91Ó°ÊÓ

The given atom is technetium -$98$

Mass defect = Actual mass - Theoretical mass $\frac{\text{Bindingenergy}}{\text{Nucleon}}=\frac{\text{Massdefect}931.5\text{MeV}}{\text{Totalnumberofnucleons}}$ …â¶Ä¦(1)

The mass of technetium - $98$is$98.0\text{amu}$.

Technetium - $98$ contains $43$ number of protons and $55$ number of neutrons.

Theoretical mass of technetium$−98$.

Hydrogen atom mass$=43×1.007825\text{amu}=43.336475\text{amu}$.

Neutron mass$=55×1.008665\text{amu}=55.476575\text{amu}$ .

Hence, theoretical mass of technetium$−98=(43.336475+55.476575)\text{amu}$ .

Theoretical mass$=98.81305\text{amu}$.

Substitute the values of theoretical mass and actual mass of technetium - $98$.

Mass defect.$=(98.0−98.81305)\text{amu}=−0.81305\text{amu}$

Substitute the value of mass defect in equation (1).

$\begin{array}{l}\frac{\text{Bindingenergy}}{\text{Nucleon}}=\frac{−0.81305×931.5\text{MeV}}{98}\\ \frac{\text{Bindingenergy}}{\text{Nucleon}}=−7.75716\text{MeV}/nucleon\end{array}$