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Prove that the transitional-state wave function (5.33) does not have a well-defined energy.

Short Answer

Expert verified

The obtained solution for the energy still hasa wave function, so the original wave function does not have a defined energy.

Step by step solution

01

Identification of given data 

The given data from equation 5.33 is:

  • The sum of the two different solutions is Anxe-iEn/t+Bme-iEm/t
02

Concept/Significance of wave function

A wave function is a function that plots the probability of a particle's existence in a quantum system as a function of position, momentum, duration, and/or rotation.

03

Proof of the transitional state wave function does not have defined energy 

The transitional state wave function is:

x,t=nxe-iEn/t+me-iEm/t

Apply the energy operator on the above equation.

E^x,t=ixnxe-iEn/t+me-iEm/t=inxe-iEn/tx+ime-iEm/tx=Ennxe-iEn/t+Emme-iEm/t.

The obtained solution for the energy still hasa wave function;therefore, the original wave function does not have defined energy.

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Most popular questions from this chapter

The potential energy shared by two atoms in a diatomic molecule, depicted in Figure 17, is often approximated by the fairly simple function U(x)=(ax12)-(bx6)where constants a and b depend on the atoms involved. In Section 7, it is said that near its minimum value, it can be approximated by an even simpler function鈥攊t should 鈥渓ook like鈥 a parabola. (a) In terms ofa and b, find the minimum potential energy U (x0) and the separation x0 at which it occurs. (b) The parabolic approximation UP(x)=U(xo)+12(x-xo)2has the same minimum value at x0 and the same first derivative there (i.e., 0). Its second derivative is k , the spring constant of this Hooke鈥檚 law potential energy. In terms of a and b, what is the spring constant of U (x)?

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To show that the potential energy of finite well is U=h2(n1)28mL2

There are mathematical solutions to the Schr枚dinger equation for the finite well for any energy, and in fact. They can be made smooth everywhere. Guided by A Closer Look: Solving the Finite Well. Show this as follows:

(a) Don't throw out any mathematical solutions. That is in region Il (x<0), assume that (Ce+ax+De-ax), and in region III (x>L), assume that(x)=Fe+ax+Ge-ax. Write the smoothness conditions.

(b) In Section 5.6. the smoothness conditions were combined to eliminate A,Band Gin favor of C. In the remaining equation. Ccanceled. leaving an equation involving only kand , solvable for only certain values of E. Why can't this be done here?

(c) Our solution is smooth. What is still wrong with it physically?

(d) Show that

localid="1660137122940" D=12(B-kA)andF=12e-L[(A-Bk)sin(kL)+(Ak+B)cos(kL)]

and that setting these offending coefficients to 0 reproduces quantization condition (5-22).

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