},\) due west?

ssm Two very small spheres are initially neutral and separated by a distance of \(0.50 \mathrm{m}\). Suppose that \(3.0 \times 10^{13}\) electrons are removed from one sphere and placed on the other. (a) What is the magnitude of the electrostatic force that acts on each sphere? (b) Is the force attractive or repulsive? Why?

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