/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A uniform circular disc of radiu... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A uniform circular disc of radius \(r\) is placed on a rough horizontal surface and given a linear velocity \(v_{0}\) and angular velocity \(\omega_{0}\) as shown. The disc comes to rest after moving some distance to the right. It follows that (1) \(3 v_{b}=2 \omega_{b} r\) (2) \(2 v_{0}=\omega_{0} r\) (3) \(v_{6}=\omega_{b} r\) (4) \(2 v_{0}=3 \omega_{0} r\)

Short Answer

Expert verified
The correct condition is (3): \(v_6 = \omega_b r\).

Step by step solution

01

Understanding the Motion

When the disc is moving, it rolls on the surface. It will come to rest due to friction, which acts tangentially, providing both the deceleration of linear velocity and a change in angular velocity. During rolling, the point of contact does not slip.
02

Velocity and Angular Velocity Relationship

For rolling without slipping, the condition at any instant is given by the relation between linear velocity \(v_b\) and angular velocity \(\omega_b\) as \(v_b = \omega_b r\).
03

Initial Condition and Verification

Verify each condition given in the exercise against the rolling without slipping condition. Start with (1): \(3v_b = 2\omega_b r\). Substitute \(v_b = \omega_b r\).
04

Evaluate Condition (1)

From \(v_b = \omega_b r\), substituting gives \(3\omega_b r = 2\omega_b r\), which does not hold true unless \(\omega_b = 0\), an inconsistency since the disc is initially moving.
05

Evaluate Condition (2)

Condition (2): \(2v_0 = \omega_0 r\) implies \(v_0 = \frac{\omega_0 r}{2}\). Compare with the rolling condition \(v_0 = \omega_0 r\), leading to a contradiction, indicating this must be false.
06

Evaluate Condition (3)

Condition (3): \(v_6 = \omega_b r\). This expresses a consistent relationship where the point of contact on the surface has no relative motion between the disc and the surface, satisfying the condition for rolling.
07

Evaluate Condition (4)

Condition (4): \(2v_0 = 3\omega_0 r\). If we assume \(v_0 = \omega_0 r\), this equation is modified to \(2\omega_0 r = 3\omega_0 r\), so it requires \(\omega_0 = 0\) which contradicts the initial motion.
08

Conclusion

The only condition that consistently meets the rolling without slipping criterion is (3): \(v_6 = \omega_b r\). This matches the physical principles and constraints of motion for a rolling disc slowing to rest due to friction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Velocity
Linear velocity is a critical concept when understanding the motion of a rolling disc. It describes how fast the disc is moving along a straight line. In the context of a disc rolling without slipping, linear velocity is directly related to the speed at which the disc moves across the surface.
For a disc to roll without slipping, there is a specific relationship between its linear velocity (\(v_b\)) and its angular velocity (\(\omega_b\)). This relation can be represented by the equation:
  • \(v_b = \omega_b r\)
where \(r\) is the radius of the disc.
This equation signifies that the linear speed at which a point on the edge of the disc travels across the floor should equal the speed of the disc's rotation times its radius.
In simple terms, for rolling without slipping, the disc must move forward one circumference length for each full rotation.
Angular Velocity
Angular velocity is all about how fast an object rotates. For the uniform circular disc in question, this indicates the rate of spin around its center.
In a rolling motion without slipping, angular velocity is just as important as linear velocity. As discussed, they are interconnected by the equation \(v_b = \omega_b r\). So, when either velocity changes, the other must adjust accordingly to maintain a non-slipping condition.
Understanding angular velocity helps to comprehend motion changes due to frictional forces. As the disc slows and eventually stops, its angular velocity reduces in response to external forces acting on it. The frictional force opposes the initial motion and gradually brings the disc to rest.
Friction
Friction is an essential force in the context of rolling without slipping. It is the force that opposes the relative motion between the disc and the surface it rolls on.
In this scenario, static friction is responsible for the rolling action where there is no slipping. Static friction adjusts itself to be exactly the force required to maintain the non-slip condition, acting tangentially at the point of contact. It provides both deceleration for the linear velocity and a change in the angular velocity.
Here are key aspects of friction for rolling discs:
  • It prevents slipping and, instead, creates what's called 'rolling friction.'
  • It acts at the surface of contact, delivering necessary changes to maintain the rolling without slipping nature.
  • It eventually causes the rolling disc to come to rest.
Thus, friction simultaneously serves as the enabler for continued rolling and the mechanism for bringing the motion to a stop.
Uniform Circular Disc
The term 'uniform circular disc' refers to an object with a circular shape and uniform mass distribution. This means the mass is evenly spread out across the disc's area.
This characteristic is crucial for predicting motion dynamics, ensuring consistent rotation around the center. In physics problems, a uniform circular disc simplifies calculations since its symmetry offers predictable behavior under rotational dynamics.
When analyzing motion such as rolling without slipping, a uniform mass distribution allows for straightforward application of formulas like:
  • \(v_b = \omega_b r\), linking linear and angular motions.
The uniformity means the moment of inertia, an important factor in rotational dynamics, can easily be calculated and applied. Overall, uniform circular discs are classic examples in physics for exploring and illustrating fundamental concepts of motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A uniform box of height \(2 \mathrm{~m}\) and having a square base of side \(1 \mathrm{~m}\), weight \(150 \mathrm{~kg}\), is kept on one end on the floor of a truck. The maximum speed with which the truck can round a curve of radius \(20 \mathrm{~m}\) without causing the block to tip over is (assume that friction is sufficient so that there is no sliding). (1) \(15 \mathrm{~m} / \mathrm{s}\) (2) \(10 \mathrm{~m} / \mathrm{s}\) (3) \(8 \mathrm{~m} / \mathrm{s}\) (4) depends on the value of coefficient of friction

A horizontal turn table in the form of a disc of radius \(r\) carries a gun at \(G\) and rotates with angular velocity \(\omega_{0}\) about a vertical axis passing through the centre \(O\). The increase in angular velocity of the system if the gun fires a bullet of mass \(m\) with a tangential velocity \(v\) with respect to the gun is (moment of inertia of gun \(+\) table about \(O\) is \(I_{0}\) ) (1) \(\frac{m v r}{I_{0}+m r^{2}}\) (2) \(\frac{2 m v r}{I_{0}}\) (3) \(\frac{v}{2 r}\) (4) \(\frac{m v r}{2 I_{0}}\)

A solid homogenous sphere is moving on a rough horizontal surface, partially rolling and partially sliding. During this kind of motion of the sphere (1) Total kinetic energy is conserved (2) Angular momentum of the sphere about the point of contact is conserved (3) Only the rotational kinetic energy about the centre of mass is conserved (4) Angular momentum about the centre of mass is conserved

A disc is given an initial angular velocity \(\omega_{0}\) and placed on a rough horizontal surface as shown in figure. The quantities which will not depend on the coefficient of friction is/are (1) the time until rolling begins (2) the displacement of the disc until rolling begins (3) the velocity when rolling begins (4) the work done by the force of friction

A rolling body of mass \(m=4 \mathrm{~kg}\), radius \(R\) and radius of gyration \(k=R / \sqrt{3}\) is placed as a plank which moves with an acceleration \(a_{0}=1 \mathrm{~ms}^{-2}\). Find the frictional force acting on the body if it rolls without sliding. (in \(\mathrm{N}\) ).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.