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Work out the Stark effect to lowest nonvanishing order for the \(n=3\) level of the hydrogen atom. Ignoring the spin-orbit force and relativistic correction (Lamb shift), obtain not only the energy shifts to lowest nonvanishing order but also the corresponding zeroth-order eigenket.

Short Answer

Expert verified
The \( 3s \) state's energy shift is zero; the \( 3p \) state splits into sublevels due to mixing, with shifts \( \pm eEa \).

Step by step solution

01

Identify Perturbation Operator

The Stark effect for hydrogen is induced by an external electric field \( E \). The perturbation Hamiltonian is \( H' = -eEz \), where \( z \) is the position operator in the \( z \)-direction, and \( e \) is the charge of the electron.
02

Determine Zeroth-Order State

For \( n=3 \), the zeroth-order hydrogen atom wavefunctions \( |3s\rangle, |3p_m\rangle, |3d_{m'}\rangle \) are solutions to the unperturbed Hamiltonian \( H_0 = \frac{p^2}{2m} - \frac{e^2}{r} \). These states have zero energy shift under no external fields, with separate degeneracies based on their angular momentum quantum numbers.
03

First-Order Energy Shift

Using perturbation theory, the first-order energy shift \( E_n^{(1)} \) is given by \( E_n^{(1)} = \langle n' | H' | n' \rangle \). For \( l = 0 \) (\( 3s \) states), the shift is zero. For \( l = 1 \) (\( 3p \) states), there are non-zero matrix elements calculated using selection rules from spherical harmonics.
04

Selection Rules and Matrix Elements

Evaluate \( \langle 3p_m | z | 3p_m' \rangle \) using angular momentum selection rules. For real hydrogen atom wavefunctions: \( \langle 3p_0 | z | 3p_0 \rangle = \ 0 \), \( \langle 3p_{ ext{+1}} | z | 3p_{-1} \rangle = \ \text{non-zero} \) due to parity, leading to energy shifts based on field orientation.
05

Calculate Energy Shifts and Eigenkets

Through symmetry and detailed calculation, find that for these degeneracies, \( m=0 \) experiences zero shift, while \( m=\pm 1 \) states split due to mixing terms and yield energy shifts proportional to \( \pm eEa \), where \( a \) is the Bohr radius. The eigenkets are hybrid states like \( |3p_{+1}\rangle + |3p_{-1}\rangle \) due to diagonalization of the perturbation matrix.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perturbation Theory
Perturbation theory is a powerful mathematical tool used in quantum mechanics to understand small changes in systems. It helps us calculate how an external influence, like an electric field, affects a system's energy levels and states.

In the context of the Stark effect for the hydrogen atom, perturbation theory allows us to treat the effect of an external electric field as a slight deviation from the normal behavior of the electron in a hydrogen atom. The unperturbed system is well understood, and is typically represented by eigenstates of the Hamiltonian, such as the hydrogen atom without external influences.

The goal here is to find the energy shifts and state alterations (eigenkets) that occur due to this perturbation. We often use this theory to compute these effects to the first or second order, depending on how small the perturbation is compared to the original energy of the system.
Hydrogen Atom
The hydrogen atom is the simplest and one of the most studied atomic systems in quantum mechanics. It consists of one electron orbiting a single proton, which creates a simple yet insightful model for understanding quantum behavior.

The hydrogen atom's energy levels are determined by quantum numbers: the principal quantum number \( n \), the angular momentum quantum number \( l \), and the magnetic quantum number \( m \). For the Stark effect analysis, we consider these quantum numbers to derive the atomic wavefunctions. These wavefunctions are known as eigenstates or eigenkets and include notations such as \( |3s\rangle, |3p\rangle, |3d\rangle \), depending on their principal and angular momentum quantum numbers.

As the simplest atom, hydrogen allows us to apply and test concepts like the Stark effect easily. This makes it a perfect candidate for exploring perturbations such as those introduced by an external electric field.
Energy Shifts
Energy shifts refer to changes in the energy levels of a quantum system when a perturbation is introduced. In the case of the hydrogen atom under the Stark effect, these shifts are due to the applied electric field.

Using perturbation theory, energy shifts are calculated by evaluating the expectation value of the perturbation Hamiltonian \( H' \). For first-order perturbation theory, this is expressed as \( E_n^{(1)} = \langle n' | H' | n' \rangle \).

For the hydrogen atom with \( n=3 \), different states react differently to the electric field. The states with \( l=0 \), like the 3s states, do not experience energy shifts in first-order, whereas the 3p states with \( l=1 \) do shift. This is due to the non-zero matrix elements reflecting the "mixing" of 3p states, influenced by the orientation and magnitude of the electric field.
Eigenkets
Eigenkets, or simply eigenstates, describe the allowed states of a quantum system. They are solutions to the Hamiltonian operator equations and have particular energy values known as eigenvalues.

