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When a material of interest is irradiated by neutrons, radioactive atoms are produced continually and some decay according to their given half-lives. (a) If radioactive atoms are produced at a constant rate \(R\) and their decay is governed by the conventional radioactive decay law, show that the number of radioactive atoms accumulated after an irradiation time \(t\) is $$ N=\frac{R}{\lambda}\left(1-e^{-\lambda t}\right) $$ (b) What is the maximum number of radioactive atoms that can be produced?

Short Answer

Expert verified
a) The derivation leads to the given formula for the amount of produced atoms over time: \(N(t) = \frac{R}{\lambda}(1 - e^{-\lambda t})\). b) The maximum number of radioactive atoms that can be produced is \(\frac{R}{\lambda}\).

Step by step solution

01

Part A Step 1: Understand the decay model

The model for radioactive decay of a substance is based on the assumption that each atom decays independently at a rate proportional to the number present. This leads to the differential equation \(N'(t) = -\lambda N(t)\), where \(\lambda > 0\) is the decay constant and N(t) represents the number of radioactive atoms at time t.
02

Part A Step 2: Formulate the model for production and decay

In this case, atoms are being produced at a constant rate R. Therefore, the rate of change of the number of atoms N(t) is the rate of production minus the rate of decay, which gives us the differential equation \(N'(t) = R - \lambda N(t)\).
03

Part A Step 3: Solve the differential equation

We solve this linear first order differential equation by using an integrating factor. This will yield \(N(t) = \frac{R}{\lambda}(1 - e^{-\lambda t})\). That proves the equation for the number of radioactive atoms after an irradiation time \(t\).
04

Part B Step 1: Find the maximum number

The maximum number of atoms is achieved when production of atoms equals their decay, or when time tends to infinity. So we need to find the limit as t tends to infinity for \(N(t)\). By simple limit analysis, we find that the exponential term tends to 0, leaving us with \(N_{max} = \frac{R}{\lambda}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life of Radioactive Isotopes
The half-life of a radioactive isotope is the time required for half the atoms of a radioactive sample to undergo decay. It's a constant value characteristic of the isotope and an essential parameter in nuclear physics. Understanding half-life gives insight into the stability of a radioactive isotope and its potential applications.

For instance, if an isotope has a half-life of 5 years, then after 5 years, only half of the original number of atoms would remain; after another 5 years, half of the remaining atoms would decay, leaving a quarter of the original number. The half-life concept is key to solving radioactive decay problems as it relates directly to the decay constant \(\lambda\) through the formula \(\lambda = \frac{\ln(2)}{\text{half-life}}\). When dealing with neutron irradiation, an understanding of the half-life allows the prediction of how long an irradiated material will remain radioactive.
Radioactive Decay Law
The law guiding radioactive decay quantifies how radioactive isotopes degrade over time. It states that the decay rate of a radioactive substance is directly proportional to the number of radioactive atoms present at any given time.

This behavior can be mathematically expressed as \(N'(t) = -\lambda N(t)\), where \(N'(t)\) is the rate of change of the number, \(N(t)\) is the number of radioactive atoms at time \(t\), and \(\lambda\) is the decay constant unique to that isotope. From this law, we derive the exponential decay formula used to calculate the remaining number of atoms after a certain period. Additionally, the radioactive decay law is imperative in safety protocols and medical applications, where precise knowledge of isotope behavior is necessary.
Differential Equations in Physics
Differential equations are mathematical equations that relate functions to their derivatives. In physics, they are used extensively to model the behavior of systems. Particularly, first-order linear differential equations are prevalent in representing rates of change - like in the case of radioactive decay.

To solve the equation \(N'(t) = R - \lambda N(t)\) given in the exercise, one employs an integrating factor to isolate \(N(t)\) and determine the number of radioactive atoms as a function of time. This process transforms real-world phenomena into workable mathematical forms that can be analyzed and solved, shedding light on conceptual understanding or predicting future states of the system.
Neutron Irradiation
Neutron irradiation pertains to the exposure of material to a flux of neutrons, which can alter the material's structure or induce radioactivity by transmutating stable isotopes into radioactive isotopes. This process is important in nuclear reactor technology and material science.

During irradiation, neutrons can be absorbed by atomic nuclei, leading to reactions that change the isotopic composition of the material. The rate at which radioactive isotopes are produced (\(R\)) must be controlled and measured for precise adjustments in applications such as cancer treatment through radiotherapy or in the production of certain medical isotopes. The concepts learned in the exercise, such as the calculation of \(N(t)\) and maximum number, \(N_{max}\), are critical in designing and managing processes involving neutron irradiation.

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Most popular questions from this chapter

Consider a hydrogen atom with the electron in the \(2 p\) state. The magnetic field at the nucleus produced by the orbiting electron has a value of \(12.5 \mathrm{~T}\). The proton can have its magnetic moment aligned in either of two directions perpendicular to the plane of the electron's orbit. Because of the interaction of the proton's magnetic moment with the electron's magnetic field, there will be a difference in energy between the states with the two different orientations of the proton's magnetic moment. Find that energy difference in electron volts.

\(Q\) values for \(\beta\) decay. One must be careful in calculating \(O\) values for beta decay. Atomic masses cannot always be used without correction, because electron masses do not always cancel as in alpha decay. Show that the correct expressions for beta decay are electron emission \(Q=\left[M\left({Z}^{A} \mathrm{X}\right)-M(z+1 \mathrm{Y})\right] c^{2}\) positron emission \(Q=\left[M\left({Z}^{A} \mathrm{X}\right)-M\left({ }_{z-1}^{A} Y\right)-2 m_{e}\right] c^{2}\) electron capture \(Q=\left[M\left({ }_{Z}^{A} \mathrm{X}\right)-M({z}-1 \mathrm{Y})\right] c^{2}\)

Find the radii of (a) a nucleus of \({ }_{2}^{4} \mathrm{H}\) and (b) a nucleus of \({ }_{92}^{238} \mathrm{U} .\) (c) What is the ratio of these radii?

A laboratory stock solution is prepared with an initial activity due to \({ }^{24} \mathrm{Na}\) of \(2.5 \mathrm{mCi} / \mathrm{mL}\), and \(10 \mathrm{~mL}\) of the stock solution is diluted (at \(t_{0}=0\) ) to a working solution with a total volume of \(250 \mathrm{~mL}\). After \(48 \mathrm{~h}\), a \(5-\mathrm{mL}\) sample of the working solution is monitored with a counter. What is the measured activity? (Note: \(1 \mathrm{~mL}=\) 1 milliliter, and the half-life of \({ }^{24} \mathrm{Na}\) is \(15.0 \mathrm{~h}\).)

Using a reasonable scale, sketch an energy-level diagram for (a) a proton and (b) a deuteron, both in a magnetic field \(B\). (c) What are the absolute values of the changes in energy that accompany the possible transitions between the levels shown in your diagrams?

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