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In making an alloy, a substance of specific gravity \(s_{1}\) and mass \(m_{1}\) is mixed with another substance of specific gravity \(s_{2}\) and mass \(m_{2} ;\) then the specific gravity of the alloy is (a) \(\left(\frac{m_{1}+m_{2}}{s_{1}+s_{2}}\right)\) (b) \(\left(\frac{s_{1} s_{2}}{m_{1}+m_{2}}\right)\) (c) \(\left(\frac{m_{1}+m_{2}}{\frac{m_{1}}{s_{1}}+\frac{m_{2}}{s_{2}}}\right)\) (d) \(\left(\frac{\frac{m_{1}}{s_{1}}+\underline{m_{2}}}{m_{1}+m_{2}}\right)\)

Short Answer

Expert verified
(c) \(\left(\frac{m_1+m_2}{\frac{m_1}{s_1}+\frac{m_2}{s_2}}\right)\)

Step by step solution

01

Understand Specific Gravity

Specific gravity is a measure of the density of a substance compared to the density of water. If a substance has a specific gravity of 2, it is twice as dense as water.
02

Calculate Volumes

The volume of the first substance can be calculated by the formula \( V_1 = \frac{m_1}{s_1} \) and for the second substance \( V_2 = \frac{m_2}{s_2} \). This uses the relation \( \, density = \frac{mass}{volume} \, \) hence \( volume = \frac{mass}{density} \).
03

Total Mass of the Alloy

The total mass of the alloy is simply the sum of the masses of the two substances: \( m_{total} = m_1 + m_2 \).
04

Total Volume of the Alloy

The total volume of the alloy is the sum of the volumes of the two substances: \( V_{total} = V_1 + V_2 = \frac{m_1}{s_1} + \frac{m_2}{s_2} \).
05

Calculate Specific Gravity of the Alloy

The specific gravity of the alloy can be found using the formula \( s = \frac{m_{total}}{V_{total}} \). Substituting the values gives \( s = \frac{m_1 + m_2}{\frac{m_1}{s_1} + \frac{m_2}{s_2}} \).
06

Identify the Correct Answer

Compare the derived formula with the given options. The formula \( \frac{m_1 + m_2}{\frac{m_1}{s_1} + \frac{m_2}{s_2}} \) matches option (c).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alloy Composition
When creating an alloy, it involves combining two or more different substances. Each substance may have its specific gravity, which tells us how dense it is compared to water. The masses and specific gravities give us insight into how these substances will interact in the alloy.

**Understanding Alloy Composition in Depth:** - **Definition of Alloy:** An alloy is a mixture of two or more metals or a metal with another element. This mixture enhances properties such as strength, durability, or resistance to corrosion.
- **Importance of Specific Gravity:** Specific gravity helps determine how dense each component is in the alloy. It is crucial to know the proportion of each component to understand the alloy’s overall characteristics.
- **Example Use in Industry:** Alloys are often used in construction, electronics, automotive, and aerospace industries for their enhanced properties. For instance, steel (an alloy of iron and carbon) is commonly used for building structures due to its strength and flexibility.
By analyzing the characteristics of components, we can predict the properties of the resulting alloy. This step in the exercise prepares students to calculate how combining different substances changes overall properties.
Density Calculations
Density calculations play a pivotal role in determining the specific characteristics of an alloy. Density is defined as mass per unit volume, often expressed in \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \].

**Steps for Density Calculations:** - **Calculate Individual Volumes:** Start by finding the volume of each component substance using the mass and specific gravity. For the first substance, the volume is \[ V_1 = \frac{m_1}{s_1} \] and for the second substance, it is \[ V_2 = \frac{m_2}{s_2} \].
- **Total Mass of the Alloy:** Sum up the masses of the individual substances. This gives \[ m_{total} = m_1 + m_2 \].
- **Total Volume of the Alloy:** Add the calculated volumes of each substance, which results in \[ V_{total} = V_1 + V_2 = \frac{m_1}{s_1} + \frac{m_2}{s_2} \]. This helps ascertain the space the alloy occupies.
Density calculations help in understanding how much space an alloy occupies and its compactness, which affects its potential uses and manipulation.
Mass and Volume Relationships
Understanding the relationship between mass and volume can greatly help when analyzing and forming an alloy. It's essential to realize how mass and volume interplay affects the overall specific gravity.

**Key Concepts of Mass and Volume Relationships:** - **Mass and Volume Definition:** Mass is the amount of matter in an object, usually measured in grams or kilograms. Volume is the space that matter occupies, typically measured in liters or cubic meters.
- **Relation to Specific Gravity:** Specific gravity is defined as the ratio of the density of the alloy to the density of water. It helps understand how much mass fits within a certain volume, impacting how an alloy behaves.
- **Formula Application:** Using the formula \[ s = \frac{m_{total}}{V_{total}} \], indicates how the overall density, and thereby the specific gravity, is influenced by the constituents' masses and volumes.
Grasping mass and volume relationships offers insights into how alloys are constructed and their final properties. This aids in predicting how the alloy will perform under various conditions.

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Most popular questions from this chapter

A tank is filled with water upto a height \(H\). Water is allowed to come out of a hole \(P\) in one of the walls at a depth \(D\) below the surface of water. Express the horizontal distance \(x\) in terms of \(H\) and \(D\) (a) \(x=\sqrt{D(H-D)}\) (b) \(x=\sqrt{\frac{D(H-D)}{2}}\) (c) \(x=2 \sqrt{D(H-D)}\) (d) \(x=4 \sqrt{D(H-D)}\)

A large tank filled with water to a height of \(h\) is said to be emptied through a small hole at the bottom. The ratio of time taken for the level of water to fall down from \(h\) to \(h / 2\) and from \(h / 2\) to zero is (a) \(\sqrt{2}\) (b) \(1 / \sqrt{2}\) (c) \(\sqrt{2}-1\) (d) \(\frac{1}{\sqrt{2}-1}\)

A U-tube containing a liquid is accelerated horizontally with a constant acceleration \(a .\) If the separation between the two vertical limbs is \(l\), then the difference in the heights of the liquid in the two arms is (a) zero (b) \(l\) (c) \(\frac{l a}{g}\) (d) \(\frac{l a}{g}\)

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A piece of wood is floating in water. When the temperature of water rises, the apparent weight of the wood will (a) increase (b) decrease (c) may increases or decrease (d) remain same

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