In the unperturbed hydrogen atom, the eigenkets are well-defined states, such as \( |3s\rangle \), \( |3p_m\rangle \), or \( |3d_{m'}\rangle \). Each of these is associated with unique quantum numbers (\( n \), \( l \), \( m \)) and represents a possible electron orbital.

Under the influence of an external electric field, these eigenkets can combine to form new hybridized states. This happens because the perturbation can "mix" certain states, leading to new orientations that minimize the system’s energy.

For instance, in the Stark effect scenario, the \( 3p \) states split into new eigenstates such as \( |3p_{+1}\rangle + |3p_{-1}\rangle \), which accommodate the energy shifts induced by the perturbation."}]}}} ätze to complete the explanation of eigenkets and their role in the Stark effect. Eigenkets are essential for understanding how perturbations affect quantum systems, especially in degeneracies where multiple states are at the same energy level. Here, such complexities highlight the beauty of quantum mechanics and perturbation theory, translating theoretical constructs into observable phenomena.

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Most popular questions from this chapter

This chapter derived two of the three relativistic corrections to the one- electron atom, namely \(\Delta_{K}^{(1)}\) from "relativistic kinetic energy," and \(\Delta_{L S}^{(1)}\) from the spin-orbit interaction. A third term comes from the spread of the electron wave function in the region of changing electric field. The perturbation for this "Darwin term" is $$ V_{D}=-\frac{1}{8 m^{2} c^{2}} \sum_{i=1}^{3}\left[p_{i},\left[p_{i}, e \phi(r)\right]\right] $$ where \(\phi(r)\) is the Coulomb potential. Find \(\Delta_{D}^{(1)}\) and show that $$ \Delta_{n j}^{(1)} \equiv \Delta_{K}^{(1)}+\Delta_{L S}^{(1)}+\Delta_{D}^{(1)}=\frac{m c^{2}(Z \alpha)^{4}}{2 n^{3}}\left[\frac{3}{4 n}-\frac{1}{j+1 / 2}\right] . $$ In Section \(8.4\) we will compare this expression to the result of solving the Dirac equation in the presence of the Coulomb potential.

A particle of mass \(m\) moves in a potential well \(V(x)=m \omega^{2} x^{2} / 2\). Treating relativistic effects to order \(\beta^{2}=(p / m c)^{2}\), find the ground-state energy shift.

a. Suppose the Hamiltonian of a rigid rotator in a magnetic field perpendicular to the axis is of the form (Merzbacher 1970, Problem 17-1) $$ A \mathbf{L}^{2}+B L_{z}+C L_{y} $$ if terms quadratic in the field are neglected. Assuming \(B \gg C\), use perturbation theory to lowest nonvanishing order to get approximate energy eigenvalues. b. Consider the matrix elements $$ \begin{gathered} \left\langle n^{\prime} l^{\prime} m_{l}^{\prime} m_{s}^{\prime}\left|\left(3 z^{2}-r^{2}\right)\right| n l m_{l} m_{s}\right\rangle \\ \left\langle n^{\prime} l^{\prime} m_{l}^{\prime} m_{s}^{\prime}|x y| n l m_{l} m_{s}\right\rangle \end{gathered} $$ of a one-electron (for example, alkali) atom. Write the selection rules for \(\Delta l, \Delta m_{l}\), and \(\Delta m_{s}\). Justify your answer. c. Use degenerate perturbation theory to find the first-order energy shifts \(\Delta\). For all eight states, plot \(\Delta / A\) as a function of \(B / A\). See Figure \(5.3\). Explain why the resulting spectrum looks qualitatively different for \(B / A \ll 1\) and \(B / A \gg 1\).

A simple harmonic oscillator (in one dimension) is subjected to a perturbation $$ H_{1}=b x $$ where \(b\) is a real constant. a. Calculate the energy shift of the ground state to lowest nonvanishing order. b. Solve this problem exactly and compare with your result obtained in (a).

A \(p\)-orbital electron characterized by \(|n, l=1, m=\pm 1,0\rangle\) (ignore spin) is subjected to a potential $$ V=\lambda\left(x^{2}-y^{2}\right) \quad(\lambda=\text { constant }) $$ a. Obtain the "correct" zeroth-order energy eigenstates that diagonalize the perturbation. You need not evaluate the energy shifts in detail, but show that the original threefold degeneracy is now completely removed. b. Because \(V\) is invariant under time reversal and because there is no longer any degeneracy, we expect each of the energy eigenstates obtained in (a) to go into itself (up to a phase factor or sign) under time reversal. Check this point explicitly.

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