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Conceptual Example 13 deals with the hollow spherical conductor in Figure \(18.30 .\) The conductor is initially electrically neutral, and then a charge \(+q\) is placed at the center of the hollow space. Suppose the conductor initially has a net charge of \(+2 q\) instead of being neutral. What is the total charge on the interior and on the exterior surface when the \(+q\) charge is placed at the center?

Short Answer

Expert verified
Inner surface: \(-q\); Outer surface: \(+3q\).

Step by step solution

01

Analyze the Charge within the Conductor

Initially, the conductor has a net charge of \(+2q\). When a charge \(+q\) is placed at the center of the hollow sphere, it induces an equal and opposite charge, \(-q\), on the inner surface of the conductor to maintain electrostatic equilibrium.
02

Determine the Charge on the Inner Surface

The charge \(+q\) placed at the center induces a \(-q\) charge on the inner surface of the conductor, resulting in the inner surface charge being \(-q\). This counteracts the electric field due to the internal charge within the conductor's hollow space.
03

Calculate the Charge on the Outer Surface

Since the conductor was initially \(+2q\) and the inner surface now has a charge of \(-q\), the remaining charge must appear on the outer surface. Thus, the charge on the outer surface of the conductor is \(+2q - (-q) = +3q\).
04

Conclusion

The total charge on the interior surface of the hollow spherical conductor is \(-q\), while the total charge on the exterior surface is \(+3q\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Hollow Spherical Conductor
A hollow spherical conductor is a fascinating object in the realm of electrostatics. Imagine a spherical shell made of conducting material with an empty space inside. It has unique properties that make it a key subject of interest. One key feature is its ability to influence electric charge distribution. When charges are placed inside, outside, or on the conducting shell, the conductor reacts to achieve a stable state. This stability is due to the highly conductive nature of the material, which allows charges to move freely, spreading out in response to any electric influence. The way charges arrange themselves on the hollow sphere will ensure minimal repulsion amongst themselves and result in a state of electrostatic equilibrium.
Exploring Electric Charge Distribution
Electric charge distribution refers to how electric charges spread across different surfaces, especially in conductive materials. In a hollow spherical conductor, this distribution is influenced by both the geometry and the presence of internal or external charges. When a charge is introduced, the free electrons in the conductor will rearrange to counteract any electric field that the charge may create.
  • The charges on a conductor will always seek to nullify any electric field within the conductor itself by rearranging amongst themselves.
  • Initially, if a conductor is neutral and a positive charge is placed inside its hollow, like in our example, an equal negative charge appears on the inner surface.
  • This negative charge exactly cancels out the internal charge's effect, maintaining no field in the hollow region.
  • In our scenario, the additional charge introduced alters the pattern, sharing the outer surface with the remaining charge to reach a new equilibrium.
The Role of Gauss's Law
Gauss's Law is a powerful tool for solving electrostatic problems. It states that the net electric flux passing through a closed surface is proportional to the enclosed electric charge. This principle can be especially insightful when analyzing a hollow spherical conductor. To apply Gauss's Law: - Consider a Gaussian surface inside the conductor and outside the charge at the center. Since the electric field inside the conductor must be zero, any charge that appears on the inner surface must exactly cancel the internal positive charge. - Similarly, if a Gaussian surface is considered outside the entire conductor, the total net charge from combined effects of enclosed charges will define the net flux. This allows calculation of effects like the charge on the outer surface, without complicated calculations.
Achieving Electrostatic Equilibrium
Electrostatic equilibrium is the state wherein the charges on a conductor cease to move, reaching stability. This is achieved when there is no electric potential difference between any two points within the conductor. Key aspects of electrostatic equilibrium include:
  • Inside the conductor: The electric field is zero because charges have moved to cancel out interior fields.
  • Surface Distribution: Charges reside entirely on the surface, arranging to minimize repulsion.
  • In our hollow spherical conductor, when a charge is placed at the center, the charges adjust themselves such that inner charges neutralize the effect of central charge, while the rest distribute over the outer surface.
This natural outcome illustrates the marvel of electrostatic interactions, effortlessly resolving complex charge distributions into stable configurations.

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Most popular questions from this chapter

A charge \(Q\) is located inside a rectangular box. The electric flux through each of the six surfaces of the box is: \(\Phi_{1}=+1500 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C},\) \(\Phi_{2}=+2200 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}, \Phi_{3}=+4600 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}, \Phi_{4}=-1800 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}\) \(\Phi_{5}=-3500 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C},\) and \(\Phi_{6}=-5400 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C} .\) What is \(Q ?\)

In a vacuum, two particles have charges of \(q_{1}\) and \(q_{2}\), where \(q_{1}=+3.5 \mu \mathrm{C}\). They are separated by a distance of \(0.26 \mathrm{m}\), and particle 1 experiences an attractive force of \(3.4 \mathrm{N}\). What is \(q_{2}\) (magnitude and \(\operatorname{sign}\) )?

An unstrained horizontal spring has a length of \(0.32 \mathrm{m}\) and a spring constant of \(220 \mathrm{N} / \mathrm{m}\). Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by \(0.020 \mathrm{m}\) relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.

Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. The magnitude of each of the charges is \(5.0 \mu \mathrm{C},\) and the lengths of the sides of the triangle are \(3.0 \mathrm{cm} .\) Calculate the magnitude of the net force that each charge experiences.

Two point charges are fixed on the \(y\) axis: a negative point charge \(q_{1}=-25 \mu \mathrm{Cat} y_{1}=+0.22 \mathrm{m}\) and a positive point charge \(q_{2}\) at \(y_{2}=+0.34 \mathrm{m}.\) A third point charge \(q=+8.4 \mu \mathrm{C}\) is fixed at the origin. The net electrostatic force exerted on the charge \(q\) by the other two charges has a magnitude of \(27 \mathrm{N}\) and points in the \(+y\) direction. Determine the magnitude of \(q_{2}.\)

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