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Two charges attract each other with a force of \(1.5 \mathrm{N}\). What will be the force if the distance between them is reduced to one-ninth of its original value?

Short Answer

Expert verified
The force will increase to 121.5 N.

Step by step solution

01

Understanding Coulomb's Law

Coulomb's law states that the force between two point charges is directly proportional to the product of the absolute magnitudes of the charges, and inversely proportional to the square of the distance between them. The formula is given by: \[ F = k \frac{q_1 q_2}{r^2} \], where \( F \) is the force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between the charges.
02

Relating Force and Distance

According to Coulomb's law, if we reduce the distance \( r \) to one-ninth of its original value, the force \( F \) will increase proportionally to the square of the change in distance, since the force is inversely proportional to the square of the distance, i.e., \[ F' = k \frac{q_1 q_2}{(\frac{1}{9}r)^2} = k \frac{q_1 q_2}{\frac{1}{81}r^2} = 81 \times k \frac{q_1 q_2}{r^2} = 81F \].
03

Calculating the New Force

Since the original force \( F \) was \( 1.5 \mathrm{N} \), when the distance is reduced to one-ninth, the new force \( F' \) is \( 81 \times 1.5 \mathrm{N} = 121.5 \mathrm{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Force
Electric force is the push or pull exerted between two charged objects. It arises from the electric charges in objects, which can either be positive or negative. The force exerted can be attractive or repulsive, depending on the type of charges interacting. Like charges repel each other, while unlike charges attract each other.
  • The strength of the electric force depends on two main factors: the amount of charge and the distance between the charges.
  • More charge generally means a stronger force. Similarly, the closer the charges, the stronger the force between them.
Coulomb's Law gives us a precise mathematical foundation to calculate this force, expressing how these factors quantitatively determine the force's magnitude.
Inverse Square Law
The inverse square law is a principle that describes how a quantity is distributed in space. For electric forces, it states that the magnitude of the force between two charges is inversely proportional to the square of the distance between them.
This means if the distance between two charges is doubled, the force is reduced to a quarter of its original value. Similarly, if the distance between the charges is halved, the force increases by four times.
  • The formula following the inverse square law is: \[ F = k \frac{q_1 q_2}{r^2} \] where \( F \) represents the force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the respective charges, and \( r \) is the distance between the charges.
  • This inverse relationship is crucial for understanding how changes in distance affect electric forces, leading to the exponential increase or decrease as distances change.
Point Charges
Point charges are an idealization where we consider charges to be concentrated at a single point in space. In reality, this is an approximation, but it's a powerful tool to simplify complex problems.
  • A point charge is thought to have no dimensions, yet it still possesses a certain magnitude of charge, either positive or negative.
  • This simplification helps in applying mathematical models like Coulomb's Law to calculate electric forces without considering the physical size of the charges.
Applications of point charges are widespread in physics, especially in electrostatics, where understanding the interaction between discrete charge quantities is necessary.
Distance and Force Relationship
The relationship between distance and force in the context of electric charges is a central aspect of Coulomb's Law. This relationship is captured by the inverse square law and highlights how sensitive electric forces are to changes in distance.
If the distance between two point charges is reduced, the electric force increases dramatically. For instance, reducing the distance to one-ninth of its original value results in the electric force increasing by a factor of 81, as demonstrated through the inverse square principle.
  • The concept is crucial for predicting how forces operate over different distances and understanding interactions at the microscopic and macroscopic scales.
  • Understanding this relationship allows us to manipulate and control electric forces in applications like medical devices, electrical engineering, and technology developments.
Such insights become particularly important in fields such as atomic physics and electrical engineering, where distance plays a pivotal role in determining the operational dynamics of systems.

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Most popular questions from this chapter

The masses of the earth and moon are \(5.98 \times 10^{24}\) and \(7.35 \times 10^{22} \mathrm{kg}\) respectively. Identical amounts of charge are placed on each body, such that the net force (gravitational plus electrical) on each is zero. What is the magnitude of the charge placed on each body?

ssm Two very small spheres are initially neutral and separated by a distance of \(0.50 \mathrm{m}\). Suppose that \(3.0 \times 10^{13}\) electrons are removed from one sphere and placed on the other. (a) What is the magnitude of the electrostatic force that acts on each sphere? (b) Is the force attractive or repulsive? Why?

Conceptual Example 13 deals with the hollow spherical conductor in Figure \(18.30 .\) The conductor is initially electrically neutral, and then a charge \(+q\) is placed at the center of the hollow space. Suppose the conductor initially has a net charge of \(+2 q\) instead of being neutral. What is the total charge on the interior and on the exterior surface when the \(+q\) charge is placed at the center?

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of \(+20.0 \mu \mathrm{C}\) and the instrument indicates that the electric force exerted on it is \(40.0 \mu \mathrm{N}\), due east. What are the magnitude and direction of the electric field? (b) What are the magnitude and direction of the electric field if the object has a charge of \(-10.0 \mu \mathrm{C}\) and the instrument indicates that the force is \(20.0 \mu \mathrm{N},\) due west?

A cube is located with one corner situated at the origin of an \(x, y,\) \(z\) coordinate system. One of the cube's faces lies in the \(x, y\) plane, another in the \(y, z\) plane, and another in the \(x, z\) plane. In other words, the cube is in the first octant of the coordinate system. The edges of the cube are \(0.20 \mathrm{m}\) long. A uniform electric field is parallel to the \(x, y\) plane and points in the direction of the \(+y\) axis. The magnitude of the field is \(1500 \mathrm{N} / \mathrm{C}\). (a) Using the outward normal for each face of the cube, find the electric flux through each of the six faces. (b) Add the six values obtained in part (a) to show that the electric flux through the cubical surface is zero, as Gauss' law predicts, since there is no net charge within the cube.

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