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If things really do have a dual wave-particle nature, then if the wave spreads, the probability of finding the particle should spread proportionally, independent of the degree of spreading, mass, speed, and even Planck鈥檚 constant. Imagine that a beam of particles of mass m and speedv, moving in the x direction, passes through a single slit of width w . Show that the angle 1at which the first diffraction minimum would be found ( n=wsinn, from physical optics) is proportional to the angle at which the particle would likely be deflected pyp , and that the proportionality factor is a pure number, independent of m, v, w and h . (Assume small angles: sintan).

Short Answer

Expert verified

It is shown that1=4蟺胃1伪胃

Step by step solution

01

The diffraction minimum:

It is known that the diffraction minimum can be obtained at1=w

02

Required Proof:

Since, 1is a very small angle, then

11

Here,1is the angle at which the first diffraction minimum is obtained. So,

1=w1=hmvw

Now, the angle at which the particle deflected is

=pyp 鈥.. (1)

Since, it is known that

ypyh2

And the momentum, p = mv

So, substitute the above value into the angle equation (1), and you have

h(2y)(mv)h2wmvh4蟺尘惫飞

Now, from the above calculations, you can say that 1=4蟺胃1伪胃and the proportionality factor is a pure number equals 4.

Hence, it is proved that 1and the proportionality factor is a pure number.

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