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Two equal spheres \(B\) and \(C\), each of mass \(m\), are in contact on a smooth horizontal table. A third sphere \(A\) of same size as that of \(B\) or \(C\) but mass \(m / 2\) impinges symmetrically on them with a velocity \(u\) and is itself brought to rest. The coefficient of restitution between the two spheres \(A\) and \(B\) (or between \(A\) and \(C\) ) is (1) \(1 / 3\) (2) \(1 / 4\) (3) \(2 / 3\) (4) \(3 / 4\)

Short Answer

Expert verified
The correct answer is (2) \( \frac{1}{4} \).

Step by step solution

01

Understand the Problem

You have three equal spheres, B and C touching each other, and a third sphere A hits them and comes to rest symmetrically with velocity u. B and C have mass m and A has mass m/2. You need to find the coefficient of restitution between A and B (or A and C).
02

Apply Conservation of Linear Momentum

Apply the law of conservation of linear momentum in the direction of the movement. Initially, sphere A has momentum \( \frac{m}{2}u \). After collision, A comes to rest and B and C start moving. Let their velocities be \( v \). The equation is: \[ \frac{m}{2}u = 2m \cdot v \] Simplifying gives \( v = \frac{u}{4} \).
03

Apply the Definition of Coefficient of Restitution

The coefficient of restitution (e) between A and B (or A and C) is given by \( e = \frac{v_B - v_A}{u_A - u_B} \). After the collision, A's velocity \((v_A)\) is 0 and B's velocity \((v_B)\) is \( v = \frac{u}{4} \). Therefore, \[ e = \frac{\frac{u}{4} - 0}{u - 0} = \frac{1}{4}. \]
04

Select the Correct Answer

Based on the calculation of the coefficient of restitution, select (2) \( \frac{1}{4} \) from the given options.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Linear Momentum
In physics, the principle of conservation of linear momentum is fundamental to understanding how objects behave during collisions. When two or more bodies interact in an isolated system, the total momentum of the system remains constant, provided no external forces act on it. This principle can be expressed mathematically as:\[ \sum m_i \cdot v_{i, \text{initial}} = \sum m_i \cdot v_{i, \text{final}} \]For a collision involving sphere A (with mass \( \frac{m}{2} \)) and spheres B and C (each with mass \( m \)), conservation of linear momentum tells us that the initial momentum of the system, due to A's movement, is transferred to B and C after the collision. Sphere A initially has momentum \( \frac{m}{2}u \), which is evenly distributed between spheres B and C since the collision is symmetric. This calculation results in the velocity of B and C being \( \frac{u}{4} \), once A comes to a stop. Understanding this concept helps clarify the distribution of velocities post-collision and highlights the importance of momentum in physical interactions.
Collision of Spheres
Collisions occur in various forms; when spheres collide, their interaction is often analyzed by considering the energy exchange and momentum transfer. A collision of spheres, like in our scenario with spheres A, B, and C, can be analyzed by using the concepts of elasticity and momentum.
  • **Elastic Collisions**: These are characterized by the conservation of both momentum and kinetic energy.
  • **Inelastic Collisions**: Here, kinetic energy is not conserved, although momentum is.
In this exercise, the collision of the spheres is considered inelastic relative to the kinetic energy of the system. However, linear momentum is conserved throughout the process. Analyzing how sphere A impacts spheres B and C helps us determine the aftermath arrangement of velocities and measure the efficiency of energy transfer, which is crucial for calculating the coefficient of restitution.
Symmetric Impact
The concept of symmetric impact simplifies the analysis of collisions involving multiple objects. In this exercise, the phrase "impinges symmetrically" indicates that sphere A impacts spheres B and C exactly at their point of contact and equally transfers its momentum to them.
  • **Equal Force Distribution**: Because the impact is symmetric, the forces exerted by A are equally shared by B and C.
  • **Velocity Distribution**: This symmetry ensures that post-collision, B and C acquire equal velocities, simplifying calculations.
Understanding symmetric impacts is crucial for correctly applying the conservation laws. By acknowledging this symmetry, we conclude that B and C move away from the point of contact with equal speed \( \frac{u}{4} \). Symmetry in the collision significantly reduces the complexity of solving momentum and restitution problems since it allows for straightforward mathematical modeling.
Kinematics in Collisions
Kinematics deals with the motion of objects without considering the forces that cause the motion. In the context of collisions, understanding the kinematics helps us predict and analyze the trajectory and velocity of objects post-collision.Key kinematic concepts in collision scenarios include:- **Velocity Changes**: Kinematics focuses on how velocities of spheres A, B, and C change due to the collision. Sphere A comes to rest while spheres B and C move forward with new velocities.- **Coefficient of Restitution**: The mathematical expression that represents the relative velocity of separation to the relative velocity of approach between two colliding objects. In our exercise, the coefficient was derived as \( \frac{1}{4} \), indicating the degree of elasticity in the collision.Studying kinematics provides a comprehensive view of the motion characteristics, equipping us with the tools needed to fully understand and solve problems related to the movement of spheres post-collision.

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Most popular questions from this chapter

A ball collides with a fixed inclined plane of inclination \(\theta\) after falling through a distance \(h\). If it moves horizontally just after the impact, the coefficient of restitution is (1) \(\tan \theta\) (2) \(\tan ^{2} \theta\) (3) \(\cot \theta\) (4) \(\cot ^{2} \theta\)

Three balls \(A, B\) and \(C\) of masses \(2 \mathrm{~kg}, 4 \mathrm{~kg}\) and \(8 \mathrm{~kg}\), respectively, move along the same straight line and in the same direction, with velocities \(4 \mathrm{~m} / \mathrm{s}, 1 \mathrm{~m} / \mathrm{s}\) and \(3 / 4 \mathrm{~m} / \mathrm{s}\). If \(A\) collides with \(B\) and subsequently \(B\) collides with \(C\), find the velocity of ball \(A\) and ball \(B\) after collision, taking the coefficient of restitution as unity. \(\overrightarrow{\text { (1) }} \overrightarrow{\text { (B) }} \overrightarrow{\text { (C) }}\) (1) \(v_{A}=3, v_{B}=9 / 4\) (2) \(v_{A}=0, v_{B}=3\) (3) \(v_{A}=3, v_{B}=0\) (4) \(v_{A}=0, v_{B}=0\)

A ball moving vertically downward with a speed of \(10 \mathrm{~m} / \mathrm{s}\) collides with a platform. The platform moves with a velocity of \(5 \mathrm{~m} / \mathrm{s}\) in downward direction. If \(e=0.8\), find the speed (in \(\mathrm{m} / \mathrm{s}\) ) of the ball just after collision.

A steel ball of mass \(2 \mathrm{~m}\) suffers one-dimensional elastic collision with a row of three steel balls, each of mass \(m\). If mass \(2 m\) has collided with velocity \(v\) and the three balls numbered \(1,2,3\) were initially at rest, then after the collision (1) balls 1,2 and 3 would start moving to the right, each \(_{w_{2}}\) velocity \(v / 3\) (2) balls 2 and 3 would start moving to the right, each \(w_{10}\) velocity \(v / 2\) (3) balls 2 and 3 would start moving to the right, each \(w_{2}\) velocity \(v\) (4) ball 1 and ball of mass \(2 m\) would remain at rest

A body moving towards a body of finite mass at rest collides with it. It is possible that (1) both bodies come to rest (2) both bodies move after collision (3) the moving body stops and the body at rest starts moving (4) the stationary body remains stationary and the moving body rebounds

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