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Triple Choice A pitcher throws a baseball at 40 m>s (~90 mph), and the catcher stops it in her glove. Is the work done on the ball by the catcher positive, negative, or zero? Explain.

Short Answer

Expert verified
The work done on the ball by the catcher is negative.

Step by step solution

01

Understanding Work on an Object

Work done on an object is given by the formula: \[Work = Force \times Displacement \times \cos(\theta)\]where \(\theta\) is the angle between the force and the displacement vector. If the force is in the opposite direction to the displacement, \(\cos(\theta) = -1\), resulting in negative work.
02

Analyzing the Catching Process

When the pitcher throws the ball, it moves towards the catcher's glove. As the ball is caught, the glove applies a force in the opposite direction of the ball's motion to stop it. This force opposes the ball's displacement at each point until it comes to rest.
03

Calculating the Work Done

Since the force exerted by the catcher on the ball is opposite to the direction of the ball's velocity and displacement (as the ball moves towards the catcher and stops), the angle \(\theta\) between the force and the displacement is 180 degrees, leading to \(\cos(180^\circ) = -1\). Therefore, the work done on the ball is negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force
Force is fundamentally a push or pull action that acts upon an object as a result of its interaction with another object. We encounter various types of forces daily, including gravitational, frictional, and applied forces. In the scenario of catching a baseball, the glove applies an opposing force to the moving ball to bring it to a halt.
Understanding how force works in such situations is crucial. The magnitude of force affects how quickly an object can change its speed or direction.
  • The force exerted by the catcher is intentionally applied against the ball's velocity.
  • This opposing force is what stops the ball.
In classroom examples, forces are often portrayed with vectors. These vectors have both magnitude and direction, helping us visualize the interactions between forces and objects.
Mastering the vector representation is important, as it allows us to understand the resulting motion from a given set of forces acting upon an object.
Displacement
Displacement refers to the change in position of an object. It's a vector quantity, meaning it has both magnitude and direction, similar to force. In the activity of catching a baseball, we can see that displacement is vital to understanding how the ball moves from the pitcher's hand to the catcher's glove.
To analyze the catch:
  • The ball travels a certain distance in a specific direction from the pitcher's hand to the catcher.
  • We call this directed distance 'displacement'.
This characteristic of displacement, distinguishing it from mere distance, incorporates direction, setting it apart in its applications.
During the act of catching, the displacement of the ball becomes progressively zero once the ball stops moving altogether. Thus, the catcher’s glove is involved in reducing the ball's displacement by exerting a force in the opposite direction.
Negative Work
Negative work occurs when the force applied to an object is in the direction opposite to its displacement. In our baseball scenario, as the catcher exerts a force in the opposite direction to the ball's movement, this interplay results in negative work.
Let's break this down:
  • Since work done is given by the formula \[ Work = Force \times Displacement \times \cos(\theta) \] where \( \theta \) is the angle between the force and displacement vectors.
  • If this angle is 180 degrees, as in this case, then the cosine of 180 degrees equals -1.
This tells us that the work done by the catcher's force on the ball is negative because the force and displacement are in precisely opposite directions.
Negative work indicates that energy is being extracted from the moving object, effectively reducing its motion until it comes to a stop. In practical scenarios, negative work is common in stopping mechanisms found in vehicles, sports, and various engineering applications.

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Most popular questions from this chapter

Think \& Calculate A pitcher accelerates a 0.14-kg hardball from rest to \(25.5 \mathrm{~m} / \mathrm{s}\) in \(0.075 \mathrm{~s}\). (a) How much work does the pitcher do on the ball? (b) What is the pitcher's power output during the pitch? (c) Suppose the ball reaches \(25.5 \mathrm{~m} / \mathrm{s}\) in less than \(0.075 \mathrm{~s}\). Is the power produced by the pitcher in this case more than, less than, or the same as the power found in part (b)? Explain.

Think \& Calculate A \(1100-\mathrm{kg}\) car is coasting on a horizontal road with a speed of \(19 \mathrm{~m} / \mathrm{s}\). After passing over an unpaved, sandy stretch \(32 \mathrm{~m}\) long, the car's speed has decreased to \(12 \mathrm{~m} / \mathrm{s}\). (a) Was the net work done on the car positive, negative, or zero? Explain. (b) Find the magnitude of the average net force on the car in the sandy section of the road.

A block with a mass of \(3.7 \mathrm{~kg}\) slides with a speed of \(2.2 \mathrm{~m} / \mathrm{s}\) on a frictionless surface. The block runs into a stationary spring and compresses it a certain distance before coming to rest. What is the compression distance, given that the spring has a spring constant of \(3200 \mathrm{~N} / \mathrm{m}\) ?

Calculate A \(0.27-\mathrm{kg}\) volleyball has a kinetic energy of \(7.8 \mathrm{~J}\). What is the speed of the volleyball?

The Atmos Clock The Atmos clock (the so-called perpetual motion clock) gets its name from the fact that it runs off pressure variations in the atmosphere, which drive a bellows containing a mixture of gas and liquid ethyl chloride. Because the power to drive these clocks is so limited, they have to be very efficient. In fact, a single \(60.0\)-W lightbulb could power 240 million Atmos clocks simultaneously. Find the amount of energy, in joules, required to run an Atmos clock for 1 day.

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