/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 A ball falls vertically onto a f... [FREE SOLUTION] | 91Ó°ÊÓ

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A ball falls vertically onto a floor with momentum \(p\), an then bounces repeatedly. If the coefficient of restitution is \(e\) then the total momentum imparted by the ball on the floor till the ball comes to rest is (1) \(p(1+e)\) (2) \(\frac{p}{1-e}\) (3) \(p\left(1+\frac{1}{e}\right)\) (4) \(p\left(\frac{1+e}{1-e}\right)\)

Short Answer

Expert verified
The total momentum imparted is \( p\left(\frac{1+e}{1-e}\right) \) (option 4).

Step by step solution

01

Understanding Momentum Change During Collision

The momentum changes from +p to -pe when the ball hits the floor and rebounds upward because the direction of momentum is reversed and reduced by a factor of e. The change in momentum during the first collision is \[ p - (-pe) = p + pe = p(1+e) \]
02

Calculating Further Impacts

For each subsequent bounce, the momentum imparted to the floor follows a similar pattern: the second impact imparts a change in momentum \( -pe \) to \( p \, e^2 \), resulting in \( pe(1+e) \), and so forth. These can be expressed as a geometric series.
03

Sum the Series

The total momentum imparted is the sum of the series:\[ p(1+e) + pe(1+e) + pe^2(1+e) + \, ... \] which is a geometric series with first term \( p(1+e) \) and common ratio \( e \).
04

Geometric Series Sum Formula

The sum \( S \) of an infinite geometric series is given by \[ S = \frac{a}{1-r} \]where \( a \) is the first term and \( r \) is the common ratio. Here, \( a = p(1+e) \) and \( r = e \).
05

Substitute Values into the Formula

Substitute the values into the geometric series sum formula:\[ S = \frac{p(1+e)}{1-e} \].
06

Compare with Given Options

Compare the result with the options provided in the question. The answer matches option (4): \[ p\left(\frac{1+e}{1-e}\right) \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Restitution
The coefficient of restitution, often denoted by the symbol \( e \), is a measure that describes how much kinetic energy remains after two bodies collide. This value ranges from 0 to 1.
The value of \( e \) determines how elastic a collision is:
  • If \( e = 1 \), the collision is perfectly elastic, meaning no kinetic energy is lost.
  • If \( e = 0 \), the collision is perfectly inelastic, and the objects stick together, losing most of their kinetic energy.
  • Most real-world collisions fall between these two extremes, with \( 0 < e < 1 \).
The coefficient of restitution can be calculated using the velocities of the two objects before and after the collision. Specifically, it's the ratio of the relative speed after the collision to the relative speed before the collision. In formula form, for two colliding bodies, it’s expressed as:\[e = \frac{v_2 - v_1}{u_1 - u_2} \]where \( u_1 \) and \( u_2 \) are the initial velocities, and \( v_1 \) and \( v_2 \) are the final velocities.
Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called "common ratio." This series plays a crucial role in problems involving repeated actions, like bouncing balls.
Consider a geometric series:
  • First term \( a \)
  • Common ratio \( r \)
The formula for the sum \( S \) of an infinite geometric series where the absolute value of the common ratio is less than 1 is:\[S = \frac{a}{1 - r}\]This formula helps us find the total sum of an infinite series, conveniently assuming the terms get smaller and smaller. In the case of the bouncing ball, each subsequent bounce imparts less momentum to the floor, making the sum convergent.
Collision Mechanics
Collision mechanics studies the forces and movements happening during collisions. It covers different types of collisions, such as elastic and inelastic, depending on the conservation of kinetic energy.
When a ball collides with a floor and bounces, it involves:
  • Contact force exerted by the floor on the ball, causing a change in its momentum.
  • Reversal and reduction in velocity and momentum as dictated by the coefficient of restitution \( e \).
The goal is to understand how momentum is transferred between objects and how much kinetic energy is conserved or lost. This involves applying Newton's laws and principles like the conservation of momentum. In problems like bouncing balls, calculating changes in momentum at each bounce using initial and rebound velocities gives insights into the nature of the collision.
Impulse
Impulse refers to the change in momentum resulting from a force applied over a period of time. It links directly to the concepts of momentum and force.
The impulse \( J \) experienced by an object is mathematically expressed as:\[J = F \Delta t = \Delta p\]where \( F \) is the force applied, \( \Delta t \) is the time duration over which the force is applied, and \( \Delta p \) is the change in momentum.
For instance, when a ball hits a floor, the change in momentum is a result of the impulse exerted by the floor. This impulse is responsible for the ball bouncing back up. The impulse concept is critical in calculating the total change in momentum, especially in scenarios involving repeated bounces, as the impulse represents the momentum exchange during each collision with the floor.

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Most popular questions from this chapter

Two equal spheres \(B\) and \(C\), each of mass \(m\), are in contact on a smooth horizontal table. A third sphere \(A\) of same size as that of \(B\) or \(C\) but mass \(m / 2\) impinges symmetrically on them with a velocity \(u\) and is itself brought to rest. The coefficient of restitution between the two spheres \(A\) and \(B\) (or between \(A\) and \(C\) ) is (1) \(1 / 3\) (2) \(1 / 4\) (3) \(2 / 3\) (4) \(3 / 4\)

Block \(A\) moving on frictionless horizontal plane collides head-on with block \(B\) initially at rest. The collision is NOT \((0

Column I contains physical quantity/process while column contains formula/principle. Match columns I and II such that the formula/principle is correct corresponding to the quantity in column I. $$ \begin{array}{|l|l|l|} \hline {\text { Column I }} & {\text { Column II }} \\ \hline \text { i. } \quad \text { Momentum } & \text { a. } \quad m\left(v_{2}-v_{1}\right) \\ \hline \text { ii. } \text { Impulse } & \text { b. } \begin{array}{l} \text { only momentum is } \\ \text { conserved } \end{array} \\ \hline \text { iii. Elastic collision } & \text { c. } \begin{array}{l} \text { momentum and kinefie } \\ \text { energy both are conserved } \end{array} \\ \hline \text { iv. Inelastic collision } & \text { d. } m v \\ \hline \end{array} $$

A small ball thrown at an initial velocity \(u=25 \mathrm{~m} / \mathrm{s}\) directed at an angle \(\theta=37^{\circ}\) above the horizontal collides elastically with a vertical massive smooth wall moving with a uniform horizontal velocity \(u / 5\) towards the ball. After collision with the wall the ball returns to the point from where it was thrown. Determine the time \(t\) (in \(\mathrm{s}\) ) from the beginning of motion of the ball to the moment of its impact with the wall. (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

A block of mass \(m\) starts from rest and slides down a frictionless semi- circular track from a height \(h\) as shown. When it reaches the lowest point of the track, it collides with a stationary piece of putty also having mass \(m\). If the block and the putty stick together and continue to slide, the maximum height that the block-putty system could reach is (1) \(h / 4\) (2) \(h / 2\) (3) \(h\) (4) independent of \(h\)

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