Chapter 25: Problem 24
A light source is at a distance \(d\) from a photoelectric cell, then the number of photoelectrons emitted from the cell is \(n .\) If the distance of light source and cell is reduced to half, then the number of photoelectrons emitted will become (a) \(\frac{n}{2}\) (b) \(2 n\) (c) \(4 n\) (d) \(n\)
Short Answer
Step by step solution
Understanding the Relationship
Intensity and Distance Relationship
Calculating New Intensity
Effect on Photoelectrons Emission
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inverse Square Law
- \(I\) is the light intensity.
- \(d\) is the distance from the light source.
Light Intensity
- It is a measure of the energy that hits a surface per unit area per unit time.
- Higher light intensity means more energy is being transferred to the electrons, which can impact photoelectron emission.
Photoelectron Emission
- Higher light intensity can result in more electrons being ejected because more energy is available to overcome the work function of the material.
- The energy of emitted electrons can depend on the frequency of the incoming light rather than its intensity.
Distance and Intensity Relationship
- The intensity becomes four times greater since \(\left(\frac{d}{2}\right)\) squared is \(\frac{d^2}{4}\), leading to an increase in intensity by a factor of four.
- This boost in intensity translates to four times the number of photoelectrons being emitted, assuming the emission is purely dependent on intensity.