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What is an inelastic collision? What is a perfectly inelastic collision?

Short Answer

Expert verified
An inelastic collision is where total kinetic energy is not conserved, although momentum is. A perfectly inelastic collision is where objects stick together post-collision, leading to maximum kinetic energy loss while still conserving momentum.

Step by step solution

01

Understanding Inelastic Collisions

An inelastic collision is one in which the colliding objects do not conserve their total kinetic energy during the interaction. While momentum is conserved, some kinetic energy is transformed into other forms of energy, such as heat or sound.
02

Defining Perfectly Inelastic Collisions

A perfectly inelastic collision is a specific type of inelastic collision in which the colliding objects stick together after the collision and move as a single combined mass. This results in the maximum possible loss of kinetic energy consistent with the conservation of momentum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In the realm of physics, particularly when studying motion and collisions, the conservation of momentum is a fundamental principle that cannot be ignored. Imagine two skaters pushing off from one another on an ice rink. After they separate, the total momentum remains constant, provided no external forces act upon them.

Momentum, a vector quantity defined as the product of an object's mass and velocity (\( p = m \times v \), where m is the mass and v is the velocity), dictates that the total momentum of a closed system is conserved before and after a collision. This is true for both elastic and inelastic collisions.

In the context of an inelastic collision, even though the objects collide and energy is transformed into other forms such as heat or sound, their combined momentum just before the impact must equal their total momentum just after the impact. This concept is crucial for predicting the post-collision velocity of the objects when they move together or apart after the event.
Kinetic Energy Loss
Kinetic energy is the energy possessed by an object due to its motion. The faster it moves, the more kinetic energy it has. During an inelastic collision, some of this motion energy is converted into other energy forms, causing a net loss in the system's kinetic energy.

Let's consider a simple example: two toy cars colliding. The sound you hear and the change in shape of the cars upon impact are both manifestations of this energy transformation. The kinetic energy before the collision is greater than after, because energy has been redistributed into sound, heat, and potential energy within deformed materials.

This energy loss is a significant point of difference between inelastic and elastic collisions, where in the latter, kinetic energy is conserved. Understanding this loss is key to analyzing real-world scenarios, such as car crashes or sports collisions, from both a physical and a safety perspective.
Perfectly Inelastic Collision
Delving into perfectly inelastic collisions, this is a special case where two objects collide and then proceed together as a single object. The 'perfect' aspect of it refers to this maximum level of sticking together, and consequently, the maximum possible kinetic energy is lost during the process, albeit still respecting the conservation of momentum.

To illustrate, think of a lump of clay thrown at another stationary lump. Upon impact, they stick together, forming a single, larger lump moving at a reduced speed. This scenario exhibits a perfectly inelastic collision, clearly showing the change in motion and energy of the objects.

In real life, engineers must account for these types of collisions when designing vehicles and safety equipment—knowing how much kinetic energy can be lost helps in crafting designs that protect passengers by managing the forces during a crash. For students, grasping the concept of a perfectly inelastic collision underpins not only understanding physics problems but also appreciating the practical applications in everyday safety and technology.

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Most popular questions from this chapter

A \(0.0250\) -kg bullet is accelerated from rest to a speed of \(550 \mathrm{~m} / \mathrm{s}\) in a \(3.00-\mathrm{kg}\) rifle. The pain of the rifle's kick is much worse if you hold the gun loosely a few centimeters from your shoulder rather than holding it tightly against your shoulder. (a) Calculate the recoil velocity of the rifle if it is held loosely away from the shoulder. (b) How much kinetic energy does the rifle gain? (c) What is the recoil velocity if the rifle is held tightly against the shoulder, making the effective mass \(28.0 \mathrm{~kg}\) ? (d) How much kinetic energy is transferred to the rifle-shoulder combination? The pain is related to the amount of kinetic energy, which is significantly less in this latter situation (e) Calculate the momentum of a 110 -kg football player running at \(8.00 \mathrm{~m} / \mathrm{s}\). Compare the player's momentum with the momentum of a hardthrown \(0.410-\mathrm{kg}\) football that has a speed of \(25.0 \mathrm{~m} / \mathrm{s}\). Discuss its relationship to this problem.

Must the total energy of a system be conserved whenever its momentum is conserved? Explain why or why not.

Water from a fire hose is directed horizontally against a wall at a rate of \(50.0 \mathrm{~kg} / \mathrm{s}\) and a speed of \(42.0 \mathrm{~m} / \mathrm{s}\). Calculate the magnitude of the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero.

(a) What is the momentum of a garbage truck that is \(1.20 \times 10^{4} \mathrm{~kg}\) and is moving at \(10.0 \mathrm{~m} / \mathrm{s} ?\) (b) At what speed would an \(8.00-\mathrm{kg}\) trash can have the same momentum as the truck?

One of the waste products of a nuclear reactor is plutonium-239 \(\left({ }^{239} \mathrm{Pu}\right)\). This nucleus is radioactive and decays by splitting into a helium-4 nucleus and a uranium-235 nucleus \(\left({ }^{4} \mathrm{He}+{ }^{235} \mathrm{U}\right)\), the latter of which is also radioactive and will itself decay some time later. The energy emitted in the plutonium decay is \(8.40 \times 10^{-13} \mathrm{~J}\) and is entirely converted to kinetic energy of the helium and uranium nuclei. The mass of the helium nucleus is \(6.68 \times 10^{-27} \mathrm{~kg}\), while that of the uranium is \(3.92 \times 10^{-25} \mathrm{~kg}\) (note that the ratio of the masses is 4 to 235). (a) Calculate the velocities of the two nuclei, assuming the plutonium nucleus is originally at rest. (b) How much kinetic energy does each nucleus carry away? Note that the data given here are accurate to three digits only.

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