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Chapter 8: Q18CQ (page 338)

Question: As indicated to remove one of the helium鈥檚 electrons requires24.6eV of energy when orbiting -24.6eV? Why or why not?

Short Answer

Expert verified

Answer

No, the Energy of orbiting electron is not .-24.6 ev

Step by step solution

01

Introduction.

The energy required to remove one of the helium electrons is 24.6 ev .

When the electron is orbiting the nucleus, the interaction of each electron with the positive charge of the nucleus is partially shielded by the other electron. However, the first ionization energy is tile energy required to remove one electron, and leave the other experiencing the unshielded charge of the nucleus.

02

Conclusion.

Therefore, it should be different from the energy of each electron in orbit.

No, the Energy of orbiting electron is not -24.6eV.

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Most popular questions from this chapter

Your friends ask: 鈥淲hy is there an exclusion principle?鈥� Explain in the simplest terms.

Question: The 鈥渞adius of an atom鈥� is a debatable quantity. Why?

The hydrogen spin-orbit interaction energy given in equation (8-25) is (渭0e2/4蟺mr2r3)S. L. Using a reasonable value for in terms of a0and the relationships S=32and L=蔚(鈩�+1)h, show that this energy is proportional to a typical hydrogen atom energy by the factor伪2 . where 伪is the fine structure constant.

Summarize the connection between angular momentum quantization and the stem-Gerlach experiment.

To investigate the claim that lowerimplies lower f energy. consider a simple case: lithium. which has twon=1electrons and alonen=2valence electron.

(a)First find the approximate orbit radius, in terms ofa0. of ann=1electron orbiting three protons. (Refer to Section 7.8.)

(b) Assuming then=1electrons shield/cancel out two of the protons in lithium's nucleus, the orbit radius of ann=2electron orbiting a net charge of just+e.

(c) Argue that lithium's valence electron should certainly have lower energy in a 25 state than in a2pstale. (Refer Figure 7.15.)
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