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A source of light is placed at a distance of \(1 \mathrm{~m}\) from a photocell and cut-off potential is found to be \(V_{o}\). If the distance is doubled, the cut-off potential will be (a) \(2 V_{o}\) (b) \(V_{o}^{\prime 2}\) (c) \(V_{0}\) (d) \(V_{o} / 4\)

Short Answer

Expert verified
The cut-off potential remains \(V_{o}\), so the answer is (c) \(V_{o}\).

Step by step solution

01

Understand the Photocell Setup

The photocell measures the photoelectric effect, where light incident on a material emits electrons. The 'cut-off potential' is the minimal potential needed to stop these electrons.
02

Relation Between Light Intensity and Cut-off Potential

The frequency of the light determines the cut-off potential. However, changing the distance of the light source affects the intensity, not the frequency. The equation for the photoelectric effect is unaffected by intensity: \( eV_{o} = hu - \phi \), where \( V_{o} \) is the cut-off potential, \( h \) is Planck's constant, \( u \) is the frequency, and \( \phi \) is the work function.
03

Effect of Distance on Light Intensity

When the distance doubles, the intensity of light reaching the photocell decreases fourfold due to the inverse square law. However, intensity does not directly influence the cut-off potential; it influences the number of emitted electrons, not their energy.
04

Draw Conclusion on Cut-off Potential

Since the cut-off potential depends solely on the frequency of the light and not its intensity, doubling the distance, which affects only intensity, will not change the cut-off potential.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cut-off Potential
In the context of the photoelectric effect, the cut-off potential is a critical concept. Imagine shining light on a material surface; this light causes the material to emit electrons. These electrons can be stopped using a certain potential, known as the cut-off potential. This is the minimum potential needed to prevent electrons from reaching the anode, effectively stopping their current flow. It is important to know that this potential depends on the frequency of the incident light, not on its intensity or strength. So even if the light is made weaker or stronger by changing the distance, the cut-off potential remains unchanged because the frequency is unaffected.
Light Intensity
Light intensity refers to the amount of light energy arriving at a surface per unit area per unit time. Moving a light source closer to a surface increases this intensity, while moving it farther away decreases it. However, the critical point in the photoelectric effect is that although light intensity adjusts how many electrons are released from the material, it does not change the energy of these electrons. The number of electrons emitted, but not their speed or energy, is directly linked to the intensity of light. Thus, changes in light intensity will affect the current flowing through the photocell but not the stop potential or cut-off potential.
Inverse Square Law
The inverse square law is a principle that describes how light intensity diminishes with increasing distance from the source. Specifically, as you double the distance, the intensity decreases by a factor of four. This occurs because the light spreads over a larger area as it travels further away. Even with the intensity falling under this law, the crucial thing to remember is that the cut-off potential of a photocell relies on the frequency of the photons, not on how intense the light is at the point of measurement. Thus, regardless of increased distance reducing intensity, the energy needed to stop the electrons (cut-off potential) remains the same.
Photocell
A photocell is a device that demonstrates the photoelectric effect. When illuminated, it generates electricity by emitting electrons, which then form a current. The photocell absorbs photons from the incident light, exciting electrons and freeing them. This current can be measured, and changes in it can help in understanding various properties like light intensity and frequency. Importantly, within the photocell setup, varying the light intensity might alter the rate of electron release, but it will not affect the energy or velocity of those electrons unless there is a shift in frequency. Consequently, while intensity influences how much current is generated, it does not impact the cut-off potential.

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Most popular questions from this chapter

The energy of a photon of characteristic \(X\) -rays from a Coolidge tube comes from the (a) kinetic energy of the striking electron (b) kinetic energy of the free electron of target (c) kinetic energy of the ions of the target (d) electronic transition of the target atom

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