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(a) Calculate the momentum of a 2000-kg elephant charging a hunter at a speed of \(7.50 \mathrm{~m} / \mathrm{s}\). (b) Compare the elephant's momentum with the momentum of a \(0.0400-\mathrm{kg}\) tranquilizer dart fired at a speed of \(600 \mathrm{~m} / \mathrm{s}\). (c) What is the momentum of the \(90.0\) -kg hunter running at \(7.40 \mathrm{~m} / \mathrm{s}\) after missing the elephant?

Short Answer

Expert verified
The elephant's momentum is \(15000 \text{ kg} \cdot \text{m/s}\), the tranquilizer dart's momentum is \(24 \text{ kg} \cdot \text{m/s}\), and the hunter's momentum is \(666 \text{ kg} \cdot \text{m/s}\).

Step by step solution

01

Calculate the momentum of the elephant

Momentum is calculated as the product of mass and velocity. Use the formula \( p = m \cdot v \) where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. For the elephant with mass \(m = 2000 \text{ kg}\) and velocity \(v = 7.50 \text{ m/s}\), calculate the momentum as \( p_{elephant} = 2000 \text{ kg} \cdot 7.50 \text{ m/s}\).
02

Calculate the tranquillizer dart's momentum

Using the same formula for momentum \( p = m \cdot v \) for the tranquilizer dart with mass \(m = 0.0400 \text{ kg}\) and velocity \(v = 600 \text{ m/s}\), calculate its momentum as \( p_{dart} = 0.0400 \text{ kg} \cdot 600 \text{ m/s}\).
03

Calculate the hunter's momentum

The hunter's momentum is also found using the formula \( p = m \cdot v \). With the hunter's mass \(m = 90.0 \text{ kg}\) and velocity \(v = 7.40 \text{ m/s}\), the momentum is \( p_{hunter} = 90.0 \text{ kg} \cdot 7.40 \text{ m/s}\).
04

Performing the Calculations

Perform the calculations from the previous steps to find the momentums: \( p_{elephant} = 2000 \cdot 7.50 = 15000 \text{ kg} \cdot \text{m/s}\), \( p_{dart} = 0.0400 \cdot 600 = 24 \text{ kg} \cdot \text{m/s}\), and \( p_{hunter} = 90.0 \cdot 7.40 = 666 \text{ kg} \cdot \text{m/s}\).
05

Comparison of Momenta

Compare the calculated values of momenta for the elephant, dart, and hunter to see the differences. The values indicate the momentum of each component in the scenario.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Momentum Formula
The concept of momentum is pivotal in physics, especially when analyzing moving objects and their interactions. The momentum formula, expressed as \( p = m \cdot v \) where \( p \) represents momentum, \( m \) is mass, and \( v \) is velocity, calculates the 'quantity of motion' an object possesses. A straightforward computation for a charging elephant weighing 2000-kg at a velocity of 7.50 m/s gives us a momentum of \( p_{elephant} = 2000 \text{ kg} \cdot 7.50 \text{ m/s} = 15000 \text{ kg} \cdot \text{m/s} \).

The calculation reflects the principle that momentum is directly proportional to both the mass and velocity of an object: greater mass or higher speed results in greater momentum. In real-world scenarios, this means a massive, swiftly-charging elephant can have a devastating impact, a concept crucial for understanding collision outcomes in physics.
Conservation of Momentum
One of the fundamental laws of physics is the conservation of momentum. This principle states that the total momentum of a closed system remains constant if no external forces act upon it. It's a symphony in play during interactions like collisions or explosions. To visualize this, consider two skaters pushing off from one another; they move apart, but the sum of their momenta before and after the push remains constant.

Using our earlier example, if the elephant were to collide with another object, and assuming no external forces interfere, the combined momentum of the elephant and that object before and after the collision would be the same. This concept allows us to predict the outcome of collisions in a closed system, and it is a cornerstone for solving problems involving interactions between objects.
The Relationship Between Velocity and Mass
Digging deeper into momentum, it's critical to understand the interplay between an object's velocity and mass. Taking the tranquilizer dart with a mass of \( 0.0400 \text{ kg} \) and velocity of \( 600 \text{ m/s} \) as an example, despite its meager mass, the dart attains a momentum of \( p_{dart} = 0.0400 \text{ kg} \cdot 600 \text{ m/s} = 24 \text{ kg} \cdot \text{m/s} \), through its incredibly high speed.

Conversely, a slow-moving but massive object can yield equal momentum, as seen with the swift but lighter hunter with a momentum of \( p_{hunter} = 90.0 \text{ kg} \cdot 7.40 \text{ m/s} = 666 \text{ kg} \cdot \text{m/s} \). This illustrates that momentum can be high for objects of low mass if their velocity is sufficiently high, and vice versa. The momentum formula thus elegantly binds mass and velocity, two seemingly dissimilar attributes, into a single coherent concept.

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Most popular questions from this chapter

(a) During an ice skating performance, an initially motionless \(80.0-\mathrm{kg}\) clown throws a fake barbell away. The clown's ice skates allow her to recoil frictionlessly. If the clown recoils with a velocity of \(0.500 \mathrm{~m} / \mathrm{s}\) and the barbell is thrown with a velocity of \(10.0 \mathrm{~m} / \mathrm{s}\), what is the mass of the barbell? (b) How much kinetic energy is gained by this maneuver? (c) Where does the kinetic energy come from?

Water from a fire hose is directed horizontally against a wall at a rate of \(50.0 \mathrm{~kg} / \mathrm{s}\) and a speed of \(42.0 \mathrm{~m} / \mathrm{s}\). Calculate the magnitude of the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero.

A person slaps her leg with her hand, bringing her hand to rest in \(2.50\) milliseconds from an initial speed of \(4.00 \mathrm{~m} / \mathrm{s}\). (a) What is the average force exerted on the leg, taking the effective mass of the hand and forearm to be \(1.50 \mathrm{~kg}\) ? (b) Would the force be any different if the woman clapped her hands together at the same speed and brought them to rest in the same time? Explain why or why not.

Two football players collide head-on in midair while trying to catch a thrown football. The first player is \(95.0 \mathrm{~kg}\) and has an initial velocity of \(6.00 \mathrm{~m} / \mathrm{s}\), while the second player is \(115 \mathrm{~kg}\) and has an initial velocity of \(-3.50 \mathrm{~m} / \mathrm{s}\). What is their velocity just after impact if they cling together?

(a) What is the mass of a large ship that has a momentum of \(1.60 \times 10^{9} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\), when the ship is moving at a speed of \(48.0 \mathrm{~km} / \mathrm{h}\) ? (b) Compare the ship's momentum to the momentum of a 1100-kg artillery shell fired at a speed of \(1200 \mathrm{~m} / \mathrm{s}\)

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