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To expose photographic films. photons of light dissociate silver bromide AgBrmolecules which requires an energy of 1.2eV . What limit does this impose on the wavelengths that may be recorded by photographic film?

Short Answer

Expert verified

The wavelengths that may be recorded by photographic film is1.037×10-6m

Step by step solution

01

Step 1:

In specifically, a photon's energy is equal to the radiation frequency multiplied by Planck's constant.

The energy of the photon is given by expression,

E=HFE=hcπ

Here, E is the energy of a photo, his the plank’s constant, cis the speed of light, λis the wavelength, andf is the frequency.

02

Calculate the wavelength.

Consider the given data as below.

The energy, E=1.2eV

Plank’s constant, h=6.636×10-34J⋅s

Speed of light, role="math" localid="1657556142389" c=3×108ms

To calculate the wavelength rearrange equation (1) as below.

λ=hcE

Substituting the known parameter to calculate the value of wavelength.

λ=6.636×10-34J·s×3×108m/s1.2eV1eV1.6×10-19J=1.037×10-6m

Therefore, the limit for the wavelength is respectively 1.037×10-6m

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