/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 104 A block with a mass of \(3.7 \ma... [FREE SOLUTION] | 91Ó°ÊÓ

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A block with a mass of \(3.7 \mathrm{~kg}\) slides with a speed of \(2.2 \mathrm{~m} / \mathrm{s}\) on a frictionless surface. The block runs into a stationary spring and compresses it a certain distance before coming to rest. What is the compression distance, given that the spring has a spring constant of \(3200 \mathrm{~N} / \mathrm{m}\) ?

Short Answer

Expert verified
The spring compresses approximately 7.48 cm.

Step by step solution

01

Understand the Problem

We need to find the distance a spring is compressed when a block of mass \(3.7\,\mathrm{kg}\) slides into it with a velocity of \(2.2\,\mathrm{m/s}\), given that the spring constant \(k\) is \(3200\,\mathrm{N/m}\). The block comes to rest, implying that its initial kinetic energy gets converted entirely into the potential energy of the compressed spring.
02

Write the Energy Conservation Equation

The kinetic energy \( KE \) of the block when it first hits the spring is given by \( KE = \frac{1}{2} m v^2 \). The potential energy \( PE_s \) stored in the spring when it is compressed a distance \( x \) is given by \( PE_s = \frac{1}{2} k x^2 \). By energy conservation, \( KE = PE_s \).
03

Substitute Known Values into the Energy Equation

Plug in the known values: \( m = 3.7\,\mathrm{kg} \), \( v = 2.2\,\mathrm{m/s} \), and \( k = 3200\,\mathrm{N/m} \) into the equation \( \frac{1}{2} m v^2 = \frac{1}{2} k x^2 \). This becomes \( \frac{1}{2} \times 3.7 \times (2.2)^2 = \frac{1}{2} \times 3200 \times x^2 \).
04

Solve for Compression Distance \( x \)

Simplify the equation \( \frac{1}{2} \times 3.7 \times (2.2)^2 = \frac{1}{2} \times 3200 \times x^2 \). First, calculate the left side: \( \frac{1}{2} \times 3.7 \times 4.84 = 8.942 \). Now, divide by \( 1600 \) (\( 3200/2 \)) to solve for \( x^2 \): \( 8.942 = 1600 x^2 \). Finally, solve \( x = \sqrt{\frac{8.942}{1600}} \).
05

Calculate the Final Answer

Compute the value from the previous step. Calculate \( x = \sqrt{0.005589} \). This gives \( x \approx 0.0748 \). Therefore, the block compresses the spring approximately \( 0.0748 \) meters, which converts to 7.48 cm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy that an object possesses because of its motion. In simple terms, any object that is moving has some amount of kinetic energy. This energy depends on two main things: the mass of the object and its velocity. The formula to calculate kinetic energy is given by:
  • \( KE = \frac{1}{2} m v^2 \)
Here, \( m \) is the mass of the object, and \( v \) is its velocity. The square of the velocity makes a huge impact on the kinetic energy. For example, if you double the velocity, the kinetic energy increases by four times.

In our current exercise, a block with a mass of 3.7 kg is moving at 2.2 m/s. Therefore, the kinetic energy when it hits the spring is calculated using the above formula.

Remember, because energy is a scalar quantity, kinetic energy does not have a direction only a magnitude. In the context of this exercise, understanding kinetic energy is pivotal because it shows how energy is transformed as the block encounters the spring.
Potential Energy
Potential energy refers to the stored energy that an object has due to its position or state. Specifically, when we speak about a spring, we're interested in the potential energy stored when the spring is compressed or stretched. This is called elastic potential energy, and for a spring, it can be found using the formula:
  • \( PE_s = \frac{1}{2} k x^2 \)
Here, \( k \) is the spring constant, which measures the stiffness of the spring, and \( x \) is the displacement from its equilibrium position.

In the scenario from our exercise, the spring initially stored no energy, as it was not compressed or stretched. When the block hits the spring, it compresses it, thus storing energy in it as potential energy.

Potential energy in this spring compression situation is key because it allows us to link energy conservation concepts — the kinetic energy of the moving block is transformed into the potential energy stored in the spring.
Spring Constant
The spring constant, also known as stiffness constant, is a measure of a spring’s resistance to being compressed or stretched. The larger the spring constant, the stiffer the spring, and the more force is required to compress or stretch it by a given amount. This constant is denoted by \( k \) and is measured in newtons per meter (\( N/m \)).
  • The spring constant tells us how much force we need to apply to compress or stretch the spring by 1 meter.
In the given exercise, a spring constant of 3200 N/m indicates a very stiff spring.

It's integral to our energy conservation calculations, as a high spring constant means a significant amount of energy is stored in even a slight compression. It directly influences the potential energy in our spring as per the formula \( PE_s = \frac{1}{2} k x^2 \). Thus, understanding the value and role of the spring constant helps us predict how a spring will react under force, which is crucial for solving problems involving energy conservation in mechanical systems.

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Most popular questions from this chapter

A crow drops a \(0.11-\mathrm{kg}\) clam onto a rocky beach from a height of \(9.8 \mathrm{~m}\). What is the kinetic energy of the clam when it is \(5.0 \mathrm{~m}\) above the ground? What is its speed at that point?

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