Chapter 10: Problem 33
A tank is filled with water upto a height \(H\). Water is allowed to come out of a hole \(P\) in one of the walls at a depth \(D\) below the surface of water. Express the horizontal distance \(x\) in terms of \(H\) and \(D\) (a) \(x=\sqrt{D(H-D)}\) (b) \(x=\sqrt{\frac{D(H-D)}{2}}\) (c) \(x=2 \sqrt{D(H-D)}\) (d) \(x=4 \sqrt{D(H-D)}\)
Short Answer
Step by step solution
- Determine the speed of water exiting the hole
- Calculate time of flight for water to hit the ground
- Express horizontal range in terms of speed and time
- Simplify the expression for horizontal range
- Compare with given options
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Key Concepts
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